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1) After 4 years, the ratio of the ages of A and B is 3:2 and the C’s age 5 years ago is 8 years less than the present age of B. Average of the ages of A, B and C together is 32 years 4 months. Find the present age of A?
A.40 years
B.44 years
C.48 years
D.52 years
E.None of these
2) Present age of A is 6 times the age of B 2 years ago. 4 years hence, A’s age will be 4 times the age of B at that time. What will be the age of B after 6 years?
A.19 years
B.11 years
C.18 years
D.17 years
E.None of these
3) Ratio of the ages of Anu to France is 5:4 and Ram is 4 years younger than Anu and Karthick is 6 years younger than Ram. If Karthick’s present age is 20 years, then the present age of Karthick is approximately what percent of the present age of France?
A.83%
B.86%
C.89%
D.78%
E.75%
4) The present ages of Arul and Arun is 7: 5 and after four years the ratio becomes 15: 11. What is the difference between the ages of Arul and Arun 5 years ago?
A.12 years
B.16 years
C.20 years
D.24 years
E.10 years
5) Ratio of the ages of A, B and C is 4: 5: 6 and the ratio of the ages of D and E is 3: 2. If the sum of the ages of C and D is 60 years and the ratio of the ages of B to E is 15: 8, then what is the average ages of A, B, C, D and E?
A.24 years
B.26 years
C.28 years
D.30 years
E.None of these
6) Ratio of present ages of A and B is 4: 5. Sum of the present age of D and A is 41. C is 2 years younger than B. Average of the present age of B, C and D is 21 years. Find the difference of D and C’s age.
A.3
B.5
C.7
D.9
E.None of these
7) The ratio of present ages of Ganesh and Prabha is 3: 2. Present age of Prabha is equal to the age of Ganesh 8 years ago. Find the sum of the ages of Ganesh and Prabha after 5 years?
A.38 years
B.42 years
C.46 years
D.50 years
E.None of these
8) The ratio of present ages of A and B is 5: 7. After 5 years, the ratio of ages of A and B will be 3: 4. Find the difference between their ages
A.10 years
B.12 years
C.14 years
D.8 years
E.None of these
9) Ratio of present age of Satish and Raju is 7: 6. Sum of the present age of Sweta and Satish is 54. Anu is 4 years younger than Raju. Average of present ages of Raju, Anu and Sweta is 23 1/3 years. Find the difference of Sweta and Anu’s age.
A.2
B.4
C.6
D.8
E.None of these
10) Ten years ago, the average of the ages of David, Hari and Kani is 34 years and after 6 years, the average ages of Hari and Kani is 53 years. Find the present age of David.
A.30 years
B.34 years
C.38 years
D.42 years
E.None of these
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Answers :
1) Answer: B
A’s age after 4 years = 3x
B’s age after 4 years = 2x
Present age of B = 2x – 4
C’s present age – 5 = 2x – 4 – 8
C’s present age = 2x – 7
A + B + C = 32(1/3) * 3 = 97
3x – 4 + 2x – 4 + 2x – 7 = 97
7x = 112
x = 16
A’s present age = 3 * 16 – 4 = 44 years
2) Answer: C
A = 6(B – 2)
A = 6B – 12
6B – A = 12 —-(i)
A + 4 = 4(B + 4)
A – 4B = 12 —-(ii)
Solving equation i and ii we get,
A = 60 years and B = 12 years
So after 6 yrs, age of B will be 12 + 6 = 18 years.
3) Answer: A
Present age of Karthick = 20 years
Present age of Ram = 20 + 6 = 26 years
Anu’s age = 26 + 4 = 30 years
Present age of France = 30 * 4/5 = 24 years
Required percentage = 20/24 * 100 = 83%
4) Answer: B
(7x + 4)/(5x + 4) = 15/11
75x + 60 = 77x + 44
2x = 16
X = 8
Arul age 5 years ago = (7 * 8) – 5 = 51
Arun age 5 years ago = (5 * 8) – 5 = 35
Difference = 51 – 35 = 16 years
5) Answer: B
Ratio of the ages of A, B, C, D and E = 12: 15: 18: 12: 8
18x + 12x = 60
30x = 60
x = 2
Required average = ((12 + 15 + 18 + 12 + 8) * 2)/5
= 26 years
6) Answer: C
A = 4x and B = 5x
C = 5x – 2 and D = 41 – 4x
Given, (5x + 5x – 2 + 41 – 4x)/3 = 21
=> x = 4
Required difference = D – C = 41 – 4x – 5x + 2 = 7
7) Answer: D
The ratio of present ages of Ganesh and Prabha = 3: 2 (3x, 2x)
Present age of Prabha = The age of Ganesh, 8 years ago
2x = 3x – 8
x = 8
Present age of Ganesh and Prabha = 24 and 16 years
Required Sum = 24 + 16 + 10 = 50 years
8) Answer: A
The ratio of present age of A and B = 5: 7 (5x, 7x)
After 5 years, the ratio will be = 3: 4
(5x + 5) / (7x + 5) = ¾
20x + 20 = 21x + 15
x = 5
Present ages of A and B is 25 years and 35 years respectively
Required difference = 35 – 25 = 10 years
9) Answer: C
Satish = 7x and Raju = 6x
Anu = 6x – 4 and Sweta + 7x = 54
Sweta = 54 – 7x
(6x + 6x – 4 + 54 – 7x)/3 = 23 1/3
=> x = 4
Swetha = 54 – 7x = 26 years
Anu = 6x – 4 = 20 years
Required difference = 26 – 20 = 6 years
10) Answer: C
David – 10 + Hari – 10 + Kani – 10 = 34 * 3
David + Hari + Kani = 132 years
Hari + 6 + Kani + 6 = 53 * 2
Hari + Kani = 94
David = 132 – 94 = 38 years
11) Three years ago, the ratio of the ages of A and B is 3:4 and the average of the ages of B and C after 4 years is 40 years. If after 9 years, A’s age is equal to the average ages of B and C, then what is the present age of C?
A.28 years
B.33 years
C.37 years
D.43 years
E.48 years
12) The average age of A, B, C and D is 42 years and the average ages of B, C and D is 28 years. If the sum of the ages of A and B is 144 years and after 10 years, the ratio of the ages of B to C is 7:3, then what is the present age of D?
A.8 years
B.7 years
C.12 years
D.5 years
E.None of these
13) Five years ago, the ratio of the ages of A to B is 2:1 and the present age of A is 20 years more than B. If C’s age is 20% more than the sum of the present age of A and B together, then what is C’s age after 8 years?
A.90 years
B.88 years
C.94 years
D.86 years
E.None of these
14) The respective ratio of the present ages of father to son is 7:3. Five years ago, the ratio of their ages was 5:2. Then what will be the son’s age, 10 years from now?
A.45 years
B.55 years
C.60 years
D.35 years
E.40 years
15) A’s age is 120% of B’s age and B’s age is 125% of C’s age. If the average of the ages of A, B and C is 50 years, the find 175% of C’s age?
A.70
B.80
C.60
D.50
E.None of these
16) Average of the ages of Sam, Shon, Surya and Sunil is 39 years. If the sum of the ages of Sam and Sunil is 78 years and the difference between the ages of Shon and Surya is 6 years. Ratio of the ages of Shon and Sunil is 3:2. If Shon is elder than Surya, what is the present age of Sam?
A.50 years
B.48 years
C.45 years
D.60 years
E.54 years
17) 6 years ago, the ratio of the ages of Shon and Sania is 4:5 and after 12 years, the ratio of the age of Shon to Sania will be 7:8. What is the ratio of the present age of Shon to Sania?
A.5:6
B.6:7
C.7:8
D.4:5
E.None of these
18) Three years hence, the ratio of Karthi and Janvi will be 7:5. The age of Karthi two years hence is equal to two times the age of Janvi 5 years ago. What is the present age of Karthi?
A.24 years
B.26 years
C.32 years
D.38 years
E.None of these
19) Ratio of the present ages of Ovi and Kavi is 4:5. The present age of Pooja is 60% of the present age of Kavi.Average of the ages of Ovi, Kavi and Pooja is 24 years, then find the sum of the present ages of Pooja and Ovi?
A.48 years
B.36 years
C.42 years
D.30 years
E.None of these
20) Five years ago, the ratio of the ages of A and B is 4: 5 and after 5 years, the ratio becomes 6: 7. What is the difference between the ages of A and B after 20 years?
A.5 years
B.4 years
C.3 years
D.8 years
E.None of these
Try Ages Questions For Online Mock Test
Answers :
11) Answer: C
(A – 3)/(B – 3)=3:4
4A – 12=3B – 9
4A – 3B=3
((B + 4) + (C + 4))/2=40
B + C=72
A’s age after 9 years=72/2=36 years
A’s present age=36 – 9=27 years
4 * 27 – 3B=3
B=35 years
C=72 – 35=37 years
12) Answer: E
A + B + C + D=42 * 4=168
B + C + D=28 * 3=84
A + B=144
A=168 – 84 = 84 years
B =144 – 84 = 60 years
C + D =168 – (84 + 60) = 24 years
After 10 years B’s age=60 + 10=70 years
C’s age after 10 years=70 * 3/70=30 years
Present age of C=30 – 10=20 years
D =24 – 20 = 4 years.
13) Answer: E
(A – 5)/(B – 5) = 2/1
A – 5 = 2B – 10
A – 2B = -5
A = B + 20
B + 20 – 2B=-5
B = 25
A = 25 + 20=45
C = 120/100 * (45 + 25)
= 84 years
After 8 years C’s age = 84 + 8=92 years
14) Answer: B
The respective ratio of the present ages of father to son is 7:3
Father’s age = 7x
Son’s age = 3x
Five years age, Father’s age = 7x-5
Son’s age = 3x-5
(7x – 5)/(3x – 5) = 5/2
14x – 10 = 15x – 25
x = 15
Son’s present age = 15 * 3=45 years
After 10years, the son’s age = 55 years
15) Answer: A
A=120B/100
A=6/5 * B
B=125/100 * C
B=5/4 * C
5A/6=5/4 * C
A/3=C/2
A=3C/2
3C/2 + 5/4 * C + C=50 * 3
6C + 5C + 4C=600
C=40 years
175% of C’s age=175/100 * 40
=70
16) Answer: A
Sam + Shon + Surya + Sunil=39 * 4=156
Sam + Sunil=78
Shon – Surya=6
Shon + Surya=156 – 78=78
2Shon=84
Shon=42 years
Sunil=2/3 * 42=28
Sam=78 – 28=50 years
17) Answer: A
(4x + 6 + 12)/(5x + 6 + 12) = 7/8
(4x + 18) * 8 = (5x + 18) * 7
32x + 144 = 35x + 126
3x = 18
x = 6 years
Preset age ratio of Shon to Sania= (4 * 6 + 6):(5 * 6 + 6)
= 30:36
=5:6
18) Answer: C
Three years hence, the ratio of Karthi and Janvi = 7:5(7x, 5x)
Present age of Karthi and Janvi = 7x – 3, 5x – 3
According to the question,
7x – 1 = 2*(5x – 8)
7x – 1 = 10x – 16
3x = 15
x = 5
The present age of Karthi = 7x – 3 = 35 – 3 = 32 years
19) Answer: C
Ovi’s present age = 4x
Kavi’s present age = 5x
Pooja = 60/100 * 5x = 3x
Sum of the ages of Ovi, Kavi and Pooja = 24 * 3 = 72
4x + 5x + 3x = 72
x = 6 years
Sum of the present age of Pooja and Ovi = 4x + 3x = 7x
= 7 * 6 = 42 years
20) Answer: A
The ratio of ages of A and B, 5 years ago = 4: 5 (4x, 5x)
(4x + 10)/(5x + 10) = 6/7
30x + 60 = 28x + 70
2x = 10
x = 5
A’s age after 20 years = 4 * 5 + 5 + 20 = 45
B’s age after 20 years = 5 * 5 + 5 + 20 = 50
Difference between A and B = 5 years
21) The ratio of the ages of Sachin and his father is 1 : 3 respectively. After 8 years, the ratio of their ages will be 3 : 7 respectively. Then find what will be the ratio of their ages 7 years ago?
A.5 : 11
B.9 : 41
C.11 : 23
D.12 : 25
E.None of these
22) After 2 years, Raj’s age will be 30% more than Rahul’s age. If the ratio of present ages of Rahul and Raj is 3: 4 respectively, then after how many years, Raj’s age will be 24% more than Rahul’s age?
A.5 years
B.9 years
C.7 years
D.8 years
E.6 years
23) After 6 years, the ratio of the ages of Dhoni, Harthick and Rohit is 6:4:7. If the product of the present ages of Harthick and Rohit is 648 years, then what is the present age of Dhoni?
A.24
B.30
C.36
D.18
E.42
24) Six years ago, the ratio of the ages of Kani and vani is 5:6. The age of Kani after 4 years is equal to the age of Vani 2 years ago. If the average of the present age of Vani, Kani and Veni is 41 years, then find the age of Veni after 5 years?
A.45 years
B.40 years
C.55 years
D.50 years
E.60 years
25) The present age of Balu is 23 years which is 15% more than the present age of Sankar. The ratio of present age of Sankar and Sanu is 4: 5 respectively. If Amol is 5 years elder than Sanu, then find the ratio of present ages of Sankar to Amol.
A.1: 2
B.2: 3
C.3: 4
D.4: 5
E.None of these
26) The average of the present age of Leela, Nila and Kani is 27 years. If the ratio of the ages of Nila and Kani after 9 years is 3:4 and the Leela is 9 years elder than Kani, then find the sum of the present age of Leela and Nila?
A.48
B.54
C.60
D.36
E.45
27) The ratio of present ages of Ram and Ravi is 15: 13 respectively and the average present ages of Ram, Ravi and Sanam is 23 years. When Rio joins them, then the average becomes 21 years. If Sanam is 2 years younger than Rio, find the ratio of the present ages of Ram and Rio.
A.1: 2
B.2: 1
C.2: 3
D.4: 1
E.None of these
28) Present age of Raman is 3 times the present age of Kamal. If after 6 years, Raman age will be 4 times the age of Kamal 6 years ago. Find the average of the present ages of Raman and Kamal?
A.60 years
B.56 years
C.74 years
D.48 years
E.None of these
29) P is 7 years older than Q and R’s present age is 5 years less than the double of Q’s present age. If R is 13 years older than P, then after 8 years, R’s age will be what per cent of P’s age?
A.133.33%
B.150%
C.125%
D.132.5%
E.137.5%
30) P’ present age is thrice the difference between Q’s present age and R’s present age. If R’s present age is 40% more than Q’s present age, then find the ratio of P’s present age to Q’s present age?
A.4: 3
B.5: 4
C.Cannot be determined
D.6: 5
E.5: 3
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Answers :
21) Answer: B
Let the age of Sachin = x
And the age of his father = 3x
So, according to the question,
(x + 8)/(3x + 8) = 3/7
7x + 56 = 9x + 24
9x – 7x = 56 – 24
2x = 32
x = 16
So, the age of Sachin before 7 year = 16 – 7 = 9 year
And the age of his father before 7 year = (16 × 3) – 7 = 41 year
Hence, the required answer = 9 : 41.
22) Answer: C
Let present ages of Rahul and Raj are ‘3x’ years and ‘4x’ years, respectively.
So,
(4x + 2) = (3x + 2) * (130/100)
40x + 20 = 39x + 26
x = 6
Rahul’s present age = 3 * 6 = 18 years
Raj’s present age = 4 * 6 = 24 years
Let after ‘t’ years Raj’s age will be 24% more than Rahul’s age.
So,
(24 + t) = (18 + t) * (124/100)
600 + 25t = 558 + 31t
t = 7
So, after 7 years, Raj’s age will 24% more than Rahul’s age.
23) Answer: B
(4x – 6) * (7x – 6) = 648
28x2 – 24x – 42x + 36 = 648
28x2 – 66x + 36 = 648
14x2 – 33x + 18 = 324
14x2 – 33x + 18 – 324 = 0
14x2 – 33x – 306 = 0
14x2 – 84x + 51x – 306 = 0
14x (x – 6) + 51(x – 6)= 0
(14x + 51) (x – 6) = 0
x = 6
Present age of Dhoni = 6 * 6 – 6 = 36 – 6 = 30 years
24) Answer: D
Vani + Kani + veni = 41 * 3 = 123
Present age of Kani = 5x + 6
Present age of Vani = 6x + 6
(5x + 6 + 4) = (6x + 6 – 2)
x = 6
Present age of Kani = 5 * 6 + 6 = 36 years
Present age of Vani = 6 * 6 + 6 = 42 years
Present age of Veni = 123 – 36 – 42 = 45
Veni age after 5 years = 45 + 5 = 50 years
25) Answer: B
Sankar = 23 / 1.15 = 20 years
Sanu = 20 * 5 / 4 = 25 years
Amol = 25 + 5 = 30 years
Required ratio = Sanu: Amol
= 20: 30 = 2: 3
26) Answer: B
Leela + Nila + Kani = 27 * 3 = 81
Nila + 9 = 3x
Kani + 9 = 4x
Leela – Kani = 9
Leela – (4x – 9) = 9
Leela = 9 + 4x – 9 = 4x
3x – 9 + 4x – 9 + 4x = 81
11x = 99
x = 9
Sum of the ages of Leela and Nila = 4 * 9 + (3 * 9 – 9)
= 54
27) Answer: B
Ram = 15x and Ravi = 13x
Sanam = 3 * 23 – 28x = 69 – 28x
Rio = 4 * 21 – 3 * 23 = 15 years
Sanam = 15 – 2 = 13 years
=> 69 – 28x = 13
=> x = 2
Ram = 15x = 30 years
Required ratio = Ram: Rio = 30: 15 = 2: 1
28) Answer: A
Let the present age of Raman = x years
And the present age of Kamal = y years
Now, x = 3y
So, according to the question,
(x + 6) = 4 × (y – 6)
x + 6 = 4y – 24
Put the value of x,
3y + 6 = 4y – 24
y = 30
So, the present age of Kamal = 30 years
And the present age of Raman = 3 × 30 = 90 years
This, the average age of both = (30 + 90)/2 = 60 years
29) Answer: D
Let Q’s present age = ‘x’ years
So, P’s present age = (x + 7) years
And R’s present age = (2x – 5) years
From the question:
2x – 5 – x – 7 = 13
x = 25
P’s present age = 25 + 7 = 32 years
P’s age after 8 years = 32 + 8 = 40 years
R’s present age = 2 * 25 – 5 = 45 years
R’s age after 8 years = 45 + 8 = 53 years
Required percentage = (53/40) * 100 = 132.5%
30) Answer: D
Let Q’s present age = ‘x’ years
So, R’s present age = 140% of ‘x’ = (7x/5) years
Let P’s present age = ‘y’ years
So,
y = 3 * [(7x/5) – x]
y = 3 * 2x/5
5y = 6x
y/x = 6/5
So, ratio of P’s present age to Q’s present age = 6: 5
31) Average ages of Anil, Mathavi and Merlin is 26 years. If the present age of Mathavi is two times of the age of Merlin 6 years ago and the present age of Anil is 12 years more than that of Mathavi, then what is the present age of Merlin?
A.12 years
B.18 years
C.15 years
D.22 years
E.24 years
32) The ratio of the ages of Vishva and Shalini is 7:4 and the ratio of the ages of Shamala and Shalini is 5:4. If Vishva is 36 years elder than Shamala, then find the average age of Vishva, Shalini and Shamala together?
A.88 years
B.92 years
C.96 years
D.82 years
E.None of these
33) After 6 years, the ratio of the ages of Arul to Karan is 7:6. The average age of Arul, Karan and Saran is 30 years. If the age of Saran is 12 years younger than Arul, then find the present age of Karan?
A.24 years
B.30 years
C.36 years
D.42 years
E.18 years
34) The sum of the present ages of P and Q is 70 years. If the ratio of the age of P 4 years ago and the age of Q 4 years hence is 3: 4 respectively, then find the ratio of age of P 6 years hence to the age of Q 6 years ago.
A.1: 2
B.2: 1
C.3: 4
D.4: 3
E.None of these
35) Sum of the ages of A and B five years hence is 60 and the ratio between the age of A, 4 years ago and age of B, 4 years hence is 9:16, find the present age of B?
A.22 years
B.28 years
C.24 years
D.26 years
E.27 years
36) 2 years ago, Age of Naren was four times the age of Sam 5 years ago. If the present age of Naren is 150% more than the present age of Sam, then what is the age of Sam?
A.6 years
B.8 years
C.10 years
D.12 years
E.None of these
37) 8 years ago, the ratio of the ages of Sureka and Francis is 7:6. Sureka’s age 6 years ago is 25% less than the age of Francis after 8 years. If the average age of Sureka, Francis and Dev is 32 years, find the present age of Dev?
A.22 years
B.24 years
C.26 years
D.28 years
E.20 years
38) After 8 years, the ratio of the ages of Pinky and Blacky is 2:3. 4 years ago, the age of Pinky is half of the present age of Blacky. If the present age of Whitey is 25% more than the sum of the present age of Pinky and Blacky, then find the age of Whitey after 5 years?
A.75 years
B.80 years
C.85 years
D.90 years
E.95 years
39) Present ages of Amol and Sanu are in the ratio of 4: 5 respectively. After 5 years, ages of Sam and Sanam will be in the ratio of 6: 7 respectively. Present age of Sanam is 5 years elder than that of Sanu. Find the age of Sanu, if the present average age of Amol, Sanu, Sam and Sanam is 25 years.
A.20 years
B.25 years
C.30 years
D.35 years
E.None of these
40) Ratio of the ages of Rani and Vani is 4:5 and after 5 years, the ratio of the ages of Vani and Sana is 3:4. If the difference between the ages of Sana and Rani is 15 years, then find the average age of Vani and Sana?
A.25 years
B.30 years
C.35 years
D.40 years
E.45 years
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Answers :
31) Answer: B
Anil + Mathavi + Merlin = 26 * 3 = 78
Mathavi = 2 * (Merlin – 6)
Anil – Mathavi = 12
Anil = 12 + 2Merlin – 12
Merlin + 2Merlin – 12 + 2Merlin = 78
5 Merlin = 90
Merlin = 18 years
32) Answer: C
The ratio of the ages of Vishva, Shalini and Shamala = 7:4:5
7x – 5x = 36
x = 18
Required average = (16 * 18)/3
= 96 years
33) Answer: B
Arul + Karan + Saran = 30 * 3 = 90
Arul – Saran = 12
Arul = 7x – 6
Karan = 6x – 6
Saran = 7x – 6 – 12
7x – 6 + 6x – 6 + 7x – 18 = 90
20x = 120
x = 6
Present age of Karan = 36 – 6 = 30 years
34) Answer: D
Let the age of P = x. Age of P and Q = 70
Age of Q = 70 – x
(x – 4): (70 – x + 4) = 3: 4
=> x = 34
Required ratio = (x + 6): (70 – x – 6)
= 40: 30 = 4: 3
35) Answer: B
Let present age of A = a, present age of B =b
It is given that, a+5+b+5=60
a+b=50
It is also given that,
a-4/b+4 = 9/16
16a-64= 9b+36
16a-9b =100
By solving the above equations we get, a=22, b=28
Present age of B=28 years
36) Answer: D
Present age of Sam = x
=> Age of Sam 5 years ago = x – 5
Age of Naren 2 years ago = 4x – 20
Present age of Naren = 4x – 20 + 2 = 4x – 18
4x – 18 = 250/100 * x
=> x = 12 = Age of Sam
37) Answer: D
S = 7x + 8
F = 6x + 8
7x + 8 – 6 = 75/100 * (6x + 8 + 8)
28x + 8 = 18x + 48
x = 4
Sureka = 7 * 4 + 8 = 36
Francis = 6 * 4 + 8 = 32
Sureka + Francis + Dev = 32 * 3 = 96
Dev = 96 – 36 – 32 = 28
38) Answer: C
Let P be the present age of Pinky, B be the present age of Blacky and W be the present age of Whitey
P = 2x – 8
B = 3x – 8
P – 4 = B/2
2P – 8 = B
2 * (2x – 8) – 8 = 3x – 8
4x – 16 – 8 = 3x – 8
x = 16
P = 32 – 8 = 24
B = 48 – 8 = 40
W = (24 + 40) * 125/100 = 80
Required answer = 80 + 5 = 85 years
39) Answer: B
Amol = 4x and Sanu = 5x
Sanam = 5 + 5x
Sanam after 5 years = 5 + 5x + 5 = 5x + 10
Sam after 5 years = 6/7 * (5x + 10) = 30x/7 + 60/7
Sam’s present age = 30x/7 + 60/7 – 5 = 30x/7 + 25/7
4x + 5x + 5x + 5 + 30x/7 + 25/7 = 25 * 4
=> 128x = 640
=> x = 5
Sanu = 5x = 25 years
40) Answer: B
Rani = 4x
Vani = 5x
Sana = [4/3 * (5x + 5)] – 5 = 20x/3 + 20/3 – 5
Sana – Rani = 15
(20x/3 + 20/3 – 5) – 4x = 15
20x – 12x = 15*3 – 5
20x – 12x = 40
x =5
Vani = 5*5 = 25
Sana = 4/3 * (5 * 5 + 5) – 5 = 35
Required average = (25 + 35)/2 = 30 years
41) After 10 years, the ratio of age of Ganga and Senthil will be 13: 15 respectively. If the average of present ages of Ganga and Senthil is 18 years and the ratio of present ages of Ganga and Saravanan is 8: 9, then find the present age of Saravanan.
A.12 years
B.16 years
C.18 years
D.20 years
E.None of these
42) 10 years ago the age of A is the age B 4 years ago and Age of C after 7 years is 15years. If Present average age of them is 16years, then find the sum of the ages of A and C after 3 years?
A.32 years
B.37 years
C.27 years
D.42 years
E.47 years
43) After eight years the age of A is 28.56% more than its present age and two years before the age ratio of B and C is 5:6.If Age of B after 7 years is 40% more than that of A then find the present age of C?
A.54 years
B.48 years
C.45 years
D.50 years
E.58 years
44) 4 years ago, the average age of A, B and C was 48 years and the sum of age of A and B after 6 years is 100. Find the present age of C.
A.80 years
B.49 years
C.52 years
D.68 years
E.None of these
45) 5 years hence, the ratio of age of Anusha and Kavin is 3: 4. 8 years ago, the ratio of age of Anusha and Kavin is 2: 7. Then find the age of Kavin, 10 years hence?
A.32 years
B.30 years
C.23 years
D.27 years
E.None of these
46) Ratio of the ages of A and B is 3: 2 and the ratio of the ages of A after 5 years and B, 2 years ago is 2: 1. What is the average age of A and B after 10 years?
A.22.5 years
B.36.5 years
C.28.5 years
D.32.5 years
E.None of these
47) The ratio of the ages of Anusha to Bavi after 6 years is 4:5 and the difference between the ages of Anusha and Bavi after 12 years ago is 9 years. If the ratio of the ages of Anusha to Ravi is 3:4, then what is Ravi’s age after 5 years?
A.45 years
B.53 years
C.41 years
D.57 years
E.65 years
48) The ratio of the present ages of Divya to that of Sara is 9: 11. Siva is 2 years older than Sara. Siva’s age after 9 years will be 44 years. What is the present age of Divya’s mother, who is 26 years older than Divya?
A.44 years
B.53 years
C.46 years
D.43 years
E.None of these
49) The current age of Naren is 10% more than that of Nakul. Ten years ago, the difference between their ages was 3 years. Find the current age of Nakul.
A.15
B.20
C.25
D.30
E.None of these
50) Average age of (k – 14) students of a class is 18 years. If the age of 53 years old teacher is included, then average age of group in increased by 1 year.Find (k – 10.5) % of 7500.
A.2712.50
B.2812.50
C.2912.25
D.2812.25
E.None of these
Try Ages Questions For Online Mock Test
Answers :
41) Answer: C
Present age of Ganga = 13x – 10
Present age of Senthil = 15x – 10
(13x – 10) + (15x – 10) = 18 * 2
=> x = 2
Ganga’s age = 16 years
Age of Saravanan = 9/8 * 16 = 18 years
42) Answer: B
Let present age of A =a, B=b, C=c
It is given that,
(a-10)=(b-4)
(a-b) =6
Age of C after 7 years
c+7 =15
Present age of C =15-7 =8
Average age of them =16 years
Total age of them = 16*3 =48years
a+ (a-6)+8 =48
2a -6 = 40
a=23years
Required sum = 23+3 + 8+3 = 37 years
43) Answer: D
Let present age of A =7x
After 8 years age of A = 128.56% of 7x = 9x
7x+8 =9x
x=4
Present age of A =7x =28 years
Age of B after 7 years = 140% of (28+7) = 49
Present age of B = 49 – 7 =42 years
Age of B before 2 years = 40
Age of C before 2 years = (40/5) * 6=48 years
Present age of C =50years
44) Answer: D
Total age of (A + B + C) 4 years ago = 48 x 3 = 144
Total of present age of (A + B + C) = 144 + 12 = 156
But, according to the question (A + B) after 6 years = 100
So, sum of present age of (A + B) = 100 – 12 = 88 years
Thus, the present age of C = 156 – 88 = 68 years.
45) Answer: E
5 years hence, the ratio of age of Anusha and Kavin = 3: 4 (3x, 4x)
8 years ago, the ratio of age of Anusha and Kavin = 2: 7
According to the question,
(3x – 13)/(4x – 13) = (2/7)
21x – 91 = 8x – 26
13x = 65
x = 5
The age of Kavin, 10 years hence = 4x + 5 = 25 years
46) Answer: D
(3x + 5)/(2x – 2) = 2/1
4x – 4 = 3x + 5
x = 9
A’s age = 3 * 9 = 27 years
B’s age = 2 * 9 = 18 years
Required average = (27 + 18 + 20)/2 = 32.5 years
47) Answer: A
5x – 4x = 9 years
x = 9
Anusha’s age after 6 years = 4 * 9 = 36 years
Present age of Anusha = 36 – 6 = 30 years
Present age of Ravi = 4/3 * 30 = 40 years
Ravi’s age after 5 years = 40 + 5 = 45 years
48) Answer: B
Siva’s present age = 44 – 9 = 35 years
Sara’s present age = 35 – 2 = 33 years
From the ratio = 9: 11, we get Divya’s age = 27 years
Present age of Divya’s mother = 27 + 26 = 53 years
49) Answer: D
Current age of Nakul = x years
Current age of Naren = 1.1x years
1.1x – x = 3
=> x = 30 years = Age of Nakul
50) Answer: B
Sum of ages of all students = 18 x (k – 14) = 18k – 252
When teacher is included, sum of ages of all = 19 x (k – 14 + 1) = 19k – 247
According to question
(19k – 247) – (18k – 252) = 53
k = 53 – 5 = 48
Required value = (48 – 10.5) % of 7500 = 2812.5
51) 2 years ago, Age of Naren was four times the age of Sam 5 years ago. If the present age of Naren is 150% more than the present age of Sam, then what is the age of Sam?
A.6
B.8
C.10
D.12
E.None of these
52) The sum of the present ages of P and Q is 70 years. If the ratio of the age of P 4 years ago and the age of Q 4 years hence is 3: 4 respectively, then find the ratio of age of P 6 years hence to the age of Q 6 years ago.
A.1: 2
B.2: 1
C.3: 4
D.4: 3
E.None of these
53) Average age of Anil, Mathavi and Merlin is 26 years. If the present age of Mathavi is two times of the age of Merlin 6 years ago and the present age of Anil is 12 years more than Mathavi, then what is the present age of Merlin?
A.12 years
B.18 years
C.15 years
D.22 years
E.24 years
54) The sum of the present ages of mother and daughter is 51 years. Six years ago, mother’s age is 12 times of the age of daughter at that time and the ratio of the age of mother to father is 14:15, then find the difference between the age of Daughter and father.
A.30 years
B.32 years
C.33 years
D.27 years
E.36 years
55) Yuvi’s present age is 33(1/3)% of the sum of the present age of Som and Ramya. If the present age of Som is 25% more than the present age of Ramya, then what is the ratio of the present age of Yuvi, Ramya and Som?
A.1:2:3
B.2:3:4
C.3:4:6
D.5:6:7
E.None of these
56) Four years hence, Mala will be 5 times of her daughter’s age and four years ago, the ratio of the age of Mala and her daughters is 6:1. What is the present age of Mala’s daughter?
A.32
B.36
C.48
D.28
E.24
57) The average ages of Amala and Vimala is 28 years. If the ratio of the ages of Amala 12 years hence and the age of Vimala 8 years ago is 3:2, then find the present age of Amala?
A.22
B.20
C.26
D.28
E.24
58) Ratio of the ages of A and B is 7:8 and the ratio of the ages of B and C is 5:6. If the average age of A, B, C and D is 40 years, then find the present age of D?
A.20
B.35
C.25
D.19
E.Cannot be determined
59) 5 years ago, the average age of Chinnu and Nani is 23. At present, the ratio between their ages is 15:13. Find the Chinnu age after 10 years?
A.50 years
B.45 years
C.60 years
D.40 years
E.35 years
60) The present age of a father is 100% more than the present age of his son. 10 years ago, the age of father is 200% more than as that of his son. What will be the ratio of the ages of father and son after 15 years from now?
A.9:5
B.11:7
C.10:7
D.8:3
E.12:7
Try Ages Questions For Online Mock Test
Answers :
51) Answer: D
Present age of Sam = x
=> Age of Sam 6 years ago = x – 5
Age of Naren 2 years ago = 4x – 20
Present age of Naren = 4x – 20 + 2 = 4x – 18
4x – 18 = 250/100 * x
=> x = 12 = Age of Sam
52) Answer: D
Let the age of P = x. Age of P and Q = 70
Age of Q = 70 – x
(x – 4): (70 – x + 4) = 3: 4
=> x = 34
Required ratio = (x + 6): (70 – x – 6)
= 40: 30 = 4: 3
53) Answer: B
Anil + Mathavi + Merlin = 26 * 3 = 78
Mathavi = 2 * (Merlin – 6)
Anil – Mathavi = 12
Anil = 12 + 2Merlin – 12
Merlin + 2Merlin – 12 + 2Merlin = 78
5 Merlin = 90
Merlin = 18 years
54) Answer: E
M + D = 51—–(1)
M – 6 = 12 * (D – 6)
M – 6 = 12D – 72
12D – M = 66—–(2)
13D = 117
D = 9
M = 51 – 9 = 42
F = 42 * 15/14 = 45
Difference = 45 – 9 = 36 years
55) Answer: E
Som = 125/100 * Ramya
Som/Ramya = 5/4
(5K + 4K) * 100/300 = Yuvi
Yuvi = 3k
Required ratio = 3K:4K:5K
= 3:4:5
56) Answer: B
M + 4 = 5(D + 4)
M + 4 = 5D + 20
M – 5D = 16 —–(1)
(M – 4)/(D – 4) = 6/1
6D – 24 = M – 4
6D – M = 20 ——-(2)
D = 36
57) Answer: E
Amala + Vimala = 28 * 2 = 56——(1)
(Amala + 12)/(Vimala – 8) = 3/2
3Vimala – 24 = 2Amala + 24
3Vimala – 2Amala = 48—–(2)
From (1) and (2)
Vimala = 32
Amala = 56 – 32 = 24
58) Answer: E
Ratio of the ages of A, B and C = 35:40:48
35x + 40x + 48x + D = 40 * 4
We can’t find the answer
59) Answer: D
5 years ago, their average age is 23
therefore total age = 23*2 = 46
present age of Chinnu and Nani = 46+5+5 = 56
Chinnu age = 15/28*56 = 30
after 10 years = 30+10 = 40 years
60) Answer: B
Present age of son = x
Present age of father = 200/100 * x = 2x
(x – 10)/(2x – 10) = 100/300
2x – 10 = 3x – 30
x = 20
Present age of father = 2 * 20 = 40
Required ratio = (40 + 15):(20 + 15)
= 55:35
= 11:7
This post was last modified on February 3, 2024 12:52 pm