Dear Aspirants, Here we have given the Important RRB ALP & Technicians Exam 2018 Practice Test Papers. Candidates those who are preparing for RRB ALP 2018 can practice these Arithmetic Questions to get more confidence to Crack RRB 2018 Examination.
[WpProQuiz 1454]
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- If a & b are whole numbers such that ab = 361 then (a+1)b-1 =?
(A) 10
(B) 30
(C) 20
(D) 11
- In an examination, it is required to get 64% of the aggregate marks to pass. A student gets 440 marks and is declared failed by 9% marks. What are the maximum aggregate marks can a student get?
(A) 850
(B) 780
(C) 900
(D) 800
- Giridhar purchased 100 sarees at the rate of Rs. 450 per piece. While selling, he offered 10% discount on labelled price and earned a profit of 20%. What was the labelled price of each saree?
(A) Rs. 540
(B) Rs.600
(C) Rs. 590
(D) Rs. 650
- The sum of two numbers is 23 and the difference is 5. What is the sum of their squares?
(A) 277
(B) 291
(C) 349
(D) 554
- How many different words can be formed by using the letters of the word ALLAHABAD so that the vowels are always together?
(A) 512
(B) 360
(C) 396
(D) 420
- The HCF of two numbers in the ratio 2: 7 is 23. Find their LCM.
(A) 322
(B) 46
(C) 151
(D) 197
7.If the sum and product of the roots of a quadratic equation are 8 and 15, then the quadratic equation is
(A) x2 – 8x – 15 = 0
(B) x2 + 8x + 15 = 0
(C) x2 – 8x + 15 = 0
(D) x2 + 8x – 15 = 0
- A sphere and a right circular cylinder have equal volume and radii. What is the ratio of the height of the cylinder to the radius?
(A) 3: 4
(B) 4: 3
(C) 9: 16
(D) √3: √4
- Select the option that will replace the question mark (?) in the given series to make it continuous.
8, 12, 30, 105, 472.5, ? , 16891.875
(A) 2598.75
(B) 2597.25
(C) 2598.25
(D) 2545.25
- What should be placed in place of x so that 23567×32 will be divisible by 11?
(A) 4
(B) 6
(C) 5
(D) 7
Answer:
- Answer: C
The given expression is: ab = 361
ab = 192
Comparing both sides, we get a = 19 & b = 2
Value of (a+1)b-1=( 19+1)2-1= (20)1= 20.
- Answer: D
Marks obtained by a student = (64% – 9%) of maximum aggregate marks = 55% of the maximum aggregate marks
55% of aggregate marks = 440
Aggregate marks = 440/55*100= 800
- Answer: B
Discount = 10% (Given)
Therefore, S.P. = 90% of M.P ….(1)
Profit = 20% (Given)
Therefore, S.P. = 120% of C.P…..(2)
By combining (1) and (2), we get:
90% of M.P. = 120% of C.P.
M.P. = 4/3 of C.P. = 4/3 × 450 = 600
- Answer: A
Let the first number be x Second number = 23 – x
According to the question, x – (23 – x) = 5 x – 23 + x = 5 2x = 28 x = 14
First number = 14
Second number = 9
Sum of the squares of numbers = 142 + 92 = 196 + 81 = 277
- Answer: B
There are 4 vowels and 5 consonants in the word ALLAHABAD.
Let’s consider 4 vowels to be 1 letter.
Now, we have 5 + 1 = 6 letters, and these 6 letters can be arranged in 6!/2! = 360 ways. (Note that the consonant L is there twice in the word.)
Also, the 4 vowels can be arranged among themselves in 4!/4! ways.
Therefore, the total number of words that can be formed is 360 × 1 = 360.
- Answer: A
Since the numbers are in the ratio 2: 7 and HCF is 23, the required LCM = 2 × 7 × 23 = 322
7.Answer: C
Equation with roots α and β is x2 – (α + β) x + αβ = 0. Hence, the required equation is x2 – 8x + 15 = 0.
- Answer: B
Let the radius be r and height of the cylinder is h.
4/3 πr3= πr2h
4/3 r=h
h/r =4/3
- Answer: A
472.5 × 5.5 = 2598.75
- Answer: B
A number is divisible by 11 if the difference between the sum of numbers at even places and the sum of numbers at odd places is either 0 or divisible by 11.
The difference of the sum of numbers at even places and odd places = 2 + 5 + 7 + 3 – (3 + 6 + x + 2)
= 17 – 11 – x
= 6 – x
6 – x is zero, when x = 6
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-1)
RRB ALP 2018 Practice Test Papers | Arithmetic Questions (Day-2)
