Dear Aspirants, Our IBPS Guide team is providing new series of Numerical Ability Questions for LIC HFL Associate/ Assistant 2019 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
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Directions (Q. 1 – 5): What approximate value should come in place of question mark (?) in the following questions?
1) 26 % of 349.75 – 32 % of 599.27 =? – 157.94 – (27.21)2
a) 820
b) 568
c) 786
d) 634
e) 912
2) 5 2/3 of 299.78 + 3 1/8 of 429.67 =? % of 749.85
a) 384
b) 360
c) 448
d) 412
e) 490
3) (553.672 + 959.325 – 432.72) ÷ 14.85 =?
a) 72
b) 86
c) 65
d) 58
e) 95
4) [((149 ÷ 3) ÷ 9.97)2 + (64.13 × 9.05)1/2] = (?)2
a) 12
b) 18
c) 7
d) 23
e) 30
5) ? ÷ 3.9 + 72.03 × 15 = 4824.12 + 1598.23
a) 25682
b) 21368
c) 18924
d) 16780
e) 27950
Directions (Q. 6 – 10) Study the following information carefully and answer the given questions.
The following table shows the total number of tyres (In lakhs) manufactured by 5 different companies in a certain year.
6) Total number of tyres rejected by the company P is approximately what percentage more/less than the total number of tyres rejected by the company T?
a) 7 % less
b) 15 % more
c) 15 % less
d) 24 % more
e) 7 % more
7) Find the average number of tyres manufactured by all the given companies together?
a) 32.4 lakhs
b) 28.5 lakhs
c) 30.8 lakhs
d) 34.6 lakhs
e) None of these
8) Find the difference between the total number of tyres sold by the company Q to that of company S?
a) 792600
b) 756800
c) 833200
d) 809270
e) None of these
9) Find the ratio between the total number of tyres rejected by the company Q to that of R?
a) 72: 55
b) 53: 115
c) 84: 137
d) 65: 96
e) None of these
10) Total number of tyres sold by the company P is approximately what percentage of total number of tyres sold by the company R?
a) 60 %
b) 75 %
c) 50 %
d) 85 %
e) 105 %
Answers:
Directions (1-5):
1) Answer: c)
26 % of 350 – 32 % of 600 = x – 158 – 272
(26/100)*350 – (32/100)*600 = x – 158 – 729
91 – 192 + 158 + 729 = x
X = 786
2) Answer: d)
6 of 300 + 3 of 430 = x% of 750
(300*6) + (3*430) = (x/100)*750
1800 + 1290 = 15x/2
(3090*2)/15 = x
X = 412
3) Answer: a)
(554 + 959 – 433)/15 = x
X = 1080/15 = 72
4) Answer: c)
[((150 ÷ 3) ÷ 10)2 + (64 × 9)1/2] = x2
(150/30)2 + (8*3) = x2
25 + 24 = x2
X2 = 49
X = 7
5) Answer: b)
x ÷ 4 + 72 × 15 = 4824 + 1598
(x/4) + 1080 = 6422
(x/4) = 5342
X = 5342*4 = 21368
Directions (6-10):
6) Answer: e)
Total number of tyres rejected by the company P
= > 3200000*(2/100) = 64000
Total number of tyres rejected by the company T
= > 4000000*(1.5/100) = 60000
Required % = [(64000 – 60000)/60000]*100 = 7 % more
7) Answer: a)
The average number of tyres manufactured by all the given companies together
= > (32 + 26 + 48 + 16 + 40)/5
= > 162/5 = 32.4 lakhs
8) Answer: c)
The total number of tyres sold by the company Q
= >2600000*(95/100)*(84/100) = 2074800
The total number of tyres sold by the company S
= > 1600000*(97/100)*(80/100) = 1241600
Required difference = 2074800 – 1241600 = 833200
9) Answer: d)
The total number of tyres rejected by the company Q
= > 26*(5/100) = 1.3 lakhs
The total number of tyres rejected by the company R
= > 48*(4/100) = 1.92 lakhs
Required ratio = 1.3: 1.92 = 130: 192 = 65: 96
10) Answer: b)
Total number of tyres sold by the company P
= > 3200000*(98/100)*(78/100) = 2446080
Total number of tyres sold by the company R
= > 4800000*(96/100)*(72/100) = 3317760
Required % = (2446080/3317760)*100 = 73.726 = 75 %
This post was last modified on November 27, 2021 10:24 am
