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Directions (Q. 1-5): What will come in the place of question mark (?) in the following series?
1) 97, 99, 105, 117, ?
a) 143
b) 151
c) 137
d) 147
e) 153
2) 10, 5, 5, 7.5, 15, ?
a) 37.5
b) 24.25
c) 40.75
d) 33.5
e) 29
3) 11, 16, 26, 41, 61, ?
a) 72
b) 94
c) 108
d) 86
e) 78
4) 9, 21, 51, 135, 381, ?
a) 753
b) 841
c) 907
d) 1055
e) 1113
5) 3, 4, 10,33, 136, ?
a) 565
b) 685
c) 840
d) 720
e) 460
Directions (Q. 6 – 10): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer as,
A) If a > b
B) If a < b
C) If a ≥ b
D) If a ≤ b
E) If a = b or no relation can be established between x and y
6)
I) a² – 32a + 252 = 0
II)b² – 28b + 192 = 0
7)
I) a² – 32a + 247 = 0
II)b² – 22b + 117 = 0
8)
I) a² + 29a + 208 = 0
II)b² + 19b + 78 = 0
9)
I) a² – 22a + 105 = 0
II)b² – 27b + 162 = 0
10)
I) (a – 18)² = 0
II) b² = 324
11) If the ratio of investment of Abhishek and Abhijit is 3:4, then the total profit at the end of the year is Rs. 50000 and Abhishek’s share in total profit is Rs. 10000. What is the ratio of their time period of investment?
a) 1:2
b) 1:3
c) 1:4
d) 2:3
e) 3:5
12) By giving a discount of 20%, a person is making a profit of Rs. 50. If the markup percentage is 30, then find the cost price of the item?
a) Rs 1300
b) Rs 1500
c) Rs 1250
d) Rs 1400
e) None of These
13) The simple interest received on a certain sum is Rs. 35000 in five years at the rate of 10%. What would be the compound interest received on a same sum at a rate of 6% in 2 years?
a) Rs. 7924
b) Rs. 8236
c) Rs. 8418
d) Rs. 8652
e) None of these
14) Rishi and Kunal entered into a partnership with investment in the ratio 6: 7 respectively. After one year, Nimi joined them with double the initial investment of Rishi. At the end of two years, Rishi doubled his investment. At the end of three years, they earned a total profit of Rs.69000. Find the difference between the shares of Kunal and Nimi in the profit.
a) Rs.4000
b) Rs.3000
c) Rs.5000
d) Rs.6000
e) None of these
15) The difference between the two numbers is 540. 32 % of one number is equal to 48 % of another number. Find the two numbers?
a) 1620 and 1080
b) 1510 and 970
c) 1480 and 940
d) 1350 and 810
e) 1730 and 1190
16) Priyanka is 8 years older than Renuka. The ratio of the present ages of Priyanka to Myna is 4 : 5. Renuka is 16 years younger than Myna. What is Renuka’s present age?
a) 28 years
b) 24 years
c) 20 years
d) 32 years
e) None of these
17) If downstream speed of a boat is 200% more than the upstream speed of the boat and an object flowing on river covers 100 m in 40 seconds, then how much distance boat can cover in still water in 1 hour?
a) 15 km
b) 16 km
c) 27 km
d) 18 km
e) None of these
18) Pipe A and pipe B can fill the tank while working alone in 12 hour and 10 hours respectively but there is an another pipe C which can empty the fully filled tank in 15 hours. If there is 200 liters of water available in the tank and pipe A, B and C were opened then tank will be fully filled in 8 hours. What is the capacity of the tank?
a) 3200 liter
b) 2500 liter
c) 3000 liter
d) 3600 liter
e) 4000 liter
19) The marked price of Sofa is Rs. 1500 more than the cost price. When the discount of Rs. 250 is allowed, the profit of 20 % is earned. At what price should Sofa be sold to earn the profit of 30 %?
a) Rs. 8125
b) Rs. 7340
c) Rs. 8845
d) Rs. 7920
e) None of these
20) A box contains 7 red balls, 5 black balls, 4 orange balls. If three balls are drawn out randomly, then the probability of getting a ball of different colours?
a) 5/8
b) 3/7
c) ¼
d) 4/5
e) None of these
Directions (Q. 21 – 25): Study the following information carefully and answer the given questions.
The following table shows the total number of students in different branches from 2001 to 2005 in a certain college.
21) Find the ratio of total students in Aeronautical and chemical to that of total students in civil and electronics in all the given years together?
a) 35:27
b) 119:270
c) 191:230
d) 357:811
e) None of these
22) What is the average number of students in the year 2004 in all the given branches together?
a) 84
b) 92
c) 80
d) 76
e) None of these
23) What was the percentage increase of students in 2003 in all the given branches together as compared to the previous year?
a) 23.56%
b) 27.98%
c) 37.88%
d) 26.89%
e) 32.26%
24) Find the difference between the total Electronic, Computer Science and Aeronautical students to that of total Mechanical, Chemical and Civil students in all the given years together?
a) 562
b) 304
c) 458
d) 420
e) None of these
25) In which year, was the growth being maximum in Mechanical while comparing with the previous year?
a) 2005
b) 2004
c) 2003
d) 2002
e) Either b or d
Directions (Q. 26-30): What value will come in place of question mark (?) in the following questions?
26) ∛157464 + √8836 – 45 % of 800 =? + (1188 ÷ 9) – 362
a) 952
b) 816
c) 878
d) 924
e) None of these
27) 160% of 150 + ?% of 900 = 1770
a) 165
b) 170
c) 190
d) 180
e) 175
28) √1225 + ? = 4 2/7 of 140
a) 720
b) 565
c) 345
d) 630
e) 440
29) 15 1/3 – 4 1/6 + 8 5/12 – 7 2/3 = ? + 2 7/12
a) 11 2/5
b) 13 ¼
c) 8 3/7
d) 9 1/3
e) None of these
30) 11 * ? *9 = 542 + 54
a) 28
b) 33
c) 30
d) 27
e) 22
Directions (Q. 31 – 35) what approximate value should come in the place of question mark (?) in the following questions?
31) 26 % of 397 + 48 % of 703 – 25 % of 451 = ?
a) 370
b) 250
c) 330
d) 410
e) 290
32) (8/36) ÷ (216/63) × 756 – 341.67 + 67 % of 599 = ?
a) 110
b) 170
c) 230
d) 250
e) 190
33) 41 % of 697 + 69 % of 804 – 35 % of 751 = ?
a) 523
b) 577
c) 642
d) 675
e) 440
34) 33450 ÷ 11 + (5/7) of 12542 + 52 % of 2499 = ?2 – 387.78
a) 86
b) 105
c) 78
d) 92
e) 117
35)120 % of 1799 + (3/7) of 6889 = (?) + 218.81
a) 5160
b) 4350
c) 5740
d) 6320
e) 4890
Answers :
1) Answer : C)
+ (12+1), + (22+2), + (32+3), + (42+4),…
2) Answer : A)
*0.5, *1, *1.5, *2, *2.5,…
3) Answers : D)
Difference of difference: 5, 5, 5, 5…
4) Answer: E)
*3-6, *3-12, *3-18, *3-24, *3-30,…
5) Answer : B)
*1+1, *2+2, *3+3, *4+4,…
6) Answer : E)
I) a² – 32a + 252 = 0
(a – 18) (a – 14) = 0
a = 18, 14
II) b² – 28b + 192 = 0
(b – 12) (b – 16) = 0
b = 12, 16
Can’t be determined
7) Answer : C)
I) a² – 32a + 247 = 0
(a – 13) (a – 19) = 0
a = 13, 19
II) b² – 22b + 117 = 0
(b – 13) (b – 9) = 0
b = 13, 9
a ≥ b
8) Answer : D)
I) a² + 29a + 208 = 0
(a + 13) (a + 16) = 0
a = -13, -16
II) b² + 19b + 78 = 0
(b + 13) (b + 6) = 0
b = -13, -6
a ≤ b
9) Answer : E)
I) a² – 22a + 105 = 0
(a – 15) (a – 7) = 0
a = 15, 7
II) b² – 27b + 162 = 0
(b – 18) (b – 9) = 0
b = 18, 9
Can’t be determined
10) Answer : C)
I) (a – 18)² = 0
(a – 18) (a – 18) = 0
a = 18, 18
II) b² = 324
b = ±18
a ≥ b
11) Answers : B)
The ratio of investment of Abhishek and Abhijit = 3 : 4
The ratio of share of Abhishek and Abhijit = 10000 : 40000 = 1: 4
Investment*Period = Ratio of profit
The ratio of time period of Abhishek and Abhijit = (1/3) : (4/4) = 1 : 3
12) Answer : C)
Let CP = 100n
Hence MP = 130n
And SP = 130n x 0.8 = 104n
Profit = 4n = 50
=> n = 12.5
Hence cost price = Rs. 1250
13) Answers : D)
S.I = (P*n*r)/100
35000 = (P*5*10)/100
P = (35000*100)/50
P = Rs. 70000
Compound Interest:
70000*(6/100) = 4200
74200*(6/100) = 4452
C.I = 4200 + 4452 = Rs. 8652
14) Answer : B)
The share of Rishi, Kunal and Nimi,
= > [6*2 + 12*1] : [7*3] : [12*2]
= >24 : 21 : 24
= >8 : 7 : 8
23’s = 69000
1’s = 3000
The difference between the shares of Kunal and Nimi in the total profit
= > (8’s – 7’s) = Rs. 3000
15) Answers : A)
Let the two numbers be x and y,
X – Y = 540
(32/100)*X = (48/100)*Y
(X/Y) = 3/2
X : y = 3 : 2
1’s = 540
The two numbers be,
= > 3’s = (540*3) = 1620
= > 2’s = (540*2) = 1080
16) Answer : B)
Priyanka = Renuka + 8
The ratio of the present ages of Priyanka to Myna = 4 : 5 (4x, 5x)
Renuka = Myna – 16
Renuka’s present age = 5x – 16
Priyanka = Renuka + 8
4x = 5x – 16 + 8
8 = 5x – 4x
X = 8
Present age of Renuka = 5x – 16 = 40 – 16 = 24 years
17) Answer : D)
The ratio of speed of downstream to that of upstream = 3 : 1
Speed of stream = 100/40 = 5/2 m/s = (5/2)*(18/5) = 9 Km/hr
(1/2)*(3x – x) = 9
X = 9
Speed of boat in still water = (1/2)*(4x) = 2x = 18 Km/hr
Distance covered in 1 hour = 18 km
18) Answer : C)
Let total capacity of the tank be T litres
Part of tank filled when all the pipes are opened = T*(1/12+1/10-1/15) = 7T/60
Total tank filled in 8 hours = (7T/60)*8 = 56T/60 =14T/15
According to the question,
= > (14T/15) + 200 = T
= > T/15 = 200
= > T = 3000 litres
19) Answer : A)
Let the C.P be x,
M.P = 1500 + C.P = 1500 + x
- P = (1500 + x) – 250 = 1250 + x
S.P = (120/100)*x =(6/5)x
1250 + x = (6/5)x
6250 + 5x = 6x
C.P(X) = 6250
To earn a profit of 30 %,
- P = (130/100)*6250 = Rs. 8125
20) Answer : C)
Total probability n(S) = 16C3
Required probability n(E) = 7C1 and 5C1 and 4C1
P(E) = n(E)/n(S)
P(E) = (7C1 and 5C1 and 4C1)/ 16C3
P(E) = ¼
21) Answer : B)
Total students in Aeronautical and Chemical = 216 + 141 = 357
Total students in Civil and electronics = 500 + 310 = 810
Required ratio = 357 : 810 = 119 : 270
22) Answer : A)
Total students in 2004 in all the given branches together
= > 109 + 110 + 115 + 80 + 60 + 30 = 504
Required average = 504/6 = 84
23) Answer : E)
Total number of students in 2002
= > 75 + 80 + 65 + 46 + 25 + 19 = 310
Total number of students in 2003
= > 85 + 95 + 108 + 60 + 35 + 27 = 410
Required percentage = [(410 – 310)/310] * 100 = 32.26%
24) Answer : B)
Total Students in Mechanical = 50 + 75 + 85 + 109 + 120 = 439
Total Students in Chemical = 15 + 19 + 27 + 30 + 50 = 141
Total Students in Civil = 24 + 46 + 60 + 80 + 100 = 310
Total Electronic, Computer Science and Aeronautical students in all the given years together
= > 439 + 141 + 310 = 890
Total Students in Electronic = 65 + 80 + 95 + 110 + 150 = 500
Total Students in Computer Science = 45 + 65 + 108 + 115 + 145 = 478
Total Students in Aeronautical = 11 + 25 + 35 + 60 + 85 = 216
Total Mechanical, Chemical and Civil students in all the given years together
= > 500 + 478 + 216 = 1194
Required difference = 1194 – 890 = 304
25) Answer : D)
From the given figure,
Growth in mechanical students:
In 2002: [(75 – 50)/150] * 100 = 50%
In 2003: [(85 – 75)/175] * 100 = 13.33%
In 2004: [009 – 85)/85] * 100 = 28.23%
In 2005: [020 – 109)/109] * 100 = 10.09%
26) Answer : A)
54 + 94 – (45/100)*800 = x + (1188/9) – 1296
54 + 94 – 360 + 1296 = x + 132
54 + 94 – 360 + 1296 – 132 = x
X = 952
27) Answer : B)
X % of 900 = 1770 – 160 % of 150
(x/100)*900 = 1770 – (160 * 150)/100
9x = 1770 – 240
x = 1530/9 = 170
28) Answer : B)
x = 140 * (30/7) – √1225
x = 20 * 30 – 35
x = 600 – 35 = 565
29) Answer : D)
15 1/3 – 4 1/6 + 8 5/12 – 7 2/3 – 2 7/12 = x
(15 – 4 + 8 – 7 – 2) (1/3 – 1/6 + 5/12 – 2/3 – 7/12) = x
10 [(4 – 2 + 5 – 8 – 7)/12] = x
X = 10 (-8/12) = 10 (-2/3)
X = (30 – 2)/3 = 28/3 = 9 1/3
30) Answer : C)
11 *x* 9 = 542 + 54
99 x = 2916 + 54
x = 2970/99 = 30
31) Answer : C)
(26/100)*400 + (48/100)*700 – (25/100)*450 = x
104 + 336 – 112.5 = x
X = 327.5 = 330
32) Â Answer : A)
(8/36)*(63/216)*756 – 342 + (67/100)*600 = x
X = 49 – 342 + 402
X = 109 = 110
33) Answer : B)
41 % of 700 + 69 % of 800 – 35 % of 750 = x
X = (41/100)*700 + (69/100)*800 – (35/100)*750
X = 287 + 552 – 262.5
X = 576.5 = 577
34) Answer : E)
(33451/11) + (5/7)*12544 + (52/100)*2500 = x2 – 388
3041 + 8960 + 1300 + 388 = x2
X2 = 13689
X = 117
35) Answer : E)
120 % of 1800 + (3/7)*6888 = x + 219
(120/100)*1800 + (3/7)*6888 = x + 219
2160 + 2952 – 219 = x
X = 4893 = 4890
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