Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for IBPS RRB Clerk/EPFO Assistant/LIC ADO Prelims 2019 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
IBPS RRB Clerk Prelims Free Mock Test
EPFO Assistant Prelims Free Mock Test
LIC ADO Prelims Free Mock Test
[WpProQuiz 6577]
Directions (Q. 1 – 5): What value should come in place of (?) in the following number series?
1) 73, 37, 38, 58.5, 119, ?
a) 300
b) 324
c) 348
d) 272
e) 290
2) 18, 32, 105, 404, 2045, ?
a) 10586
b) 14752
c) 8625
d) 12234
e) 13865
3) 24, 36, 54, 81, 121.5, ?
a) 196
b) 218
c) 232
d) 174.75
e) 182.25
4) 1386, 1386, 693, 231, 57.75, ?Â
a) 18.25
b) 11.55
c) 24.65
d) 15.45
e) 27.35
5) 264, 1595, 2324, 2667, 2792, ?
a) 3157
b) 3392
c) 2819
d) 2675
e) 3068
Directions (Q. 6 – 10): Study the following information carefully and answer the given questions.
The following bar graph shows the total distance (In Km) travelled by 3 different persons in 5 different months.
6) Find the ratio between the total distance travelled by P in the month of January, March and May together to that of total distance travelled by R in the month of February, April and June together?
a) 143: 144
b) 147: 128
c) 141: 128
d) 128: 141
e) None of these
7) Find the difference between the total distance travelled by Q in the month of January and February together to that of total distance travelled by the same person in the month of May and June together?
a) 60 km
b) 40 km
c) 80 km
d) 20 km
e) None of these
8) Total distance travelled by all the 3 persons in the month of February is approximately what percentage more/less than the total distance travelled by all the 3 persons in the month of April?
a) 25 % more
b) 25 % less
c) 15 % less
d) 15 % more
e) 40 % more
9) Find the average distance travelled by person Q in all the given months together?
a) 920 km
b) 1050 km
c) 1180 km
d) 1370 km
e) None of these
10) Total distance travelled by person P and Q together in the month of March is approximately what percentage of total distance travelled by person Q and R together in the month of May?
a) 85 %
b) 70 %
c) 120 %
d) 135 %
e) 100 %
Answers:
Directions (1-5):
1) Answer: a)
73 * 0.5 + 0.5 = 37
37 * 1 + 1 = 38
38 * 1.5 + 1.5 = 58.5
58.5 * 2 + 2 = 119
119 * 2.5 + 2.5 = 300
2) Answer: d)
18 * 2 – 22 = 32
32 * 3 + 32 = 105
105 * 4 – 42 = 404
404 * 5 + 52 = 2045
2045 * 6 – 62 = 12234
3) Answer: e)
24 * 1.5 = 36
36 * 1.5 = 54
54 * 1.5 = 81
81 * 1.5 = 121.5
121.5 * 1.5 = 182.25
4) Answer: b)
1386 ÷ 1 = 1386
1386 ÷ 2 = 693
693 ÷ 3 = 231
231 ÷ 4 = 57.75
57.75 ÷ 5 = 11.55
5) Answer: c)
264 + 1331 (113) = 1595
1595 + 729 (93) = 2324
2324 + 343 (73) = 2667
2667 + 125 (53) = 2792
2792 + 27 (33) = 2819
Directions (6-10):
6) Answer: b)
The total distance travelled by P in the month of January, March and May together
= > 960 + 860 + 1120 = 2940 km
The total distance travelled by R in the month of February, April and June together
= > 840 + 760 + 960 = 2560 km
Required ratio = 2940 : 2560 = 147: 128
7) Answer: d)
The total distance travelled by Q in the month of January and February together
= > 1040 + 780 = 1820 km
The total distance travelled by the same person in the month of May and June together
= > 1040 + 760 = 1800 km
Required difference = 1820 – 1800 = 20 km
8) Answer: c)
Total distance travelled by all the 3 persons in the month of February
= > 720 + 780 + 840 = 2340 km
Total distance travelled by all the 3 persons in the month of April
= > 1060 + 920 + 760 = 2740 km
Required % = [(2740 – 2340) / 2740] * 100 = 15 % less
9) Answer: a)
The average distance travelled by person Q in all the given months together
= > (1040 + 780 + 980 + 920 + 1040 + 760) / 6
= > 5520/6 = 920 km
10) Answer: e)
The total distance travelled by person P and Q together in the month of March
= > 860 + 980 = 1840 km
The total distance travelled by person Q and R together in the month of May
= > 1040 + 820 = 1860 km
Required % = (1840 / 1860) * 100 = 98.92 % = 100 %
