Dear Readers, Bank Exam Race for the Year 2019 is already started, To enrich your preparation here we have providing new series of Practice Questions on Quantitative Aptitude – Section. Candidates those who are preparing for NIACL AO Mains 2019 Exams can practice these questions daily and make your preparation effective.
[WpProQuiz 5126]
Click here to take NIACL AO Mock Test
Directions (Q. 1 – 5): What approximate value should come in place of (?) in the following questions?
1) (21/47) ÷ (179/234) × 141 + 3278.12 – 42 % of 899 =?
a) 2982
b) 3156
c) 2844
d) 2353
e) 1890
2) (3/17.92) × 431 + (3.72/14) × 209 + 70% of 499 =? – 1335
a) 2356
b) 2192
c) 1817
d) 1624
e) 2530
3) 90% of 12599 + 120% of 32999 – 635.92 =?
a) 42728
b) 50304
c) 33627
d) 39756
e) 45130
4) (3/11) of 186.58 × 25.12 ÷ 5 – ? = 65.31 ÷ 5 + 24.98
a) 234
b) 292
c) 305
d) 217
e) 350
5) 12 (¾) – 5 (7/9) + 11 (1/5) – 8 (1/9) =? – 3 (½)
a) 14
b) 25
c) 8
d) 33
e) 42
Directions (Q. 6 – 10): Study the following information carefully and answer the given questions.
The following line graph shows the total number of students from 6 different colleges in a certain year.
6) 23 % and 32 % of the students from college P and R respectively are going to symposium in college A to participate all the events. 52 % of the students from college A doesn’t participate any event, which is equal to 78 % of average number of students from all the given colleges together (i.e., college P, Q, R, S, T and U). Find the total number of students participated in symposium events from college P, R and A together?
a) 1798
b) 1852
c) 1644
d) 1936
e) None of these
7) Total number of students from college P and R together is what percentage of total number of students from college Q and T together?
a) 85.275 %
b) 66.525 %
c) 52.125 %
d) 71.875 %
e) None of these
8) If the ratio between the total number of girls to that boys from college S and college T is 43 : 32 and 27 : 23 respectively, then find the difference between the total number of girls to that of boys in college S and T together?
a) 320
b) 440
c) 560
d) 680
e) None of these
9) Find the total number of students in college B, if the total number of students in college B is 380 less the average number of students from all the given colleges together (i.e., College P, Q, R, S, T and U)?
a) 1350
b) 1480
c) 1270
d) 1560
e) None of these
10) Total number of students from college P, R and U together is approximately what percentage more/less than the total number of students from college Q, S and T together?
a) 2 % less
b) 15 % more
c) 15 % less
d) 2 % more
e) 23 % less
Answers :
Direction (1-5) :
1) Answer: a)
(21/47) ÷ (180/235) × 140 + 3278 – 42 % of 900 = x
(21/47)*(235/180)*140 + 3278 – (42/100)*900 = x
X = 82 + 3278 – 378 = 2982
2) Answer: c)
(3/18) × 432 + (4/14) × 210 + (70/100)*500 = x – 1335
72 + 60 + 350 + 1335 = x
X = 1817
3) Answer: b)
90% of 12599 + 120% of 32999 – 635.92 = x
X = (90/100)*12600 + (120/100)*33000 – 636
X = 11340 + 39600 – 636
X = 50304
4) Answer: d)
(3/11)*187 × 25 ÷ 5 – x = (65/5) + 25
255 – 13 – 25 = x
X = 217
5) Answer: a)
12 (¾) – 5 (7/9) + 11 (1/5) – 8 (1/9) + 3 (½) = x
X = 13 – 6 + 11 – 8 + 4
X = 14
Direction (6-10) :
6) Answer: a)
Total number of students from college A
= > (78/100)*[(1400 + 1000 + 900 + 1800 + 2200 + 2600)/6]*(100/52)
= > (78/100)*(9900/6)*(100/52)
= > 2475
The total number of students participated in symposium events from college P, R and A together
= > 1400*(23/100) + 900*(32/100) + 2475*(48/100)
= > 322 + 288 + 1188
= > 1798
7) Answer: d)
Total number of students from college P and R together
= > 1400 + 900 = 2300
Total number of students from college Q and T together
= > 1000 + 2200 = 3200
Required % = (2300/3200)*100 = 71.875 %
8) Answer: b)
The total number of girls in college S and T together
= > 1800*(43/75) + 2200*(27/50)
= > 1032 + 1188 = 2220
The total number of boys in college S and T together
= > 1800*(32/75) + 2200*(23/50)
= > 768 + 1012 = 1780
Required difference = 2220 – 1780 = 440
9) Answer: c)
The total number of students in college B
= > [(1400 + 1000 + 900 + 1800 + 2200 + 2600)/6] – 380
= > (9900/6) – 380
= > 1270
10) Answer: a)
Total number of students from college P, R and U together
= > 1400 + 900 + 2600 = 4900
Total number of students from college Q, S and T together
= > 1000 + 1800 + 2200 = 5000
Required % = [(5000 – 4900)/5000]*100 = 2 % less
