“20-20” Quantitative Aptitude | Crack SBI Clerk 2018 Day-39

By Valar Mathi - Mar 08 2018

Dear Friends, SBI Clerk 2018 Notification has been released we hope you all have started your preparation. Here we have started New Series of Practice Materials specially for SBI Clerk 2018. Aspirants those who are preparing for the exams can use this “20-20” Quantitative Aptitude Questions.

Daily Practice Test Schedule | Good Luck

Topic Daily Publishing Time
Daily News Papers & Editorials 8.00 AM
Current Affairs Quiz 9.00 AM
Logical Reasoning 10.00 AM
Quantitative Aptitude “20-20” 11.00 AM
Vocabulary (Based on The Hindu) 12.00 PM
Static GK Quiz 1.00 PM
English Language “20-20” 2.00 PM
Banking Awareness Quiz 3.00 PM
Reasoning Puzzles & Seating 4.00 PM
Daily Current Affairs Updates 5.00 PM
Data Interpretation / Application Sums (Topic Wise) 6.00 PM
Reasoning Ability “20-20” 7.00 PM
English Language (New Pattern Questions) 8.00 PM
General / Financial Awareness Quiz 9.00 PM 
[WpProQuiz 1449]

Click “Start Quiz” to attend these Questions and view Explanation

Click Here for SBI Clerk Prelims and Mains 2018 – Full Length Mock Test

Directions (Q. 1-5): What should come in place of question mark (?) in the following number series?

  1. 31, 65, 135, 277, ?
  1. 563
  2. 478
  3. 343
  4. 726
  5. None of these
  1. 729, 243, 81, 27,?
  1. 6
  2. 15
  3. 9
  4. 12
  5. None of these
  1. 15, 23, 37, 63, 113, ?
  1. 178
  2. 211
  3. 347
  4. 421
  5. None of these
  1. 39, 37, 46, 18, ?
  1. 78
  2. 9
  3. 83
  4. 12
  5. None of these
  1. 89, 44, 21.5, ? , 4.625
  1. 10.25
  2. 15.75
  3. 16.5
  4. 18.75
  5. None of these

 

Directions (Q. 6-10): What value will come in place of question mark (?) in the given questions? (You are not expected to calculate the exact value)

  1. (64.01)2 × (65)1/3 × (25.99)2 ÷ (211 × (12.97)2) = 2x
  1. 7
  2. 9
  3. 3
  4. 8
  5. 5
  1. (3/8) of 111 =? ÷ (2.1 × 0.98)
  1. 56
  2. 72
  3. 96
  4. 84
  5. 44
  1. (25.12 % of 400.01) ÷? = (125% of 3.98)2
  1. 8
  2. 4
  3. 6
  4. 12
  5. 14
  1. √x = (1247.97 + 52.1) ÷ 100.1 – 7.98
  1. 45
  2. 15
  3. 30
  4. 25
  5. 40
  1. 78.89% of 790 – 12.487 % of 3279.82 =?
  1. 200
  2. 140
  3. 170
  4. 215
  5. 115
  1. A profit of 7 % is made by selling a shirt after offering a discount of 15%. If the marked price of the shirt is Rs. 2675. Find its Cost price.
  1. 1985
  2. 1835
  3. 2125
  4. 1650
  5. None of these
  1. A and B invested in the ratio of 6:7. The profits are divided in the ratio of 3:5. If A has invested for 7 months, then B invested for?
  1. 8 months
  2. 10 months
  3. 9 months
  4. 7 months
  5. None of these
  1. If the numerator of the fraction is increased by 30 % and the denominator of the fraction is decreased by 75 % then the resultant fraction is 21/25. Find the original fraction?
  1. 21/25
  2. 18/35
  3. 5/212
  4. 21/130
  5. None of these
  1. The present age of Vinay is equal to Ragu’s age 8 years ago. Four years hence, the ages of Vinay and Ragu is in ratio of 4:5. Find Vinay’s Present age?
  1. 32 years
  2. 28 years
  3. 25 years
  4. 26 years
  5. None of these
  1. 5 women and 6 men can do a work in 8 days. 4 women and 9 men can do a same work in 6 days. How long will 8 women and 9 men can take to do the work?
  1. 6 days
  2. 5 ¼ days
  3. 7 ½ days
  4. 4 ¾ days
  5. 8 days

Directions (Q. 16 – 20): Study the following table carefully and answer the given questions.

The following table shows the sales of different types of cars (in hundred) from January to September in Mumbai.

  1. The sale of which car shows continuous increase with respect to the previous month?

a) Audi

b) I20

c) Hummer

d) Ciaz

e) BMW

  1. What was the percentage increase in the sale of the total no. of cars of last three types from Jan to September?

21%

30%

None of these

16.66%

33.33%

  1. Find the difference between the Hummer cars and Lancer cars sold over the given months?

a) 18900

b) 12650

c) 13700

d) 14450

e) None of these

  1. In which of the following months was the total number of cars sold the maximum?

a) January

b) June

c) May

d) September

e) July

  1. The number of Volvo cars sold from Jan to September is approximately what per cent more than that of I20 sold during the same period?

a) 45%

b) 35%

c) 50%

d) 55%

e) 40%

Answers With Solutions:

  1. Answer a

Explanation:

The pattern is, *2+3, *2+5, *2 +7, *2+9

The answer is, 563

  1. Answer c

Explanation:

The pattern is, ÷3

The answer is, 9

  1. Answer b

Explanation:

The difference of difference is 6, 12, 24, 48…

The answer is, 211

  1. Answer c

Explanation:

The pattern is, – (13 +1), + (23 +1), – (33 +1), + (43+1)…

The answer is, 83

  1. Answer a

Explanation:

The pattern is, ÷2 – 0.5

The answer is, 10.25

  1. Answer e

Explanation:

(64 × 64 × 4 × 26 × 26) / (211 × 13 × 13) = 2x

(26 × 26 × 24)/ 211 = 2x

26+6+4 -11 = 2x

25 = 2x

X=5

  1. Answer d

Explanation:

(3/8) × 111 = x/2

42*2 = x

X= 84

  1. Answer b

Explanation:

(25/100)*400 ÷ x = ((125/100) * 4)2

100/x = 52

100/25 = x

X = 4

  1. Answer d

Explanation:

√x = (1300/100) – 8

√x = 13 -8 =5

X= 25

  1. Answer a

Explanation:

(79/100)*790 – (13/100)*3280 = x

79 * 7.9 – 13*33 = x

632 – 429 =x

X= 203~200

11.Answer c

Explanation:

Marked Price = Rs. 2675

Profit = 7%, Discount = 15%

SP = MP*(85/100)

SP = CP* (107/100)

2675 *(85/100) = CP* (107/100)

CP = 2125

  1. Answer b

Explanation:

Investment ratio = 6:7

Profits = 3:5, A has invested for 7 months.

Ratio of Profit = 6*7: 7*x = 42: 7x

According to the question,

42/7x = 3/5

X = 10 months

13.Answer d

Explanation:

Let original fraction be x/y.

(X*130/100) / (y*25/100) = 21/25

x/y = (21/25)*(25/130)

x/y = 21/130

  1. Answer b

Explanation:

Present age of Vinay = Ragu’s age 8 years ago

4 years hence, Vinay: Ragu = 4:5 (4x, 5x)

Present ages will be, 4x-4, 5x-4

According to the question,

4x-4 = 5x-4-8

X=8

Present age of Vinay = 4x-4 = 32-4 =28 years

  1. Answer b

Explanation:

Total work = (men (or) women)*days

Work equal, so,

(5 w + 6 m)*8 = (4 w + 9 m)*6

40 w + 48 m = 24 w + 54 m

16 w= 6 m

8 w = 3 m

1 w = (3/8) m

4 w + 9 m = 4*(3/8) m+ 9 m = (21/ 2) m

8 w + 9 m = 3 m + 9 m = 12 m

Men            days

(21/2)                   6

12               ?

(21/2)*6 = 12x

X= 21/4 days = 5 ¼ days

16). Answer d

Explanation:

Ciaz only shows continuous increase with respect to the previous months.

  1. Answer b

Explanation:

Total number of required cars sold in January = 22 + 30 + 18 = 70

Total number of required cars sold in September = 30 + 40 + 21 = 91

Required % increase = [(91-70)/70] × 100 = 30%

  1. Answer a

Explanation:

Required difference = [552-363] × 100 = 18900

19.Answer e

Explanation:

Total no. of cars sold in different months Jan – 21400

June – 34800

July – 37000

May – 32300

September – 35100

Hence the total number of cars sold was the maximum in the month of July.

20.Answer a

Explanation:

Required more % = [(463 – 319) / 319] × 100 = 45%.

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