Number series questions for bank RRB, RBI, SSC & other competitive exams is a common and most expected topic in the quantitative aptitude section. Missing number series questions pdf with answers is provided here. Missing numbers are the numbers that have been missed in the given series of a number with similar differences among them. The method of writing the missing numbers is stated as finding similar changes between those numbers and filling the missing terms in the specific series and places. Missing numbers in a series can be found by identifying the common difference, difference of difference, multiplication, division, squares, cubes, etc.
Practice Topic Tests For Quantitative Aptitude Section
For the Mains examination, the common difference will be asked in the missing number series questions and the question level will be easy. For the mains examination, the combination of operations will be asked. Most of the candidates feel missing number series questions are easy compared to the wrong number series. But with consistent practice, candidates can score good marks in number series questions for bank and other competitive exams. Make use of these number series for bank po and clerical exams.
Quantitative Aptitude Questions Quiz – Practice Mock Test
Directions (1-10): The questions below are based on the given Series-I. The series-I satisfy a certain pattern, follow the same pattern in Series-II and answer the questions given below.
1) I) 12, 18, 36, 90, 270, 945
II) 112……..2520.If 2520 is the nth, Find the value of n
A.5
B.4
C.6
D.7
E.8
2) I) 5760, 960, 192, 48, 16
II) 3960……33.If 33 is the nthterm, find the value of n
A.5
B.4
C.6
D.7
E.3
3) I) 15, 16, 34, 105, 424
II) 7…..57. If 57 is the nthterm, find the value of n
A.4
B.6
C.5
D.3
E.7
4) I) 14, 24, 45, 78, 124
II) 1…..111. If 111 is the nthterm find the value of n
A.4
B.6
C.5
D.3
E.7
5) I) 1, 170, 291, 372, 421, 446
II) 93…..383. If 383 is the nthterm find the value of n
A.4
B.6
C.5
D.3
E.7
6) I) 8, 4, 6, 15, 52.5
II) 12 …. 78.75. If 78.75 is the nthterm, find the value of n
A.6
B.4
C.5
D.7
E.8
7) I) 19, 38, 114, 570, 3990
II) 23 ….. 690. If 690 is the nthterm, find the value of n
A.6
B.5
C.7
D.8
E.4
8) I) 15, 32, 68, 144, 304
II) 0.5 ….. 176. If 176 is the nthterm, find the value of n
A.9
B.8
C.7
D.6
E.11
9) I) 11, 23, 33, 41, 47
II) 114 …… 154. If 154 is the nthterm find the value of n
A.6
B.3
C.5
D.7
E.4
10) I) 102, 342, 462, 542, 602
II) 7 ….. 447. If 447 is the nthterm, find the value of n
A.2
B.3
C.4
D.6
E.5
Answers :
1) Answer: A
Series I,
12 * 1.5 = 18
18 * 2 = 36
36 * 2.5 = 90
90 * 3 = 270
270 * 3.5 = 945
Series II,
112 is the 1st term
112 * 1.5 = 168
168 * 2 = 336
336 * 2.5 = 840
840 * 3 = 2520
2520 is the 5th term
2) Answer: B
Series I,
5760/6 = 960
960/5 = 192
192/4 = 48
48/3 = 16
Series II,
3960 is the 1st term
3960/6 = 660
660/5 = 132
132/4 = 33
33/3 = 11
33 is the 4th term
3) Answer: A
Series I,
15 * 1 + 1 = 16
16 * 2 + 2 = 34
34 * 3 + 3 = 105
105 * 4 + 4 = 424
Series II,
7 is the 1st term
7 * 1 + 1 = 8
8 * 2 + 2 = 18
18 * 3 + 3 = 57
57 is the 4th term.
4) Answer: C
Series I,
14 + 10 = 24
24 + 10 + 11 = 45
45 + 10 + 11 + 12 = 78
78 + 10 + 11 + 12 + 13 = 124
Series II,
1 is the 1st term.
1+ 10 = 11
11 + 10 + 11 = 32
32 + 10 + 11 + 12 = 65
65 + 10 + 11 + 12 + 13 = 111
111 is 5th term.
5) Answer: D
Series I,
1 + 132 = 170
170 + 112 = 291
291 + 92 = 372
372 + 72 = 421
421 + 52 = 446
Series II,
93 is 1st term.
93 + 132 = 262
262 + 112 = 383
383 is 3rd term.
6) Answer: C
Series – I,
8 is the 1st term
8 * 0.5 = 4
4 * 1.5 = 6
6 * 2.5 = 15
15 * 3.5 = 52.5
Series – II,
12 is the 1st term
12 * 0.5 = 6
6 * 1.5 = 9
9 * 2.5 = 22.5
22.5 * 3.5 = 78.75 = 5th term
7) Answer: E
Series –I,
19 is the 1st term
19 * 2 = 38
38 * 3 = 114
114 * 5 = 570
570 * 7 = 3990
Series –II
23 is the 1st term
23 * 2 = 46
46 * 3 = 138
138 * 5 = 690 (4th term)
8) Answer: D
Series –I
15 is the 1st term
15 * 2 + 2 = 32
32 * 2 + 4 = 68
68 * 2 + 8 = 144
144 * 2 + 16 = 304(5th term)
Series – II,
0.5 is the 1st term
0.5 * 2 + 2 = 3
3 * 2 + 4 = 10
10 * 2 + 8 = 28
28 * 2 + 16 = 72
72 * 2 + 32 = 176 = 6th term
9) Answer: A
Series – I,
11 is the 1st term
11 + 12 = 23
23 + 10 = 33
33 + 8 = 41
41 + 6 = 47 (5th term)
Series – II,
114 is the 1st term
114 + 12 = 126
126 + 10 = 136
136 + 8 = 144
144 + 6 = 150
150 + 4 = 154 (6th term)
10) Answer: C
Series – I
102 is the 1st term
102 + 240/1 = 342
342 + 240/2 = 462
462 + 240/3 = 542
542 + 240/4 = 602
Series – II,
7 is the 1st term
7 + 240 = 247
247 + 240/2 = 367
367 + 240/3 = 447 (4th term)
This post was last modified on January 5, 2022 10:54 am