Dear Aspirants, Quantitative Aptitude plays a crucial role in Banking and all other competitive exams. To enrich your preparation, here we have provided New Pattern Aptitude Questions for IBPS Clerk Mains. Candidates those who are going to appear in IBPS Clerk Mains can practice these questions daily and make your preparation effective.
[WpProQuiz 4940]Direction (1 – 5): Study the following information carefully and answer the given questions:
The table shows percentage of work done by each persons and time taken (Days) by each person to do that work.
1) A and B working alternatively starting with A and work for 28 days after that both are left and then the remaining work completed by C and E. If C and E work alternatively starting with C then how many days remaining work will be completed?
a) 17(1/2) days
b) 18(1/2) days
c) 20(1/2) days
d) 13(1/2) days
e) None of these
2) If D work with 25 % more efficiency for 4 days after that D left and then for 12 days B work with 40 % less efficiency and A work with 50% more efficiency together. Then the remaining work completed by another person F in 15 days. Find in how many days F can complete the whole work alone?
a) 120 days
b) 180 days
c) 140 days
d) 160 days
e) None of these
3) If E work with 25% more efficiency to finish the work and F takes 75% of the days which E takes to finish 125% of work. Efficiency of G is twice of E, in how many days will the work be completed if E is worked with F and G on alternative days starting with F?
a) 16(1/8) days
b) 14(1/8) days
c) 7(1/8) days
d) 9(1/8) days
e) None of these
4) Five persons A, B, C, D and E work alternatively in such a way that, on first day, A and B work together and on second day C, D and E work together, find in how many days whole work will be completed?
a) 11(1/2) days
b) 10(1/2) days
c) 12(1/2) days
d) 9(1/2) days
e) None of these
5) A, B, C and E completed a piece work costing Rs. 40600. If their daily wages are in the ratio of 5 : 7 : 12 : 6, then what amount will be received by A and E together?
a) Rs. 24000
b) Rs. 30000
c) Rs. 25000
d) Rs. 28000
e) None of these
Directions (6 – 10): The questions below are based on the given Series-I. The series-I satisfy a certain pattern, follow the same pattern in Series-II and answer the questions given below.
6)
a) 850
b) 900
c) 920
d) 825
e) 720
7)
a) 202
b) 196
c) 144
d) 112
e) 214
8)
a) 65
b) 73
c) 87
d) 53
e) 51
9)
a) 210
b) 187
c) 193
d) 171
e) 157
10)
a) 524
b) 612
c) 670
d) 718
e) 656
Answers:
Directions (1-5):
1) Answer: a)
Number of days A to complete the whole work alone=18*100/30=60 days
Number of days B to complete the whole work alone=15*100/60=25 days
Number of days C to complete the whole work alone=5*100/25=20 days
Number of days E to complete the whole work alone=20*100/40=50 days
A and B total unit of work = 300 unit
A complete the work in first day = 5 units
B complete the work in second day = 12 units
Total work completed after two days = 5 + 12 = 17 units
Both are working 14 and 14 days respectively
Work completed after 28 days = (5*14) + (12*14) = 238
Remaining work = 300 – 238 = 62
C and E total units = 100
First day complete C = 5 units
Second day complete E = 2 units
16 days = 5*8 + 2*8 = 56 unit complete after 16 days
Remaining unit = 6
17th day C complete 5 units of work
18th day E complete = 1/2 days
Total time = 16+1+1/2 = 17(1/2) days
2) Answer: c)
Number of days D to complete the whole work alone = 4*100/20 = 20 days
D 25% more efficiency = 20*100/125 = 16 days
D Work for only 4 days = 4/16 = 1/4
Remaining work = 3/4
Number of days A to complete the whole work alone =18*100/30 = 60 days
A 50% more efficiency = 60*100/150 = 40 days
Number of days B to complete the whole work alone = 15*100/60 = 25 days
B 40% less efficiency = 25*140/100 = 35 days
A+B work for 12 days complete the work = 12*(1/40 + 1/35)
= 12* [(7+8)/280]
= 3 * [15/70]
= 9/14
Remaining work = ¾ – 9/14 = 3/28
F completed 3/28 work in 15 days.
Whole work completed by F = (28/3)*15 = 140 days
3) Answer: b)
Number of days E to complete the whole work alone=20*100/40=50 days
E takes 25% more efficiency=50*(100/125) = 40days
F complete the whole work=40*(75/100)*(100/125) = 24 days
As efficiency of G is twice that of E so time taken by G = 20 days
LCM of (40, 24, 20) = 120
E complete = 3 units per day
F = 5 units
G = 6 units
First day work E and F together = 3 + 5 = 8 units
Second day E and G = 3 + 6 = 9 units
Two days work = 8+9 = 17 units
After 14 days work = 17*7 = 119 units
Remaining work = 1 unit, which is to be completed by E and F in 1/8 days
Total time = 14 + 1/8 = 14(1/8) days
4) Answer: a)
Number of days A to complete the whole work alone=18*100/30=60days
Number of days B to complete the whole work alone=15*100/60=25 days
Number of days C to complete the whole work alone=5*100/25=20 days
Number of days D to complete the whole work alone=4*100/20=20 days
Number of days E to complete the whole work alone=20*100/40=50 days
LCM of (60, 25, 20, 20 and 50) = 300
A complete =5 units
B = 12 units
C = 15 units
D = 15 units
E = 6 units
First day work of A and B = 5 + 12 = 17 units
Second day work C, D and E = 15 + 15 + 6 = 36 units
First two days work = 17 + 36 = 53 units
First 10 days work = 53*5 = 265 units
Remaining =300 – 265 = 35
11th day = 17 units
Remaining work = 35 – 17 = 18 units
12th day = 18/36 = 1/2
Total work = 11(1/2) days
5) Answer: a)
Number of days A to complete the whole work alone=18*100/30=60days
Number of days B to complete the whole work alone=15*100/60=25 days
Number of days C to complete the whole work alone=5*100/25=20 days
Number of days E to complete the whole work alone=20*100/40=50 days
Ratio of wages = 5*60 : 7*25 : 12*20 : 6*50
= 300 : 175 : 240 : 300 = 60 : 35 : 48 : 60
(A + E)’s wages = 40600*(120/203) = Rs. 24000
Directions (6-10):
6) Answer: a)
Series I pattern:
1549 – 192 (361) = 1188
1188 – 172 (289) = 899
899 – 152 (225) = 674
674 – 132 (169) = 505
505 – 112 (121) = 384
Series II pattern:
2015 – 192 (361) = 1654
1654 – 172 (289) = 1365
1365 – 152 (225) = 1140
1140 – 132 (169) = 971
971 – 112 (121) = 850
7) Answer: d)
Series I pattern:
14 * 2 + 2 = 28+2 = 30
30 * 2 + 4 = 60 + 4 = 64
64 * 2 + 8 = 128 + 8 = 136
136 * 2 + 16 = 272 + 16 = 288
288 * 2 + 32 = 576 + 32 = 608
Series II pattern:
3 * 2 + 2 = 6 + 2 = 8
8 * 2 + 4 = 16 + 4 = 20
20 * 2 + 8 = 40 + 8 = 48
48 * 2 + 16 = 96 + 16 = 112
112 * 2 + 32 = 224 + 32 = 256
8) Answer: b)
Series I pattern:
137 + 15 = 152
152 + 20 = 172
172 + 25 = 197
197 + 30 = 227
227 + 35 = 262
Series II pattern:
73 + 15 = 88
88 + 20 = 108
108 + 25 = 133
133 + 30 = 163
163 + 35 = 198
9) Answer: c)
Series I pattern:
Series II pattern:
10) Answer: d)
Series I pattern:
153 – 1 = 3374
133 – 3 = 2194
113 – 5 = 1326
93 – 7 = 722
73 – 9 = 334
53 – 11 = 114
Series II pattern:
193 – 1 = 6858
173 – 3 = 4910
153 – 5 = 3370
133 – 7 = 2190
113 – 9 = 1322
93 – 11 = 718
Daily Practice Test Schedule | Good Luck
| Topic | Daily Publishing Time |
| Daily News Papers & Editorials | 8.00 AM |
| Current Affairs Quiz | 9.00 AM |
| Current Affairs Quiz (Hindi) | 9.30 AM |
| NIACL AO Prelims – Reasoning | 10.00 AM |
| NIACL AO Prelims – Quantitative Aptitude | 11.00 AM |
| Vocabulary (Based on The Hindu) | 12.00 PM |
| NIACL AO Prelims – English Language | 1.00 PM |
| SSC Practice Questions (Reasoning/Quantitative aptitude) | 2.00 PM |
| IBPS Clerk – GK Questions | 3.00 PM |
| SSC Practice Questions (English/General Knowledge) | 4.00 PM |
| Daily Current Affairs Updates | 5.00 PM |
| SBI PO/IBPS Clerk Mains – Reasoning | 6.00 PM |
| SBI PO/IBPS Clerk Mains – Quantitative Aptitude | 7.00 PM |
| SBI PO/IBPS Clerk Mains – English Language | 8.00 PM |
This post was last modified on January 19, 2019 6:21 pm