Dear Aspirants, Quantitative Aptitude plays a crucial role in Banking and all other competitive exams. To enrich your preparation, here we have provided New Pattern Aptitude Questions for IBPS Clerk Mains. Candidates those who are going to appear in IBPS Clerk Mains can practice these questions daily and make your preparation effective.
[WpProQuiz 4892]Click Here for IBPS Clerk Mains Online Mock Test
Click here to View Quantitative Aptitude Questions in Hindi
Directions (1-5): Study the following information carefully and answer the given questions:
The given table shows the number of students in three classes namely7th, 8th and 9th at five different schools. Some of the data are missing in the table.
1) If the total number of students in the class 8th of all the school is 900 and the total number of students in school C and D is 400 and 470 respectively. Find the total number of students in class 7 of school D?
a) 120
b) 140
c) 150
d) 100
e) None of these
2) If the number of students in class 9th of school A is 10 more than the number of students in class 9th of school B respectively. The total number of students of school B and school A is 400 and 420. The ratio of the number of students in class 7th of school D and A is 5:7 and the average number of students in school E is 180. If the ratio of the number of students of class 9 and class 7 of school E is 6:5, then what is the average number of students in class 7th of all the five schools?
a) 124
b) 126
c) 128
d) 122
e) None of these
3) If the number of students in class 9th of school B is twice the number of students in class 9th of school A and the number of students in class 9 of school E is 20 more than the number of students in that same class of school A. The number of students of class 8 of school C is 105(5/19)% of the number of students of class 9 of school E. The average number of students in class 9 of all five schools is 128, then what is the ratio of the total number students in school B to the total number of students of school C?
a) 43:38
b) 41:37
c) 45:32
d) Cannot be determined
e) None of these
4) The total number of students of school A and D is 400 and 420 respectively. The ratio of the number of students in class 9th of school A to the number of students in class 8th of school C is 2:3. The average number of students in class 7th of all the five schools together is 130 and number of class 8th students of school D is 20% more than that of the number of students in class 7th of school D. If the ratio of the number of students of class 7th of school E and A is 5:4, what is the total number of students in class 8th of all school?
a) 850
b) 800
c) 1200
d) 1000
e) 900
5) The number of students of class 8th D is 60 more than that of the number of students of class 8th in school C. The number of students in class 7 of school A and D is 20% and 80% more than the number of students in class 7 of school E respectively. The number of students of class 8th of school C is 80% of the number of class 8th of school A. The average number of students in class 8th of all the five schools is 46 more than the average number of students in class 7 of all the five schools, then what is sum of the number of students in class 7th of school D and A together?
a) 215
b) 320
c) 315
d) 325
e) None of these
Directions (6-10): Study the following information carefully and answer the given questions:
The given line graph shows the length of the platform (in meter).
The given table shows the speed of the train.
6) What is the length of train B?
Statement I: The speed of a train B is 50% more than that of the speed of train A and Train A will cross the platform4 in 36 seconds.
Statement II: Train A and train B running in the opposite direction and the train A crosses the train B in 18 seconds.
a) Only I
b) Only II
c) Either I or II are sufficient
d) All I and II necessary to the answer the question
e) The question can’t be answered even with all I and II
7) The Length of train E is 300m and it takes 18 seconds to cross the platform5 completely and the train C crosses the platform3 in 36 seconds. If Train E and train C running in same direction, in what time will they be clear of each other from the moment they meet?
a) 410 seconds
b) 810 seconds
c) 840 seconds
d) 800 seconds
e) None of these
8)
Quantity I: Two trains D and C are of equal length and running in same direction. The faster train passes the slower train in 54 seconds. The length of each train is?
Quantity II: Train B crosses the platform5 in 54 seconds and the length of train B is 800% of the length of the platform. What is the speed of the train?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
9) Train B overtakes two persons who are walking in the same direction as the train is moving at speed of 3kmph and 6kmph respectively in 6seconds and 9 seconds respectively. Then the train B crosses the platform2 in x seconds. Find the value of x?
a) 34.5 seconds
b) 27.5 seconds
c) Cannot be determined
d) 31.5 seconds
e) None of these
10) The ratio of the length of train C and train B is 5:4. Train B cross the pole in 12 seconds and the train C cross the platform1 in 18 seconds. If train B and train E running opposite direction, cross each other in 12 seconds, and length of the train E is 120% of the length of train C, then find the speed of train E?
a) 150kmph
b) 120kmph
c) 180kmph
d) 100kmph
e) None of these
Answers :
Direction (1-5) :
1) Answer: A
Number of students in class 8 of school C=400-(160+120) =120
Number of students in class 8 of school D=900-(150+160+120+320) =150
Number of students in class 7 of school D=470-(150+200) =120
2) Answer: A
Number of students of class 9th of school B=400-(120+160) =120
Number of students of class 9th of school A=120+10=130
Number of students of class 7th of school A=420-(150+130)=140
Number of students of class 7th of school D=5/7*140=100
Total number of students of school E=180*3=540
Total number of students of class 7th and class 9th of school E=540-320=220
Number of students of class 7th of school E=5/11*220=100
Required average= (140+120+160+100+100)/5=124
3) Answer: A
Number of students of class 9 of school A=x
Number of students of class 9 of school B=2x
Number of students of class 9 of school E=x+20
(x+2x+x+20+120+200)/5=128
x=75
Number of students of class 9 of school B=2(75) =150
Total Number of students of school B=120+160+150=430
Number of students of class 9 of school E=75+20=95
Number of students of class 8 of school C=105(5/19)% *95=100
Total Number of students of school C=160+100+120=380
Required ratio=430:380=43:38
4) Answer: E
Number of students in school D=420
Let Number of students of class 7th of school D=x
Number of students of class 8th of school D=x*120/100=6x/5
200+x+6x/5=420
11x/5=220
x=100
Number of students of class 7th of school D=100
Number of students of class 8th of school D=600/5=120
Total number of students of class 7 of all the 5 schools together=130*5=650
Total Number of class 7 students of school E and A=650-(120+160+100)=270
Number of students in Class 7 of school A=5/9*270=150
Number of students in Class 9 of school A=400-(150+150)=100
Number of students in Class 8th of school C=3/2*100=150
Required total=150+160+150+120+320=900
5) Answer: C
Number of students of class 8th of school C=80/100*150=120
Number of students of class 8th of school D=120+60=180
Average number of students of class 8th in all the five schools
= (150+160+120+180+320)/5
=186
Average number of students of class 7th in all the five schools=186-46=140
Total number of students of class 7th of all the five schools=140*5=700
Let Number of students of class 7th of school E=x
Number of students of class 7th of school A=x*120/100=6x/5
Number of students of class 7th of school D=x*180/100=9x/5
(x+6x/5+9x/5+120+160)=700
20x/5=420
x=105
Thus Number of students of class 7th of school A=6*105/5=126
Number of students of class 7th of school D=9*105/5=189
Required sum=126+189=315
Direction (6-10) :
6) Answer: D
From Statement I,
Speed of train B=150/100*60=90kmph
Length of train A=X
X+280=60*5/18*36
X=600-280=320m
So, Statement I alone is not sufficient to the answer the question.
From Statement II,
Train A and train B running in the opposite direction and the train A crosses the train B in 18 seconds.
So, Statement II alone is not sufficient to the answer the question.
From I and II,
Length of train B=y
320+y=(90+60)*5/18*18
y=750-320=430m
7) Answer: B
Speed of train E*5/18=(300+120)/18
Speed train E=84kmph
Length of train C+200=80*5/18*36
Length of train C=600m
Time= (300+600)/((84-80)*5/18)
Time=900*18/(4*5)=810 seconds
8) Answer: A
From Quantity I,
Length of the train D=x
(x+x)=(80-70)*5/18*54
2x=10*5*3
x=75m
From quantity II,
Length of train B=120*800/100=960m
(960+120)=(speed of train)*5/18*54
1080=speed of train*15
Speed of train=72kmph
9) Answer: A
Length of train B=x
Speed of the train B=y
x=(y-3)*5/18*6
3x=5y-15
3x+15=5y
x=(y-6)*5/18*9
2x=5y-30
2x+30=5y
2x+30=3x+15
x=15m
Length of the train x=15m
5y=3(15) +15
5y=60
y=12kmph
Required time x=(15+100)/(12*5/18)
x=115*18/12*5=34.5 seconds
10) Answer: A
Length of train C =x
x+150=80*5/18*18
x=400-150=250m
Length of train B=4/5*250=200m
Length of train E=120/100*250=300m
Speed of train E*5/18=500/12=1800/12=150kmph
Click Here for IBPS Clerk Mains Online Mock Test
Daily Practice Test Schedule | Good Luck
| Topic | Daily Publishing Time |
| Daily News Papers & Editorials | 8.00 AM |
| Current Affairs Quiz | 9.00 AM |
| Current Affairs Quiz (Hindi) | 9.30 AM |
| NIACL AO Prelims – Reasoning | 10.00 AM |
| NIACL AO Prelims – Quantitative Aptitude | 11.00 AM |
| Vocabulary (Based on The Hindu) | 12.00 PM |
| NIACL AO Prelims – English Language | 1.00 PM |
| SSC Practice Questions (Reasoning/Quantitative aptitude) | 2.00 PM |
| IBPS Clerk – GK Questions | 3.00 PM |
| SSC Practice Questions (English/General Knowledge) | 4.00 PM |
| Daily Current Affairs Updates | 5.00 PM |
| SBI PO/IBPS Clerk Mains – Reasoning | 6.00 PM |
| SBI PO/IBPS Clerk Mains – Quantitative Aptitude | 7.00 PM |
| SBI PO/IBPS Clerk Mains – English Language | 8.00 PM |
