Dear Aspirants, Our IBPS Guide team is providing new series of Quants Questions for SBI Clerk/ IBPS Clerk/ ESIC UDC /MTS Prelims so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
1) If pipe A can fill a tank 3 times more faster than pipe B and both the pipes together can fill the tank in 4 hours 48 minutes, then how many hours will be taken by pipe B alone to fill the tank?
A.32 hours
B.24 hours
C.22 hours
D.16 hours
E.None of these
2) Pipe A and B are inlet pipes and pipe C is an outlet. Pipe A and B can fill the tank in 6 hours and 7.5 hours respectively and pipe C can empty the tank in 2 hours. If pipes A, B and C together are opened simultaneously, in how many hours the tank is filled/emptied completely?
A.4
B.5
C.6
D.3
E.None of these
3) P alone can do a work in 20 days while Q alone can do the same work in 25 days. P alone does the work for first 2 days and then Q joins. P and Q work together for the next 5 days and then P alone does the remaining work. How many days will P take to complete the remaining work?
A.3 days
B.5 days
C.7 days
D.9 days
E.None of these
4) Pipe A alone and pipe B alone can fill a tank in 12 mins and 18 mins respectively. Pipe A and B together started to fill the tank and after 5 minutes pipe B was closed. What is the time taken by pipe A to fill the remaining tank? (in mins)
A.3 1/3 mins
B.3 3/4 mins
C.2 2/3 mins
D.3 2/3 mins
E.5 1/2 mins
5) The cistern has inlet pipes P and Q and an outlet pipe R. Pipes P, Q can fill the cistern alone in 15 hours and 18 hours respectively and Pipe R can empty the cistern in 27 hours. In the first 5 hours, P and Q are opened together and then for the next 12 hours, pipe Q and R are opened together. How many hours Q alone can fill the remaining tank?
A.6 hours
B.8 hours
C.3 hours
D.5 hours
E.None of these
6) Two pipes A and B can fill a cistern in 15 mins and 20 mins respectively. Pipe C can empty the cistern in 10 mins. Initially, A and B are opened. After 5 minutes, C also opened. In how much time, the total cistern is filled?
A.15 mins
B.20 mins
C.25 mins
D.30 mins
E.None of these
7) Pipe A fills the tank in 24 hours and pipe B fills the tank in 36 hours and pipe C empties the tank in 40 hours. If pipes A, B and C are opened simultaneously, how many hours are required to fill the tank completely?
A.16.5 hours
B.18.5 hours
C.20.5 hours
D.22.5 hours
E.None of these
8) Pipe A and Pipe B can fill a cistern together in 8 hours. Pipe B is 25% more efficient than pipe A. Find the capacity of the cistern, if it is given that pipe A fills the cistern at a speed of 5 litre per minute.
A.90 litres
B.80 litres
C.40 litres
D.30 litres
E.None of these
9) Pipe A is an inlet pipe and pipe B is an outlet pipe and the ratio of the time taken by pipes A and B to fill or empty the tank is 3:4. If pipe C is an inlet pipe which alone fills the tank in 30 hours and pipe A and C together can fill the tank in 10 hours, in how many hours pipe A and B together can fill the tank?
A.50 hours
B.60 hours
C.80 hours
D.90 hours
E.100 hours
10) An inlet pipe can fill a tank in 48 minutes and an outlet pipe can empty the same tank in 144 minutes. If both pipes are opened together, then find the time required to fill the 5/12th of the tank.
A.25 hours
B.20 hours
C.30 hours
D.45 hours
E.None of these
Answers :
1) Answer: B
Efficiency of A : B= 4 : 1
Time ratio of A : B = 1 : 4
1/x + 1/4x = 5/24
(4+1)/4x = 5/24
5/4x = 5/24
x= 6 hours
Required time = 4x = 4*6 = 24 hours
2) Answer: B
A = 1/6
B = 1/7.5
C = 1/2
A + B + C = 1/6 + 1/7.5 – 1/2
= (5 + 4 – 15)/30
= -1/5
3) Answer: D
Total work = 100 units
P = 100/20 = 5 units/day
Q = 100/25 = 4 units/day
Total work done in 7 days = 5 * 2 + 5 * (5 + 4) = 55 units
Remaining work = 100 – 55 = 45 units
Days taken by P = 45/5 = 9 days
4) Answer: D
Let the capacity of tank = 36 units (LCM of 12 and 18)
Efficiency of Pipe A = 3 units/min
Efficiency of Pipe B = 2 units/min
Tank filled in 5 mins = 5 x (3 + 2) = 25 units
Time taken by A to fill the remaining tank = (36 – 25)/3 = 3 (2/3) mins
5) Answer: C
Let the total amount of work (LCM 15, 18 and 27) = 270
Work done by P alone in one hour = 18
Work done by Q alone in one hour = 15
Work done by R alone in one hour = -10
Work done by P and Q together in 5 hours=(18+15)*5=165
Work done by Q and R together in 12 hours=(15-10)*12=60
The pipe Q can fill the remaining cistern in = (270-165-60)/15=3 hours
6) Answer: C
Part of the cistern filled in 5 mins = 5 * (1/15 + 1/20) = 7/12
Remaining part = 1 – 7/12 = 5/12
Part of the cistern filled in 1 min, when all the pipes are opened = 1/15 + 1/20 – 1/10 = 1/60
1/60 part filled in 1 min.
5/12 part filled in 5/12 * 60 = 25 mins
7) Answer: D
A + B – C = 1/24 + 1/36 – 1/40
= (15 + 10 – 9)/360
= 2/45
Required time = 45/2 = 22.5 hours
8) Answer: A
Let pipe A fill the tank in x minutes
Pipe B can fill the tank in x*100/125 = 4x/5 minutes
1/x + 5/4x = 1/8
x=18 minutes
Capacity of cistern = 18*5 = 90 lit
9) Answer: B
Time ratio of A and B = 3:4
1/3x + 1/30 = 1/10
1/3x = 1/15
x = 5
B = 4 * 5 = 20
A and B together can fill the tank = 1/15 – 1/20 = 1/60
10) Answer: C
1/48 – 1/144 = (3 – 1)/144 = 2/144 = 1/72
The full tank will be filled in 72 hours
5/12th of the tank will be filled in 5/12 * 72 = 30 hours
This post was last modified on March 10, 2022 3:12 pm