Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for SBI Clerk Prelims 2020 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
Approximation
Directions (01-04): Find out the approximate values comes in the place of (?) in the following questions.
1) 45.8% of 9502.20 – 1968.22 + 1682.43 =?
A.4294
B.6560
C.4080
D.4000
E.4120
2) 10.82Â + 11.023Â + 548.9 x 3.9 – ? = 1212
A.30
B.10
C.2168
D.2250
E.2440
3) 4564.12 ÷ 12 + 1453.22 – 782 = ? + 589.10
A.460
B.315
C.650
D.478
E.523
4) √728.82 +√ 3025.33 ÷ 5.22 + ? ÷ 8 = 975.550
A.7200
B.7250
C.7140
D.7500
E.7940
Data Interpretation
Directions (05-10): Study the following information carefully and answer the questions given below:
The following line graph represents the number of students in different Engineering colleges A, B, C and D in the year 2011 to 2014. The number of students is in lakh.
5) What is the sum of the total number of students in the college A, B, C and D in the year 2014?
A.3445000
B.3550000
C.3700000
D.3800000
E.3654000
6) What is the difference between the sum of the no. of students in college C and D in the year 2013 and the sum of the no. of students in college A and B in the year 2012?
A.1420000
B.1450000
C.1200000
D.1242500
E.1440200
7) What will be the ratio of the total no. of students of college A and C in 2013 to the total no. of students of college B and D in the same year?
A.13: 16
B.26: 8
C.28: 7
D.27: 7
E.26: 9
8) Find the average of the total no. of student of all the college in the year 2013.
A.700000
B.882000
C.120000
D.725000
E.187600
9) What is the approximate percentage of the total no. of students in college B in 2012 out of the total no. of students in all the colleges in 2012?
A.16%
B.11%
C.19%
D.24%
E.22%
10) If the ratio of science to commerce students is 7: 9 in college A in 2014 and the ratio of science to commerce students is 5:4 in college D in 2013, then find the ratio of the number of science students of college A in 2014 to the number of science students of college D in 2013.
A.7: 18
B.6: 21
C.5: 16
D.8: 19
E.7: 16
Answers :
1) Answer: C
45.8% of 9502.20 – 1968.22 + 1682.43 =?
46/100 x 9500 – 1968 + 1682 = ?
? = 4370 – 1968 + 1682 = 4084 = 4080 approx.
2) Answer: E
10.82Â + 11.023Â + 548.9 x 3.9 – ? = 1212
112 + 113 + 549 x 4 – 1212 = ?
121 + 1331 + 2196 – 1212 = 2436 = ?
? = 2440 approx
3) Answer: A
4564.12 ÷ 12 + 1453.22 – 782 = ? + 589.10
4564/12 + 1453 –782 – 589 = ?
380 + 1453 – 782 – 589 = ?
462 = ?
? = 460 approx.
4) Answer: D
√728.82 +√ 3025.33 ÷ 5.22 + ? ÷ 8 = 975.550
√729 + √3025 ÷ 5 +? ÷ 8 = 976
27 + 55/5 + ?/8 = 976
38 + ?/8 = 976
? = 7504 = 7500 approx.
5) Answer: D
Total students (A + B + C + D) in 2014 = (5 + 8 + 11 + 14) X 100000
= 3800000
6) Answer: C
No. of students (A + B) in 2012 = 400000 + 200000 = 600000
No. of students (C + D) in 2013 = 1800000
Difference = 1800000 – 600000 = 1200000
7) Answer: A
Required ratio = (4 + 9): (7 + 9) = 13: 16
8) Answer: D
Total students of (A + B + C + D) in 2013 = 2900000
Average = 2900000/4 = 725000
9) Answer: C
Approximate % = 400000/(200000 + 400000 + 700000 + 800000) x 100
= 19.04 = 19% approx.
10) Answer: E
Total students in college A in 2014 = 500000
Total students in college D in 2013 = 900000
Science students in college A in 2014 = 500000 x 7/16 = 218750
Science students in college D in 2013 = 900000 x 5/9 = 500000
Required ratio = 218750: 500000 = 7: 16
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