Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for SBI PO 2020 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
[WpProQuiz 7579]Click Here to View Quantitative Aptitude Video Solution
Simplifications/Approximations
Directions (1 – 10): What exact/approximate value should come in the place of question mark in the given questions?
1) 1/2 + 3 – 4 * 5 + [6 – 7 * 8/4]
a) -32.5
b) -41.5
c) -24.5
d) -18.5
e) -20.5
2) √728.4601* 4.99 -370 + [16.01 * √625.01]
a) 155
b) 165
c) 135
d) 115
e) 125
3) [(6*7 – 3+2 * 8) + 9/3] * 5 – 1 + 7
a) 192
b) 286
c) 196
d) 296
e) 324
4) [(9.99)2 * (√288.96)] – [14 – 6 * 7 + (√168.59) + (11.02)2]
a) 1594
b) 1624
c) 1748
d) 1194
e) 1064
5) [√{3√(7.99) + 6.96} – 3.89 * ( 6.99 + √( 225.1) * 5.96 ) + 13]
a) -226
b) -184
c) -196
d) -288
e) -372
6) 22% of 168 – 19% of 320 + 24% of 460 – 13% of 110
a) 70.25
b) 84.14
c) 72.26
d) 88.51
e) 76.25
7) 128.01x + √1681 = 11.993 + 168.99
a) 12.5
b) 14.5
c) 16.5
d) 22.5
e) 24.5
8) x3 – 149.996 * 1.5 = (5.01)2 * 8.99 + 177.2% of (9.99)3
a) 19
b) 25
c) 29
d) 31
e) 13
9) x% of 160 = √[(√675.989) + 110% of 111 + 20.9% of 99.998]
a) 4.75
b) 1.25
c) 8.125
d) 3.65
e) 6.67
10) 2x = [(32.001 * 5.052)/4.01] * [10.24 % of √2499]
a) 12
b) 10
c) 15
d) 16
e) 20
Answers:
Directions (1-10):
1) Answer: c)
= 1/2 + 3 – 4 * 5 + [6 – 7 * 2]
= 1/2 + 3 – 4 * 5 + [6 – 14]
= 1/2 + 3 – 4 * 5 – 8
= 0.5 + 3 – 4 * 5 – 8
= 0.5 + 3 – 20 – 8
= 3.5 – 20 – 8
= -24.5
2) Answer: b)
= √728.4601* 4.99 -370 + [16.01 * √625.01]
= 27 * 5 – 370 + [16 * 25]
= 27 * 5 – 370 + 400
= 135 – 370 + 400
= 535 – 370
= 165
3) Answer: d)
= [(6*7 – 3+2 * 8) + 9/3] * 5 – 1 + 7
= [(42 – 3 + 16) + 3] * 5 – 1 + 7
= [55 + 3] * 5 – 1 + 7
= 58 * 5 – 1 + 7
= 290 – 1 + 7
= 296
4) Answer: a)
= [(9.99)2 * (√288.96)] – [14 – 6 * 7 + (√168.59) + (11.02)2]
= [100 * 17] – [14 – 42 + (13 + 121)]
= 1700 – [14 – 42 + 134]
= 1700 – 106
= 1594
5) Answer: e)
= [√{3√(7.99) + 6.96} – 3.89 * (6.99 + √(225.1) * 5.96) + 13]
= [√8.96 – 3.89 * (7 + 15 * 6) + 13]
= [3 – 4 * 97 + 13]
= [3 – 388 + 13]
= -372
6) Answer: c)
= [20%+2%] of 168 – [ 20%-1%] of 320+ [ 20% + 2% + 2%] of 460 – [ 11% + 1% +1%] of 110
= [33.6 + 3.36] – [64 – 3.2] + [92 + 9.2 + 9.2] – [12.1 + 1.1 + 1.1]
= 36.96 – 60.8 + 110.4 – 14.30
= 147.36 – 75.1
= 72.26
7) Answer: b)
128.01x + √1681 = 11.993 + 168.99
128x + 41 = 123 + 169
128x = 1728 + 169- 41
128x = 1856
x=14.5
8) Answer: e)
x3 – 149.996 * 1.5 = (5.01)2 * 8.99 + 177.2% of (9.99)3
x3– 150 * 1.5 = 25 * 8 + 177.2% of 1000
x3– 225 = 200 + 1772
x3 = 1972 + 225= 2197
x= 13
9) Answer: c)
x% of 160 = √[ 26 + 110% of 111 + 20% of 100 ]
x% of 160 = √[ 26 + 122 + 21]
x% of 160 = √169
x=(13/160)*100 = 8.125%
10) Answer: b)
2x = [32 * 25/4] * [10.24% of 50]
= 200 * 10.24 * 50/100
= 1024
x = 10