Quantitative Aptitude Questions (Profit and Loss) for SBI Clerk 2018 Day-11

Quantitative Aptitude Questions (Profit and Loss) for SBI Clerk 2018 Day-11:

Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from March 2018. To enrich your preparation here we have providing new series of Profit and Loss – Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.

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Click “Start Quiz” to attend these Questions and view Solutions

Daily Practice Test Schedule | Good Luck

Q.1) Arun earned a profit of 10% after allowing discount of 20%. Marked price is what percent more than the cost price?

1. 32.5%
2. 30.5%
3. 37.5%
4. 42.5%
5. 28.5%

Q.2) Shopkeeper bought two cycles Rs.2400 each. He sells one at 10% profit and another at x% loss in the whole transaction there is no profit or loss, and then find the value of ‘x’

1. 15%
2. 20%
3. 25%
4. 10%
5. 12%

Q.3) Vinoth sells an article at 10% profit. He bought it 20% less and sells Rs.50 more he gains 100% profit, and then find the cost price of an article

1. Rs.100
2. Rs.120
3. Rs.110
4. Rs.125
5. Rs.140

Q.4) Prabha bought two bi-cycles at Rs.5400. He sells one at 20% profit and another at 25% loss in the whole transaction there is no profit or loss, and then what is the difference of the cost price of the bi-cycles?

1. Rs.450
2. Rs.540
3. Rs.640
4. Rs.360
5. Rs.600

Q.5) A shopkeeper marks 50% above the CP and sells at 20% discount. If the profit is double the discount and the discount rate is same, then shopkeeper marks what % more than the CP?

1. 100%
2. 120%
3. 150%
4. 200%
5. 75%

Q.6) Nandi marks a book 20% above the CP and sells 10% less than the marked price. Kavi marks the same book 25% above the CP and sells 12% less than the marked price. Find whose profit percentage is maximum and how much?

1. Kavi-8%
2. Nandi-5%
3. Kavi-10%
4. Nandi-8%
5. None of these

Q.7) Sheela marks an item one-third more than the CP and allows successive discounts of x% and (x+10) %. If the SP of an item is Rs.288 and she losses at 4%, then find the value of ‘x’

1. 8%
2. 10%
3. 5%
4. 20%
5. 12%

Q.8) Ram bought two articles at Rs.7200 each. He sells one at 30% profit and another one at 20% loss; in the whole transaction he gained 5%. What is the difference of two articles SP?  

1. Rs.1800
2. Rs.1200
3. Rs.1400
4. Rs.1600
5. Rs.1500

Q.9) Kanish bought two mobiles (Redmi and Vivo), Redmi at Rs.x and Vivo at Rs.2x. She sold Redmi at 20% profit and Vivo at 25% loss, and then find the total CP of two mobiles if the difference between the SP of Vivo and Redmi is Rs. 2400

1. Rs.24000
2. Rs.16000
3. Rs.21000
4. Rs.36000
5. Rs.15000

Q.10) Racky and Vicky bought a bi-cycle Rs.x+10000 and Rs.x+5000 respectively. Racky sold it 20% loss and Vicky sold it 20% profit in the whole transaction losses 20/7% of total CP, what is the ratio of the CP of Racky’s bi-cycle to the CP of Vicky’s bi-cycle?   

1. 2:3
2. 3:4
3. 1:2
4. 4:3
5. Cannot be determined

Answers:

Q.1) Answer: c

Let us take CP be Rs.100

SP= 110 =80% of marked price

MP = 110/80*100=137.5

Required percentage = 37.5/100*100=37.5%

Q.2) Answer: d

Given,

2400*110/100+2400*(100-x)/100=4800

=>2400*(100-x)/100=4800-2640

Simplify the above equation, we get x=10%

Q.3) Answer: a

Let us take CP of an article be x

SP = 110/100 *x

CP= 80/100*x

SP=110/100 *x+50=200/100*80/100*x

5/10*x=50=>x=100

Q.4) Answer: e

Let us take CP of one at x and another at 5400-x

Given,

X*120/100+(5400-x)*75/100=5400

24x+(5400-x)*15=5400*20

=>9x=5400*5=>x=3000

Required difference= 3000-2400=600

Q.5) Answer: a

Let us take CP Rs.100

MP = 150

SP= 150*80/100=120

Profit = 120-100=20

Incase profit = 60

SP= 160

MP=160/80*100=200

Required percentage = 100/100*100=100%

Q.6) Answer: c

Let us take CP be Rs.100

Nandi’s selling price = 120*90/100=108

Profit %= 8/100*100=8%

Kavi’s SP = 125*88/100=110

Profit % =10%

Q.7) Answer: b

CP = 288/96*100=Rs.300

MP= 300+300*1/3=400

SP=400*(100-x)/100*(90-x)/100=288

Simplify the above equation, we get x=10%

Q.8) Answer: a

Over all CP=7200

Over all SP = 7200*105/100=7560

Given,

(7200-x)*(100+30)/100+x*(100-20)/100=7560

Simplify the above equation, we get x=3600

Required difference = 3600*130/100-3600*80/100=4680-2880=1800

Q.9) Answer: a

Given,

(2x*75/100)-(x*120/100) =2400

15x-12x=24000=>x=8000

Total CP = 3*8000=24000

Q.10) Answer: d

Given,

(x+10000)*80/100+(x+5000)*120/100=(2x+15000)-(2x+15000)*20/700

70x-68x=510000-490000=2x=20000=>x=10000

Required ratio = 20000:15000=4:3

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