Practice Quantitative Aptitude Questions For IBPS 2017 Exams (Application Problems & Quadratic Equation):
Dear Readers, Important Practice Aptitude Questions for IBPS Exams 2017 was given here with Solutions. Aspirants those who are preparing for the Bank Examination and other Competitive Examination can use this material.
- Average cost of 8 bags and 5 boxes is 25. While the average cost of 4 bags and 7 boxes is 21. What is the total cost of 18 bags and 18 boxes?
- 586
- 834
- 1112
- 724
- None of these
- Harish brother is 3 years elder than Harish. Harish father was 28 years of age when Harish sister was born while Harish mother was 26 years of age when Harish was born. If Harish sister was 4 years of age when Harish brother was born, then what was the age Harish father when Harish brother was born?
- 36 years
- 30 years
- 31 years
- 32 years
- None of these
- A rectangular solid metal which is 36 cm long, 18 cm broad and 3 cm high, is to be melted and cast into two different cubes, the volume of the bigger being eight times that of the smaller one. Find the surface area of the smaller cube.
- 180 cm^2
- 36 cm^2
- 144 cm^2
- 150 cm^2
- None of these
- Machine X can print one lakh books in 8 hours. Machine Y can print the same number of books in 10 hours while machine Z can print the same in 12 hours. All the machines started printing at 9 A.M. Machine X is stopped at 11 A.M. and the remaining two machines completed work. Approximately at what time will the printing of one lakh books be completed by the machines?
- 4 pm
- 30 pm
- 1 pm
- 12 am
- 30
- A bag contains 4 Red, 8 Black and 12 White balls. Three balls are drawn randomly. What is the probability that the balls drawn are of different colours?
- 48/253
- 16/253
- 24/253
- 12/253
- 205/253
Â
Directions (Q. 6-10): In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer
- if x > y
- if x ≥ y
- if x < y
- if x ≤ y
- if x = y or no relation can be established between x and y
- I. x^2 – 82x + 781 = 0 II. y^2 = 5041
- I. 6x^2 – 17x + 12 = 0 II. 7y^2 – 13y + 6 = 0
- I. 6x^2 – 47x + 80 = 0 II. 2y^2 – 9y + 10 = 0
- I. 2x^2 + x – 1 = 0 II. 2y^2 + 13y + 15 = 0
- I. x^2 + 12x + 32 = 0 II. 2y^2 + 15y + 27 = 0
Answer With Explanation:
- 8 bag + 5 box = 25 × 13 = 325
4 bag + 7 box = 21 × 11 = 231
12 bag + 12 box = 556
Total cost of 18 bags and 18 boxes
= 556 × 3 / 2
= 834
Answer is: b)
- Let Harish age = x
Then
Harish brother’s age = x + 3
Harish mother’s age = x + 26
Harish sister’s age = (x + 3) + 4 = x + 7
Harish Father’s age = (x + 7) + 28 = x + 35
Age Harish father when Harish brother was born = x + 35 – (x + 3) = 32
Answer is: d)
Â
- Volume of cuboid = volume of two cubes together
36 × 18 × 3 = a^3 + 8a^3
a^3 = 216
a = 6 cm
Surface area of the smaller cube = 6 × 6^2
= 216 cm^2
Answer is: e)
Â
- Work done by X in 1 hour = 1/8
Work done by Y in 1 hour = 1/10
Work done by Z in 1 hour = 1/12
Work done by X,Y and Z in 1 hour = 1/8 + 1/10 + 1/12 = 37/120
Work done by Y and Z in 1 hour = 1/10 + 1/12 = 22/120 = 11/60
From 9 am to 11 am, all the machines were operating.
Ie, they all operated for 2 hours and work completed = 2 × (37/120) = 37/60
Pending work = 1- 37/60 = 23/60
Hours taken by Y an Z to complete the pending work = (23/60) / (11/60) = 23/11
This is approximately equal to 2
Hence the work will be completed approximately 2 hours after 11 am ; ie around 1 pm
Answer is: c)
Â
- Total number of balls = 4 + 8 + 12 = 24
n(s) = 24C3 = 2024
Number of ways to select one ball of each colour
= n (E) = 4C1 × 8C1 × 12C1 = 4 × 8 × 12 = 384
P (E) = 384 / 2024
= 48 / 253
Answer is: a)
Â
- I. x^2 – 11x – 71x + 781 = 0
or x(x – 11) – 71(x – 11) = 0
or (x – 11) (x – 71) = 0
x = 11, 71
II. y^2 = 5041
y = +71, -71
No relation can be established between x and y.
Answer is: e)
Â
- I. 6x^2 – 9x – 8x + 12 = 0
or 3x(2x – 3) – 4(2x – 3) = 0
or (2x – 3) (3x – 4) = 0
x = 3/2, 4/3
II. 7y^2 – 7y – 6y + 6 = 0
or 7y(y – 1) – 6(y – 1) = 0
or (7y – 6) (y – 1) = 0
y = 1, 6/7
x > y
Answer is: a)
Â
- I. 6x^2 – 15x – 32x + 80 = 0
or 3x(2x – 5) – 16(2x – 5) = 0
or (3x – 16) (2x – 5) = 0
x = 16/3, 5/2
II. 2y^2 – 4y – 5y + 10 = 0
or 2y(y – 2) – 5(y – 2) = 0
or (y – 2) (2y – 5) = 0
y = 2, 5/2
x ≥ y
Answer is: b)
Â
- I. 2x^2 + 2x – x – 1 = 0
or 2x(x + 1) – 1(x + 1) = 0
or (2x – 1) (x + 1) = 0
x = –1, 1/2
II. 2y^2 + 3y + 10y + 15 = 0
or y(2y + 3) + 5(2y + 3) = 0
or (y + 5) (2y + 3) = 0
y = –5, – 3/2
x > y
Answer is: a)
Â
- I. x^2 + 4x + 8x + 32 = 0
or x(x + 4) + 8(x + 4) = 0
or (x + 4) (x + 8) = 0
x = –4, –8
II. 2y^2 + 6y + 9y + 27 = 0
or 2y(y + 3) + 9(y + 3) = 0
or (2y + 9) (y + 3) = 0
y = – 9/2, –3
No relation can be established between x and y.
Answer is: e)
