Crack SBI Clerk / Canara Bank PO 2018 – Logical Reasoning (Coding Decoding and Inequality) Day-18

Crack SBI Clerk / Canara Bank PO 2018 – Logical Reasoning (Coding Decoding and Inequality) Day-18:

Dear Readers, Reasoning Section play a vital role in Banking and all other competitive exams. This year 2018 was started with three wonderful opportunities; Canara Bank PO Exam and Most Awaited SBI Clerk 2018. To enrich your preparation here we have providing new series of Practice Questions on Reasoning Ability – Coding Decoding and Inequality. Candidates those who are going to appear in Bank Exams 2018 can practice these questions daily and make your preparation effective.

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Daily Practice Test Schedule | Good Luck

Topic	Daily Publishing Time
Daily News Papers & Editorials	8.00 AM
Current Affairs Quiz	9.00 AM
Logical Reasoning	10.00 AM
Quantitative Aptitude “20-20”	11.00 AM
Vocabulary (Based on The Hindu)	12.00 PM
Static GK Quiz	1.00 PM
English Language “20-20”	2.00 PM
Banking Awareness Quiz	3.00 PM
Reasoning Puzzles & Seating	4.00 PM
Daily Current Affairs Updates	5.00 PM
Data Interpretation / Application Sums (Topic Wise)	6.00 PM
Reasoning Ability “20-20”	7.00 PM
English Language (New Pattern Questions)	8.00 PM
General / Financial Awareness Quiz	9.00 PM

Direction (1-5) Study the information below and answer the following question.

In a certain code language

‘We try to make’ means‘ja sa ra pa’,

 ‘Make it for good’ means ‘na ta pa ma’,

‘We are good boys’ means ‘ek ma ki ra’,

‘Boys try to respect’ means ‘ki ja sa ca’

1) Which of the following is the code for ‘to try’?

a)Ja ta

b) sa ja

c) sa ki

d) ca ek

e) none

2)What may be the possible code for‘Respect everyone’?

a)di na

b) ca ek

c) ma pa

d) na ra

e) ca di

3) Which of the following is the code for ‘are’?

a)Ki

b) ja

c) ek

d)di

e)zi

4)What is the code for ‘Try to good’?

a)Ja sa ma

b) zi mz ra

c)di  ma sa

d) ja sa di

d) ja zi di

e) none of these

5)Which of the following represents the code ‘ra ek’?

a)it for

b) boys make

c)we are

d)respect for

e) be good

solution:

1)Answer: b

2) Answer: e

3) Answer: c

4) Answer: a

5) Answer: c

 

Directions (6-10):In the question below relationship between different elements is shown in the statements. The statements are followed by two conclusions.

1. If only conclusion I Follows
2. If only conclusion II Follows
3. If either conclusion I or II Follows
4. If neither conclusion I nor II Follows
5. If both conclusions I and II Follows

6)Statement: P≤R=S; T>S=U

Conclusion:

1. U≥P
2. P<T

7)Statement: A>B=C; C≥D; D>E; E<F

Conclusion:

1. C>E
2. D≤A

8)Statement:  D>F≥H>J≤L≤N<P

Conclusion:

1. F>N
2. P>J

9)Statement: Z≥A>C=K; K<A<M

Conclusion:

1. M<Z
2. Z>K

10)Statement: Z≥A>C=K; K<A<M

Conclusion:

1. C>K
2. Z<M

Solution:

6) Answer: e

7) Answer: a

8) Answer: b

9) Answer: b

10) Answer: d

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