IBPS Clerk Prelims 2018 – Quantitative Aptitude Questions Day-33

Dear Readers, Bank Exam Race for the Year 2018 is already started, To enrich your preparation here we have providing new series of Practice Questions on Quantitative Aptitude – Section. Candidates those who are preparing for IBPS Clerk Prelims 2018 Exams can practice these questions daily and make your preparation effective.

Click here to View Quantitative Aptitude Questions in Hindi

Directions (Q. 1 – 5): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer as,

a) If x > y

b) If x ≥ y

c) If x < y

d) If x ≤ y

e) If x = y or no relation can be established between x and y

1)

I) x³ = ∛3112136 – 652 ÷ 4 + 9²

II) y² = 16

2)

I) 3x – 4y = 3

II) 5x – 2y = -9

3)

I) x² + 21x – 72 = 0

II) y² + y – 56 = 0

4)

I) 4x² – 7x – 36 = 0

II) 3y² + 22y + 19 = 0

5)

I) √x ÷ ∛13824 = ∜6561 ÷ 72

II) y² – 13y + 42 = 0

Directions (6-10): Read the following passage carefully and answer the given questions.

In a shop, there are four different colour water bottles viz. Pink, Green, Yellow and Red placed in three rows viz. R1, R2 and R3. Number of bottles in each row is same.

• Number of pink bottles in R1 is one more than the number of yellow bottles and green bottles in R1 and R3 respectively.
• Number of yellow bottles in R1 is 5 less than the green bottles, yellow bottles and red bottles in R1, R2 and R3 respectively.
• The ratio of the number of green bottles in R2, red bottles in R3 and pink bottles in R3 is 1: 2: 1.
• Number of red bottles in R2 is 90% of number of red bottles in R3.
• The ratio of the number of pink bottles in R2, yellow bottles in R3 and red bottles in R1 is 8: 9: 7.
• Total number of red bottles in R1 and R3 together is 41 from that R1 has one bottle more than R3.

6) If two bottles taken from R1, what is the probability of getting at least one pink bottle?

a) 251/639

b) 125/639

c) 254/639

d) 173/639

e) 215/639

7) What is the ratio between the number of red bottles and number of green bottles in all the three rows?

a) 51: 62

b) 59: 45

c) 49: 51

d) 63: 48

e) None of these

8) Number of pink bottles in R1 and R2 together is approximately what percentage more/less than the number of yellow bottles in R2?

a) 80%

b) 120%

c) 100%

d) 75%

e) 50%

9) Find the average number of green bottles in all the given rows?

a) 15

b) 12

c) 9

d) 18

e) 21

10) What is the difference between the total pink bottles and total yellow bottles?

a) 8

b) 10

c) 5

d) 15

e) 12

Answers :

Direction (1-5) :

1) Answer: b)

I) x³ = ∛3112136 – 652 ÷ 4 + 9²

X³ = 146 – (652/4) + 81

X³ = 146 – 163 + 81

X³ = 64

X = 4

II) y² = 16

Y = 4, -4

X ≥ y

2) Answer: e)

3x – 4y = 3 –> (1)

5x – 2y = -9 –> (2)

By solving the equation (1) and (2), we get,

X = – 3, y = -3

X = y

3) Answer: e)

I) x² + 21x – 72 = 0

(x + 24) (x – 3) = 0

X = -24, 3

II) y² + y – 56 = 0

(y + 8) (y – 7) = 0

Y = -8, 7

Can’t be determined

4) Answer: e)

I) 4x² – 7x – 36 = 0

4x² – 16x + 9x – 36 = 0

4x (x – 4) + 9(x – 4) = 0

(4x + 9) (x – 4) = 0

X = -9/4, 4 = -2.25, 4

II) 3y² + 22y + 19 = 0

3y² + 3y + 19y +19 = 0

3y (y + 1) + 19(y + 1) = 0

(3y + 19) (y + 1) = 0

Y = -19/3, -1 = -6.33, -1

Can’t be determined

5) Answer: a)

I) √x ÷ ∛13824 = ∜6561 ÷ 72

√x ÷ 24 = 9/72

√x = (9/72)*24 = 3

x = 9

II) y² – 13y + 42 = 0

(y – 7) (y – 6) = 0

Y = 7, 6

X > y

Directions (6-10):

Number of pink bottles in R1 = x

Number of yellow bottles in R1 = x-1

Number of green bottles in R3 = x-1

Number of green bottles in R1 = (x-1) +5 = x+4

Number of yellow bottles in R2 = (x-1) +5 = x+4

Number of red bottles in R3 = (x-1) +5 =x+4

Ratio of the number of green bottles in R2, red bottles in R3 and pink bottles in R3 = 1: 2: 1 = y: 2y: y

Number of red bottles in R3 = x+ 4 = 2y => y = (x+4)/2

Number of green bottles in R2 = y = (x+4)/2

Number of pink bottles in R3 = y = (x+4)/2

Number of red bottles in R2 = 90/100 * Number of red bottles in R3

= 90/100 * (x+4)

= 9/10 * (x+4)

Ratio of the number of pink bottles in R2, yellow bottles in R3 and red bottles in R1 = 8: 9: 7 = 8z: 9z: 7z — (1)

Number of red bottles in R1 and R3 = 41 — (2)

Number of red bottles in R1 = Number of red bottles in R3 + 1

Number of red bottles in R1 – Number of red bottles in R3 = 1 — (3)

Solve the equation (2) and (3), we get

Number of red bottles in R1 = 21 and Number of red bottles in R3 = 20

Substitute the value in equation (1)

Number of red bottles in R1 = 21 = 7z => z = 3

Number of pink bottles in R2 = 8z = 8* 3 = 24

Number of yellow bottles in R3 = 9z = 9* 3 = 27

Number of red bottles in R3 = 20 = x+4 => x = 20-4

x=16

Total number of bottles in each row is 72.

6) Answer: c)

Required probability = 1 – Probability of none is pink

= 1 – 56c₂/72c₂

= 1 – (56*55/72*71)

= 1 – 385/639

= (639-385)/639

= 254/639

7) Answer: b)

Required ratio = (21+18+20): (20+10+15)

= 59: 45

8) Answer: c)

Required percentage = [(16+24)-20]/20 * 100

= 20/20 * 100 = 100%

9) Answer: a)

Required average = (20+10+15)/3

= 45/3 = 15

10) Answer: e)

Required difference = (15+20+27) – (16+24+10)

= 62 – 50 = 12

Kindly watch this video to know about Must Attempt Top 5 Arithmetic Problems for IBPS Clerk Prelims 2018

Daily Practice Test Schedule | Good Luck

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