Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June 2018. To enrich your preparation here we have providing new series of Time and Work- Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.
[WpProQuiz 2710]
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- P, Q and R can complete the whole work in 15 days. P starts the work and works for ‘x’ days while Q and R complete the remaining 2/5 of the work in 8 days then find the value of x?
- 28 days
- 30 days
- 36 days
- 32 days
- None of these
- A can complete 2/3 of the work in 6 days. If A and B together the complete the work in 6 days, then find the time required by C, who is twice efficient than B?
- 9 days
- 7 days
- 12 days
- 5 days
- None of these
- P takes 9 days to complete 3/5 of the work, Q takes 3 days to complete 3/7 of the same work and R takes 4 days to complete 2/5 of the same work. If they work for 2 days together then Q and R leaves the work. Find the number of days P will take to complete the remaining work?
- 6 2/5 days
- 7 ½ days
- 4 ¾ days
- 5 5/7 days
- None of these
- 32 men can complete a piece of work in 20 days. After 8 days from the start of the work, some men left. If the remaining work was completed by the remaining men in 16 days, how many men left after 8 days from the start of the work?
- 10 men
- 8 men
- 6 men
- 5 men
- None of these
- If 30 men can do a piece of work in 20 days by working for 7 hours then find in how many days 42 men can do the same work by working 5 hours a day?
- 20 days
- 18 days
- 24 days
- 16 days
- None of these
- A can do a work in 25 days and B can do it in 20 days. They started the work together after 5 days of the work, B left the job. Then in how many days A can complete the remaining work?
- 11 ½ days
- 12 5/7 days
- 14 4/5 days
- 13 ¾ days
- None of these
- Kailash and Mathesh can do the work in 15 days and 18 days respectively. Both of them started the work together but kailash left the job 5 days before the completion of the work. How many days will they take to complete the whole work?
- 11 3/7 days
- 10 10/11 days
- 12 5/9 days
- 8 4/5 days
- None of these
- If 5 men or 8 women or 12 boys can finish a work in 60 days working 8 hours a day. The no of days taken by 15 men, 4 women and 24 boys working 12 hours a day will be?
- 8 4/9 days
- 7 3/11 days
- 9 3/7 days
- 6 5/13 days
- None of these
- Rajesh can do a work in 20 days. He works alone for 4 days and Yuva alone finishes the remaining work in 12 days. Both of them together can complete the work in?
- 11 3/11 days
- 10 5/9 days
- 8 4/7 days
- 9 2/5 days
- None of these
- Ravi and Manoj together can do the work in 15 days. Ganesh can do the same work in 40 days. Ravi is twice efficient than Ganesh. Find the time taken by Manoj to do the work alone?
- 60 days
- 40 days
- 50 days
- 45 days
- None of these
Answers:
1). Answer c
(2/5) of the work completed by Q and R in 8 days
(2/5)*(Q + R)’s whole work = 8
(Q + R)’s whole work = 8*(5/2) = 20 days
(P + Q + R)’s whole work = 15 days
P’s one day work = (1/15) – (1/20) = 5/(15*20) = (1/60)
P can complete the work alone in 60 days.
(1/60)*x = (3/5)
X = 36 days
2). Answer a
A can complete the whole work in,
= > 2/3*A’s whole work = 6
= > A’s whole work = 9 days
A’s one day work = (1/9)
(A + B)’s one day work = (1/6)
B’s one day work = (1/6) – (1/9) = (9 – 6)/54 = 3/54 = 1/18
B can complete the work in 18 days.
Efficiency ratio, B: C = 1: 2
Day ratio, B: C = 2: 1
2’s = 18
1’s = 9
‘C’ can complete the work in 9 days.
3). Answer d
Time taken by P = 9*5/3 = 15 days
Q = 3*7/3 = 7 days
R = 4*5/2 = 10 days
(P + Q + R)’s one day work = (1/15) + (1/7) + (1/10) = 65/210
(P + Q + R)’s 2 day work = (65/210)*2 = 13/21
Remaining work = 1 – (13/21) = 8/21
Remaining work done by P alone in,
(8/21)*15 = 40/7 = 5 5/7 days
4). Answer b
Total units of work = 32*20= 640 units
Work done in 8 days = 32*8= 256 units
Remaining work = 640 -256 = 384 units
Let the number of men left after 8 days be x
So,
32-x men completed the remaining 384 units in 16 days
So,
(32-x)*16 = 384
512 – 16x = 384
16x = 128
X= 8 men
5). Answer a
Let the number of days required be x
M1*D1*H1 = M2*D2*H2
30*20*7 = 42*5*x
X = (30*20*7)/(42*5)
X = 20 days
6). Answer d
A’s one day work = (1/25)
B’s one day work = (1/20)
(A + B)’s one day work = (1/25) + (1/20) = (25 + 20)/(25*20)
= > 9/100
(A + B)’s 5 day work = (9/100)*5 = 9/20
Remaining work = 11/20
A can complete the remaining work in,
(11/20)*25 = 55/4 = 13 ¾ days
7). Answer b
(x – 5)/15 + x/18 = 1
(18x – 90 + 15x)/(18*15) = 1
33x – 90 = 270
33x = 360
X = 360/33 = 120/11 = 10 10/11 days
8). Answer b
5 men = 8 women
8 women = 12 boys
15 men and 4 women and 24 boys = 24 women + 4 women + 16 women = 44 women
Women days hours
8 60 8
44 ? 12
(8*60*8) = (44* x days *12)
X = (8*60*8)/(44*12) = 80/11 = 7 3/11 days
9). Answer c
Rajesh’s one day work = (1/20)
Rajesh’s 4 days work = (4/20) = 1/5
Remaining work = 1- 1/5 = 4/5
(4/5)*Yuva’s whole work = 12
Yuva’s whole work = 12*(5/4) = 15
Yuva’s one day work = 1/15
(Rajesh + Yuva)’s one day work = (1/20) + (1/15)
= > (20 + 15)/(20*15)
= > 7/60
(Rajesh + Yuva)’s whole work = 60/7 = 8 4/7 days
10). Answer a
(Ravi + Manoj)’s one day work = (1/15)
Ganesh’s one day work = (1/40)
Efficient ratio = > Ravi: Ganesh = 2: 1
Day ratio = > Ravi: Ganesh = 1: 2
2’s = 40
1’s = 20
Ravi can do the work in 20 days.
Ravi’s one day work = (1/20)
Manoj’s one day work = (1/15) – (1/20) = (20 – 15)/(20*15) = 1/60
Manoj can do the work in 60 days.
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