Mixture and Alligation Questions PDF: Download With Answers, Take Quiz For Bank Exams

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Mixture and Alligation Questions And Answers

Mixture and Alligation Questions With Solutions: The Mixture and Alligation PDF contains all the levels and types of Mixture and Alligation questions with answers and detailed explanations. Utilize this Mixture and Alligation questions and answers pdf for the bank Prelims exam and Mixture and Alligation questions and answers pdf for bank mains to improve your speed and accuracy while solving the Mixture and Alligation questions in real exams. You may experience all the techniques and tricks to solve the questions while practicing with the Mixture and Alligation questions and answers pdf for bank exams. Aspirants who have quant as their weaker section must take up this PDF for bank exams and practice with this regularly. Candidates can start their effective preparation by exploiting this Mixture and Alligation questions pdf for bank exams.

 

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So, candidates practice well using the Mixture and alligation problems for bank PO Mains pdf.

 

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1) A milkman has 40 liters mixture of milk and water in the ratio of 5:3. If he sold 16 liters of mixture and then 12 liters of milk added to the mixture. Again he sold 20 liters of mixture and then he added 8 liters of milk to the mixture. The final quantity of the water is what percent of the final quantity of the milk?

A.10%

B.15%

C.20%

D.25%

E.None of these


2) Vessel A contains the mixture of Petrol and Diesel in the ratio of 3: 2, vessel B contains the mixture of Petrol and Kerosene in the ratio of 1: 2 and Vessel C contains mixture of Kerosene and Diesel in the ratio of 2: 3. If all the vessels are mixed in the ratio of 4: 3: 2, then find the respective ratio of Petrol, Diesel and Kerosene in the final mixture?

A.46: 58: 31

B.56: 63: 32

C.67: 72: 41

D.59: 68: 35

E.None of these


3) A Jar contains 80 liters mixture of milk and water and the quantity of the water is 30% of the total mixture. If X liters of mixture is taken out and replaced by water and then again the same quantity of the mixture is taken out and replaced by water. If final quantity of the milk is 31.5 liters, then find the value of x?

A.20 liters

B.28 liters

C.30 liters

D.40 liters

E.None of these


4) How many kilograms of rice of Rs 6.4/kg should be mixed with 10 kg of rice of Rs 4.8/kg,  in such that by selling the mixture at 20 % profit, which is Rs. 1.12 more than the average price per kg of both the varieties of rice 

A.12 kg

B.15 kg

C.10 kg

D.11 kg

E.None of these


5) The vessel A contains the ratio of the milk and water in the ratio of 8:5 and the vessel B contains 60 liters mixture of milk and water in the ratio of 7:5. If vessel A and B mixture mixed, then the ratio of the milk and water becomes 3:2, what is the initial quantity of the milk in vessel A?

A.32 liters

B.24 liters

C.40 liters

D.48 liters

E.None of these


6) A vessel has certain quantity of milk and then 8 liters of milk is taken out and replaced with water. Now 10 liters of mixture taken out and replace with water and again 12 liters of the mixture is taken out and replaced with water. If the initial quantity of the milk in the vessel is 80 liters, then what is the final quantity of the milk?

A.53.55 liters

B.54.78 liters

C.55.89 liters

D.56.19 liters

E.None of these


7) Ratio of the milk to water in vessel A to B is 3:2 and 5:6 respectively and the quantity of the milk in vessel B is 5 liters less than the quantity of the water in vessel B. If vessel A and Vessel B mixtures are mixed, then the ratio of milk to water becomes 11:10, then what is the initial quantity of vessel A?

A.60 liters

B.50 liters

C.40 liters

D.30 liters

E.None of these


8) A container contains x litres of pure milk which costs Rs. 20 per litre. From that container, 50% is taken out and water is added. The mixture in this container is poured into another container which contains same quantity with milk and water in a ratio of 3: 1. Find the price at which this mixture to be sold to make 10% profit

A.12.5 per litre

B.13.75 per litre

C.11.25 per litre

D.15.125 per litre

E.22 per litre


9) A vessel contains a mixture of milk and orange juice in the ratio of x: 3. When 10 litres of milk is added to the mixture then the ratio of milk to orange juice becomes 5: 3 and when 20 litres of milk is added then the ratio of milk to orange juice becomes 7: 4. Find the initial quantity of orange juice in the mixture.

A.125 litres

B.110 litres

C.120 litres

D.90 litres

E.115 litres


10) The cost price of milk in vessel A is Rs.66 per liter and the cost price of milk in vessel B is Rs.51. If milk in vessel A and B are mixed, then the shopkeeper sold 37.5 liters of this mixture at the cost price of milk in vessel A while he gets the profit of 10%. If he sold the same mixture at the cost price of milk in vessel B, then what is the percentage of loss or profit earned by shopkeeper?

A.8% profit

B.8% loss

C.15% loss

D.15% profit

E.None of these

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Answers :

1) Answer: C

Milk in 40 liters = 5/8 * 40 = 25 liters

Water in 40 liters = 3/8 * 40 = 15 liters

Milk in 16 liters = 16 * 5/8 = 10 liters

Water in 16 liters = 16 * 3/8 = 6 liters

After adding 12 liters Now milk quantity = 25 – 10 + 12 = 27 liters

Water quantity = 15 – 6 = 9 liters

Now the ratio of milk and water = 27:9 = 3:1

Milk in 20 liters = 20 * ¾ = 15 liters

Water in 20 liters = 20 * ¼ = 5 liters

Final milk quantity = 27 – 15 + 8 = 20 liters

Water quantity = 9 – 5 = 4 liters

Required percentage = 4/20 * 100 = 20%


2) Answer: E

Required ratio of Petrol, Diesel and Kerosene

= [4 * 3/5 + 3 * 1/3]: [4 * 2/5 + 2 * 3/5]: [3 * 2/3 + 2 * 2/5]

= 17/5: 14/5: 14/5

= 17: 14: 14


3) Answer: A

Milk in 80 liters = 80 * 70/100 = 56 liters

Water in 80 liters = 80 * 30/100 = 24 liters

31.5 = 56 * (1 – x/80)2

4.5/8 = (1 – x/80)2

4.5 * 80 * 80 / 8 = (80 – x)2

60 = 80 – x

x = 20 liters


4) Answer: C

Let the quantity of Rs 6.4/kg be x kg.

S.P of mixture= Rs [1.12 + (6.4 + 4.8)/2]=1.12 + 5.6= Rs 6.72

According to question,

=>(x * 6.4 + 4.8 * 10) * 120/100= 6.72(x + 10)

=>6.4x * 120/100 + 48 * 120/100= 6.72x + 67.2

=>0.96x= 9.6

 x= 9.6/0.96= 10kg.


5) Answer: C

Milk in vessel A = 8/13

Milk in vessel B = 7/12

Milk in final mixture = 3/5

=13:12

Total quantity of vessel A = 13/12 * 60 = 65

Quantity of milk in A = 65 * 8/13 = 40


6) Answer: A

Milk = 80 * (1 – 8/80) * (1 – 10/80) * (1 – 12/80)

= 53.55 liters


7) Answer: B

Let Quantity of milk from vessel A = 3x

Quantity of the water from vessel A = 2x

Quantity of milk from vessel B = 5y

Quantity of water from vessel B = 6y

Now, Milk in vessel B = 5 * 5 = 25 liters

Water in vessel B = 6 * 5 = 30 liters

(25 + 3x)/(30 + 2x) = 11/10

330 + 22x = 250 + 30x

8x = 80

x = 10

Quantity of vessel A = 5 * 10 = 50 liters


8) Answer: B

First Container: x litres of pure milk. 50 percent taken out and water added. So Milk = 0.5x; water = 0.5x

Second container: same quantity x.

Milk: Water = 3: 1.

So Milk= 0.75x and water = 0.25x

Two containers mixed: Total = 2x; Milk = 1.25x and Water = 0.75x

Cost price = Rs.20

Total quantity =

By mixture method, let y be the actual price of the mixture and given cost price of milk is 20 and water is 0

(20 – y)/(y – 0) = 0.75/1.25

y = 12.5;

Selling price with 10% profit = 1.1 * 12.5 = 13.75 rupees per litre


9) Answer: C

Let the initial quantity of orange juice = 3a and initial quantity of milk = xa

ATQ,

(xa + 10)/3a = 5/3

3xa + 30 = 15a (equation 1)

Also,

(xa + 20)/3a = 7/4

4xa + 80 = 21a (equation 2)

Solving equation 1 and 2, we get

a =40

Initial quantity of orange juice = 3a =3 * 40 = 120 litres


10) Answer: C

Quantity of vessel B = x

Quantity of vessel A = 37.5 – x

CP of the mixture = x * 51 + (37.5 – x) * 66

= 2475 – 15x

SP of the mixture = 37.5 * 66 = 2475

Profit = (2475 – (2475 – 15x))/(2475 – 15x) * 100 = 10

1500x = 24750 – 150x

x = 15

CP of the mixture = 2475 – 15 * 15 = 2250

New SP of the mixture = 37.5 * 51 = 1912.5

Required loss percentage = (2250 – 1912.5)/2250 * 100

= 15% loss

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