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1) The ratio of age of Subash five years ago to age of Dinesh five years ago is 2: 3. The ratio of age of Dinesh five years hence to age of Naveena five years hence is 8: 9. If Naveena is 15 years elder than Subash, find the present age of Dinesh.
A.25 years
B.30 years
C.35 years
D.40 years
E.20 years
2) 4 years ago, the ratio of 1/2 of Richa’s age at that time and 4 times of Rahul’s age at that time was 1: 2. 6 years hence, 1/3 of Richa’s age at that time will be less than Rahul’s age at that time by 3 years. What is the Rahul’s present age?
A.15 years
B.20 years
C.25 years
D.24 years
E.30 years
3) Ratio of the ages of A and B is 4:1 and the present age of C is 20% more than the average ages of A and B. If the difference between the ages of A and C is 12 years, then find the average ages of A, B and C together?
A.30 years
B.28 years
C.32 years
D.Cannot be determined
E.None of these
4) Ratio of the present ages of A and B is 5:4 and the ratio of the ages of C and D is 6:7. If the average of difference between the ages of A and B and the difference between the ages of C and D is 8.5 years and A is 14 years younger than C, then what is the present age of B?
A.40 years
B.32 years
C.48 years
D.28 years
E.None of these
5) Ratio of the ages of A, B and C is 16: 8: 1 and after 8 years the ratio of the ages of A and C is 6: 1. If the product of the ages of B and D is 640 years and the difference between the ages of D and E is 16 years, then E is older than D, what is the average ages of E and C?
A.18 years
B.20 years
C.24 years
D.22 years
E.None of these
6) The ratio of ages of Arul and Arun five years ago is 5: 4. The age of Arun 7 years hence is equal to one – third more than the age of Arul 6 years ago. Find the age of Hari whose present age is 10 more than the age of Arun.
A.25 years
B.30 years
C.40 years
D.32 years
E.35 years
7) Ratio of the ages of Arun and his father is 1:2 and the ratio of the ages of Arun’s father and mother at the time of his birth is 6:5. If Arun’s sister is 4 years younger than Arun and the ratio of Arun’s mother and his sister’s age after 12 years is 7:4. What is the present age of Arun’s father?
A.40 years
B.44 years
C.48 years
D.Cannot be determined
E.None of these
8) After 2 years the ratio of the ages of A and B is 4: 5 and 2 years ago the ages of A and C is 4:5. If the sum of the ages of B and C is 65 years, then what is sum of the ages of A, B and C?
A.91 years
B.88 years
C.85 years
D.82 years
E.None of these
9) Ratio of A’s age, 8 years after to present age of B is 3: 5 and B’s present age is 25% of C’s age after 15 years. After 4 years A’ age is 12.5% of D’s age after 4 years. If the sum of the ages of A, B, C and D after 1 year is 101, then what is the present age of B?
A.18 years
B.15 years
C.12 years
D.14 years
E.None of these
10) If the ratio of the present age of A and B and C and B is 2:3 and 4:3 respectively and the difference between the ages of C and D is 12 years. The sum of the ages of the present age of A and D’s age of after four years is 90 years. What is the present age of C?
A.40 years
B.30 years
C.20 years
D.Cannot be determined
E.None of these
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Answers :
1) Answer: C
Let the present age of Subash be x. Let the present age of Dinesh be y. Let the present age of Naveena be z.
By given data, Five years ago
(x – 5)/(y – 5) = 2/3;
3x – 15 = 2y – 10;
2y = 3x – 5 —- (1)
Five years hence,
(y + 5)/(z + 5) = 8/9
9y + 45 = 8z + 40
8z – 9y = 5 —- (2)
z – x = 15; z = x + 15 — (3)
Substitute (1) and (3) in (2)
8(x + 15) – (9/2) * (3x – 5) = 5;
8x + 120 – (27x/2) + (45/2) = 5
(11x/2) = 275/2
x = 25 years
y = 35 years
2) Answer: A
Let Richa’s present age be ‘x’ years
And Rahul’s present age be ‘y’ years
Now, (x – 4)/2/4(y – 4) = ½
(x – 4)/8(y – 4) = ½
2x – 8 = 8y – 32
2x – 8y = -24 — (1)
And, (y + 6) – 1/3(x + 6) = 3
 = >3y + 18 – x – 6 = 9
x – 3y = 3 —– (2)
Now, from equation I and II
y = 15 and x = 48
Therefore, Rahul’s present age = 15 years
3) Answer: C
A = 4x
B = x
C = 120/100 * (4x + x/2) = 3x
4x – 3x = 12
x = 12
A’s age = 4 * 12 = 48 years
B’s age = 12 years
C’s age = 3 * 12 = 36 years
Average = (48 + 36 + 12)/3 = 32 years
4) Answer: B
[(5x – 4x) + (7y – 6y)]/2 = 8.5
x + y = 17——-(1)
6y – 5x = 14 —-(2)
(2) + (1) * 5
11y = 99
y = 9 years
x = 8 years
B = 8 * 4 = 32 years
5) Answer: B
(16x + 8)/(x + 8) = 6/1
6x + 48 = 16x + 8
10x = 40
x = 4
B’s age = 8 * 4 = 32 years
B * D = 640
D = 20 years
E = 20 + 16 = 36 years
C’s age = 4 years
Average = (36 + 4)/2 = 20 years
6) Answer: E
Let x and y be the present ages of Arul and Arun respectively.
(x – 5)/(y – 5) = 5/4
4x – 20 = 5y – 25
5y – 4x = 5 ——- (1)
y + 7 = (4/3) * (x – 6)
3y + 21 = 4x – 24
4x – 3y = 45 ——- (2)
Adding two equations, 2y = 50; y = 25
So Hari age = 10 + 25 = 35
7) Answer: C
A – S = 4
A/F = ½
2A = F
(M + 12)/(S + 12) = 7/4
7S + 84 = 4M + 48
4M – 7S = 36
4M – 7(A – 4) = 36
4M – 7A + 28 = 36
4M – 7A = 8 ————(1)
(F – A)/(M – A) = 6/5
6M – 6A = 5F – 5A
6M – 5F = A
6M – 5(2A) = A
6M – 11A = 0 ————–(2)
(1) * 6 – (2) * 4
A = 24 years
F = 2 * 24 = 48 years
8) Answer: A
(A + 2)/(B + 2) = 4/5
4B + 8 = 5A + 10
4B – 5A = 2 —– (1)
A – 2/C – 2 = 4/5
4C – 8 = 5A – 10
5A – 4C = 2 ——— (2)
B + C = 65——– (3)
From (2) and (3)
(3) * 4 + (2)
5A + 4B = 262 ———- (4)
(4) + (1)
8B = 264
B = 33
C = 65 – 33 = 32
5A = 262 – 4 * 33
A = 26
Sum of A, B and C = 26 + 33 + 32 = 91
9) Answer: B
(A +8)/B = 3/5
B =25/100* (C +15)
(D+4)*12.5/100= (A +4)
5 A +40 = 3B
B =(5A +40)/3
B = 25/100 * (C +15)
(5A + 40)/3 = 1/4* (C+15)
20A +160 = 3C+45
(20A +115) = 3C
C = (20A + 115)/3
(D+4) *12.5/100 = (A +4)
(D +4)*1/8 = (A +4)
D +4 = 8A +32
D = 8A + 28
Total age of all four together after one year
(A +1)+ (C +1)+ (B +1)+ (D +1) = 101
A + B + C + D = 97
A +(20A +115)/3+(5A +40)/3+ (8A +28) = 97
52A = 291-239
A = 1
B = (5A + 40)/3
Present age of B = (5(1) + 40)/3
=15 years
10) Answer: D
Data inadequate.
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