Quantitative Aptitude Questions (Ages) for SBI Clerk 2018 Day- 81

Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June 2018. To enrich your preparation here we have providing new series of Ages – Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.

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1. Jegan’s present age is 1/5^th of his father’s age, after 4 years. After 5 years, Jegan’s father’s age will be three times of Raju’s age. Find Jegan’s age, if Raju celebrated his 15^th birthday 2 years back.

1. 14 years
2. 16 years
3. 10 years
4. 12 years
5. None of these

2. The ratio between Gowtham and Mano is 42:x. Mano is 8 years younger than Gayathri. Gayathri’s age after 7 years will be 32 years. The difference between Mano and Gowtham is equal to Gayathri’s age. Find the value of x?

1. 19 years
2. 17 years
3. 15 years
4. 13 years
5. None of these

3. Jeya has 3 daughters namely Moni, Sree and Subha. Moni is eldest one and Subha is youngest one in the family. The present age of all three of them is square numbers. 8 years hence, sum of the ages of 3 daughters is 85. Find the age of Moni, 3 years ago?

1. 33 years
2. 28 years
3. 25 years
4. 36 years
5. None of these

4. The ratio of present age of Nivetha and Renuka is 3: 5. Nivetha is 7 years younger than Banu. After 8 years Banu’s age is 30. Then find the present age of Renuka?

1. 21 years
2. 27 years
3. 23 years
4. 25 years
5. None of these

5. The sum of twice the age of Saaru and her father is 79 and the sum of twice the age of her father and Saaru is 104. The average age of Saaru and her father and mother is 32. Then find the present age of Saaru’s mother?

1. 25 years
2. 27 years
3. 31 years
4. 33 years
5. None of these

6. Sum of the ages of Vasu, Ravi, Chitra and Naveen is 78. Vasu is 5 years older than Ravi and Chitra is 3 years older than Naveen and Vasu is 9 times the age of Naveen. Find the age of Chitra?

1. 7 years
2. 9 years
3. 12 years
4. 14 years
5. None of these

7. The present age of A and B is in the ratio of 5: 6. 8 years hence, the age of A and B is in the ratio of 7: 8. Find the sum of the present ages of A and B?

1. 36 years
2. 32 years
3. 44 years
4. 38 years
5. None of these

8. The sum of the present age Raji and her son is 70 years. 15 years ago, Raji’s age was 3 times of her son. Then find the present age of Raji’s son?

1. 21 years
2. 27 years
3. 29 years
4. 25 years
5. None of these

9. Ashok got married 14 years ago. His present age is 7/5^th of his age at the time of marriage. Ashok’s brother is 10 years younger to him. Find the age of Ashok’s brother at the time of his marriage?

1. 18 years
2. 25 years
3. 21 years
4. 26 years
5. None of these

10. 5 years ago, the age of the father is 3 times the age of his son. 7 years hence, the age of the father and his son is in the ratio of 19:9. The average Present age of the father, mother, son and daughter is 30. The difference between the age of the mother and her daughter is 30. Then find the present age of the daughter?

1. 10 years
2. 14 years
3. 18 years
4. 16 years
5. None of these

Answers:

1. Answer c

Raju’s present age = 17 years

After 5 years, Jegan’s father’s age = 3*Raju’s age

= > 3*17 = 51 years

Present age of Jegan’s father = 46 years

Jegan’s present age = (1/5)* Jegan’s father’s age after 4 years

= > J = (1/5)*50

= > J = 10

Jegan’s present age = 10 years

2. Answer b

The present age of Gowtham and Mano = 42 : x

Mano = Gayathri – 8

Gayathri’s age = 32 – 7 = 25 years

Mano = 25 – 8 = 17

Gowtham’s age – Mano’s age = Gayathri’s age

Gowtham’s age = 17 + 25 = 42

The value of x = 17 years

3. Answer a

Let the ages of 3 daughters be x, y and z

According to the question,

x+y+z+24 = 85

x + y + z = 85-24 = 61

Possible square numbers are, 1, 4, 9, 16, 25, 36, 49

So,

The ages are, 9, 16 and 36

The age of Moni = 36, Sree = 16 and Subha = 9 years

The age of Moni, 3 years ago = 33 years

4. Answer d

The ratio of present age of Nivetha and Renuka = 3 : 5

Nivetha = Banu – 7

After 8 years, Banu’s age = 30

Present age of Banu = 22

Nivetha = 22 – 7 = 15

3’s = 15

1’s = 5

Present age of Renuka = 5’s = 25 years

5. Answer e

Let the age of Saaru and her father be x and y,

2x + y = 79–>(1)

X + 2y = 104 –>(2)

By solving (1) and (2),

Y = 43, X = 18

The average age of Saaru and her father and mother = 32

Sum of the ages of Saaru and her father and mother = 32*3 = 96

Present age of Saaru’s mother = 96 – (43 + 18) = 35 years

6. Answer a

Let the age of Vasu be x,

Sum of the ages of Vasu, Ravi, Chitra and Naveen = 78

Vasu + Ravi + Chitra + Naveen = 78

Vasu = Ravi + 5

Chitra = Naveen + 3

Vasu = 9*Naveen

According to the question,

= > x + x – 5 + (x/9) + 3 + (x/9) = 78

= > 2x +(2x/9) = 80

= > 20x = 720

= > x = 36

Vasu = 36 years

Chitra = (Vasu/9) + 3 = (36/9) +3 = 7 years

7. Answer c

The present ratio of age of A and B = 5: 6

8 years hence, the ratio of age of A and B = 7: 8

According to the question,

(5x + 8)/(6x + 8) = (7/8)

40x + 64 = 42x + 56

2x = 8

X = 4

The present age of A = 20, the present age of B = 24

Required sum = 20 + 24 = 44 years

8. Answer d

The sum of the present age Raji and her son = 70 years

Raji + Raji’s son = 70

15 years ago, the ratio of the age of Raji and her son = 3: 1

According to the question,

3x + 15 + x + 15 = 70

4x = 70 – 30

4x = 40

X = 10

Present age of Raji’s son = x + 15 = 25 years

9. Answer b

Ashok got married 14 years ago,

Present age of Ashok = (7/5)*Ashok’s age at the time of marriage

Present age of Ashok: Ashok’s age at the time of his marriage = 7: 5

= > 2’s = 14

= > 1’s = 7

Present age of Ashok = 7’s = 49

Ashok’s brother = Ashok – 10 = 49 – 10 = 39 years

The age of Ashok’s brother at the time of his marriage = 39 – 14= 25 years

10. Answer a

5 years ago, the ratio of age of the father and his son = 3: 1(3x, x)

7 years hence, the ratio of age of the father and his son = 19: 9

According to the question,

(3x + 12)/(x + 12) = (19/9)

27x + 108 = 19x + 228

8x = 120

X = 15

The present age of the father and his son = (3x + 5), (x + 5) = 50, 20

The average Present age of the father, mother, son and daughter = 30

Total Present age of the father, mother, son and daughter = 30*4 = 120

Total present age of the mother and her daughter = 120 – 70 = 50

Let the present age of mother and daughter be A and B,

A + B = 50—>(1)

A – B = 30—>(2)

By solving the equation (1) and (2),

A = 40, B = 10

The present age of the daughter = 10 years

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