Mixture and Alligation Questions PDF: Mixture and Alligation problems for bank exams pdf is available here. In the quantitative aptitude section, candidates will skip most of the application sums in exams. Mixture and Alligation is one of the topics in the application sums. In the bank prelims and mains exams, you should not take much time for a single question. For that, heavy practice is needed. If you practice well, you can easily solve the question in around a minute. So, practice more using the Mixture and Alligation questions pdf for bank exams. Here we have provided more Mixture and alligation questions of various models. Hence, you can learn a lot of tricks to solve the problem.
In the Mixture and Alligation problems, there are various types such as a dishonest seller, a mixture of qualities, etc. In this Mixture and Alligation questions pdf for bank exams, you can practice all these types of questions.
Banking & Insurance Exam Study Materials
Mixture and Alligation Questions PDF For Bank Exams: The Mixture and Alligation Questions pdf for bank exams download link is provided below on this page. Candidates can improve their efficiency in solving any type of Mixture and alligation questions by using this Mixture and alligation aptitude questions pdf for bank exams. This Mixture and Alligation Questions pdf will help you to solve different types and levels of Mixture and alligation questions with speed and accuracy. So download this Mixture and Alligation pdf for bank exams for your effective preparation.
Download Mixture and Alligation Questions PDF
Also, we will update the Mixture and Alligation questions pdf and Mixture and Alligation quiz daily in the below table. Candidates can download this Mixture and Alligation questions pdf to practice regularly. You can attempt the daily Mixture and Alligation quiz by clicking the take test link provided in the following table.
| Mixture and Alligation Questions For Bank Exams – Daily Quiiz | ||
| Day 1 | Mixture and Alligation Questions PDF | Take Test |
| Day 2 | Mixture and Alligation Questions PDF | Take Test |
| Day 3 | Mixture and Alligation Questions PDF | Take Test |
| Day 4 | Mixture and Alligation Questions PDF | Take Test |
| Day 5 | Mixture and Alligation Questions PDF | Take Test |
Mixture and Alligation Questions With Solutions: The Mixture and Alligation PDF contains all the levels and types of Mixture and Alligation questions with answers and detailed explanations. Utilize this Mixture and Alligation questions and answers pdf for the bank Prelims exam and Mixture and Alligation questions and answers pdf for bank mains to improve your speed and accuracy while solving the Mixture and Alligation questions in real exams. You may experience all the techniques and tricks to solve the questions while practicing with the Mixture and Alligation questions and answers pdf for bank exams. Aspirants who have quant as their weaker section must take up this PDF for bank exams and practice with this regularly. Candidates can start their effective preparation by exploiting this Mixture and Alligation questions pdf for bank exams.
Here we have discussed the advantages of Mixture and alligation problems for bank PO Mains pdf.
So, candidates practice well using the Mixture and alligation problems for bank PO Mains pdf.
More Quantitative Aptitude Topics Free PDF
1) A milkman has 40 liters mixture of milk and water in the ratio of 5:3. If he sold 16 liters of mixture and then 12 liters of milk added to the mixture. Again he sold 20 liters of mixture and then he added 8 liters of milk to the mixture. The final quantity of the water is what percent of the final quantity of the milk?
A.10%
B.15%
C.20%
D.25%
E.None of these
2) Vessel A contains the mixture of Petrol and Diesel in the ratio of 3: 2, vessel B contains the mixture of Petrol and Kerosene in the ratio of 1: 2 and Vessel C contains mixture of Kerosene and Diesel in the ratio of 2: 3. If all the vessels are mixed in the ratio of 4: 3: 2, then find the respective ratio of Petrol, Diesel and Kerosene in the final mixture?
A.46: 58: 31
B.56: 63: 32
C.67: 72: 41
D.59: 68: 35
E.None of these
3) A Jar contains 80 liters mixture of milk and water and the quantity of the water is 30% of the total mixture. If X liters of mixture is taken out and replaced by water and then again the same quantity of the mixture is taken out and replaced by water. If final quantity of the milk is 31.5 liters, then find the value of x?
A.20 liters
B.28 liters
C.30 liters
D.40 liters
E.None of these
4) How many kilograms of rice of Rs 6.4/kg should be mixed with 10 kg of rice of Rs 4.8/kg, in such that by selling the mixture at 20 % profit, which is Rs. 1.12 more than the average price per kg of both the varieties of rice
A.12 kg
B.15 kg
C.10 kg
D.11 kg
E.None of these
5) The vessel A contains the ratio of the milk and water in the ratio of 8:5 and the vessel B contains 60 liters mixture of milk and water in the ratio of 7:5. If vessel A and B mixture mixed, then the ratio of the milk and water becomes 3:2, what is the initial quantity of the milk in vessel A?
A.32 liters
B.24 liters
C.40 liters
D.48 liters
E.None of these
6) A vessel has certain quantity of milk and then 8 liters of milk is taken out and replaced with water. Now 10 liters of mixture taken out and replace with water and again 12 liters of the mixture is taken out and replaced with water. If the initial quantity of the milk in the vessel is 80 liters, then what is the final quantity of the milk?
A.53.55 liters
B.54.78 liters
C.55.89 liters
D.56.19 liters
E.None of these
7) Ratio of the milk to water in vessel A to B is 3:2 and 5:6 respectively and the quantity of the milk in vessel B is 5 liters less than the quantity of the water in vessel B. If vessel A and Vessel B mixtures are mixed, then the ratio of milk to water becomes 11:10, then what is the initial quantity of vessel A?
A.60 liters
B.50 liters
C.40 liters
D.30 liters
E.None of these
8) A container contains x litres of pure milk which costs Rs. 20 per litre. From that container, 50% is taken out and water is added. The mixture in this container is poured into another container which contains same quantity with milk and water in a ratio of 3: 1. Find the price at which this mixture to be sold to make 10% profit
A.12.5 per litre
B.13.75 per litre
C.11.25 per litre
D.15.125 per litre
E.22 per litre
9) A vessel contains a mixture of milk and orange juice in the ratio of x: 3. When 10 litres of milk is added to the mixture then the ratio of milk to orange juice becomes 5: 3 and when 20 litres of milk is added then the ratio of milk to orange juice becomes 7: 4. Find the initial quantity of orange juice in the mixture.
A.125 litres
B.110 litres
C.120 litres
D.90 litres
E.115 litres
10) The cost price of milk in vessel A is Rs.66 per liter and the cost price of milk in vessel B is Rs.51. If milk in vessel A and B are mixed, then the shopkeeper sold 37.5 liters of this mixture at the cost price of milk in vessel A while he gets the profit of 10%. If he sold the same mixture at the cost price of milk in vessel B, then what is the percentage of loss or profit earned by shopkeeper?
A.8% profit
B.8% loss
C.15% loss
D.15% profit
E.None of these
Mixture and Allegation Questions For Online Mock Test
Answers :
1) Answer: C
Milk in 40 liters = 5/8 * 40 = 25 liters
Water in 40 liters = 3/8 * 40 = 15 liters
Milk in 16 liters = 16 * 5/8 = 10 liters
Water in 16 liters = 16 * 3/8 = 6 liters
After adding 12 liters Now milk quantity = 25 – 10 + 12 = 27 liters
Water quantity = 15 – 6 = 9 liters
Now the ratio of milk and water = 27:9 = 3:1
Milk in 20 liters = 20 * ¾ = 15 liters
Water in 20 liters = 20 * ¼ = 5 liters
Final milk quantity = 27 – 15 + 8 = 20 liters
Water quantity = 9 – 5 = 4 liters
Required percentage = 4/20 * 100 = 20%
2) Answer: E
Required ratio of Petrol, Diesel and Kerosene
= [4 * 3/5 + 3 * 1/3]: [4 * 2/5 + 2 * 3/5]: [3 * 2/3 + 2 * 2/5]
= 17/5: 14/5: 14/5
= 17: 14: 14
3) Answer: A
Milk in 80 liters = 80 * 70/100 = 56 liters
Water in 80 liters = 80 * 30/100 = 24 liters
31.5 = 56 * (1 – x/80)2
4.5/8 = (1 – x/80)2
4.5 * 80 * 80 / 8 = (80 – x)2
60 = 80 – x
x = 20 liters
4) Answer: C
Let the quantity of Rs 6.4/kg be x kg.
S.P of mixture= Rs [1.12 + (6.4 + 4.8)/2]=1.12 + 5.6= Rs 6.72
According to question,
=>(x * 6.4 + 4.8 * 10) * 120/100= 6.72(x + 10)
=>6.4x * 120/100 + 48 * 120/100= 6.72x + 67.2
=>0.96x= 9.6
x= 9.6/0.96= 10kg.
5) Answer: C
Milk in vessel A = 8/13
Milk in vessel B = 7/12
Milk in final mixture = 3/5
=13:12
Total quantity of vessel A = 13/12 * 60 = 65
Quantity of milk in A = 65 * 8/13 = 40
6) Answer: A
Milk = 80 * (1 – 8/80) * (1 – 10/80) * (1 – 12/80)
= 53.55 liters
7) Answer: B
Let Quantity of milk from vessel A = 3x
Quantity of the water from vessel A = 2x
Quantity of milk from vessel B = 5y
Quantity of water from vessel B = 6y
Now, Milk in vessel B = 5 * 5 = 25 liters
Water in vessel B = 6 * 5 = 30 liters
(25 + 3x)/(30 + 2x) = 11/10
330 + 22x = 250 + 30x
8x = 80
x = 10
Quantity of vessel A = 5 * 10 = 50 liters
8) Answer: B
First Container: x litres of pure milk. 50 percent taken out and water added. So Milk = 0.5x; water = 0.5x
Second container: same quantity x.
Milk: Water = 3: 1.
So Milk= 0.75x and water = 0.25x
Two containers mixed: Total = 2x; Milk = 1.25x and Water = 0.75x
Cost price = Rs.20
Total quantity =
By mixture method, let y be the actual price of the mixture and given cost price of milk is 20 and water is 0
(20 – y)/(y – 0) = 0.75/1.25
y = 12.5;
Selling price with 10% profit = 1.1 * 12.5 = 13.75 rupees per litre
9) Answer: C
Let the initial quantity of orange juice = 3a and initial quantity of milk = xa
ATQ,
(xa + 10)/3a = 5/3
3xa + 30 = 15a (equation 1)
Also,
(xa + 20)/3a = 7/4
4xa + 80 = 21a (equation 2)
Solving equation 1 and 2, we get
a =40
Initial quantity of orange juice = 3a =3 * 40 = 120 litres
10) Answer: C
Quantity of vessel B = x
Quantity of vessel A = 37.5 – x
CP of the mixture = x * 51 + (37.5 – x) * 66
= 2475 – 15x
SP of the mixture = 37.5 * 66 = 2475
Profit = (2475 – (2475 – 15x))/(2475 – 15x) * 100 = 10
1500x = 24750 – 150x
x = 15
CP of the mixture = 2475 – 15 * 15 = 2250
New SP of the mixture = 37.5 * 51 = 1912.5
Required loss percentage = (2250 – 1912.5)/2250 * 100
= 15% loss
This post was last modified on May 22, 2024 1:13 pm