Quadratic equation questions for bank clerk prelims pdf is available here. The quadratic equation questions are frequently asked in the bank clerk prelims exams. You can expect around 5 marks from the quadratic equation. If you practice well, you can score 5 marks in around 2 to 3minutes. On continuous practice, you can gain speed in solving quadratic equation questions. So, practice more using the Quadratic equation questions for bank clerk prelims pdf. Here you can learn more shortcut tricks. So, practice in a daily manner with the quadratic equation pdf.
In this question, 2 equations based on x and y will be given. You have to find the values of x and y. Then you have to compare both values and answer all the questions. Practice more Quadratic equation questions and learn tricks to solve various types of questions.
Banking & Insurance Exam Study Materials
How to Solve Quadratic Equation?
Here we have discussed some important tips to solve the Quadratic equation questions for bank clerk prelims.
- Know the quadratic equation formula.
- With the formula, factorize the given equations.
- You can also follow shortcuts to factorize the given equations.
- Find the values of x and y.
- Compare the values and answer the questions.
So, candidates practice well using the Quadratic equation questions for bank clerk prelims pdf. So, you can easily find the x, y values quickly. These questions will help you to save more time for other time consuming topics.
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Directions (01-10): Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,
1) I)Â 2x + 3y = 47
II)3x + 2y = 48
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
2) I)Â x2Â – 23x + 120 = 0
II)y2– 14y + 48 = 0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
3) I)Â x2Â + 20x + 99 = 0
II)y2– 12y – 189 = 0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
4) I) 2x2 – 15x + 18 = 0
II)3y2– 11y + 10 = 0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
5) I) x2 – 17x + 42 =0
II)y2– 19y + 70 = 0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
6) I) x2 – 14x + 45 = 0
II) y2–20y + 99 = 0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
7) I)Â 2x2Â – 13x + 18 = 0
II)Â y2– 13y + 42 = 0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
8) I) x2 + 10x – 96 = 0
II)Â y2+ 23y + 112 = 0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
9) I)Â 2x2Â – 10x + 12 = 0
II) y2– y -2 = 0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
10) I)Â 2x2Â – 30x + 112 = 0
II)Â y2– 18y + 80 = 0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
Answers :
1) Answer: A
2x + 3y = 47——-(1)
3x + 2y = 48———(2)
(1) * 3 – (2) * 2
5y = 45
y = 9
2x = 47 – 27
x = 10
x > y
2) Answer: B
x2Â – 23x + 120 = 0
x2 – 15x – 8x + 120 = 0
x(x – 15) – 8(x – 15) = 0
(x – 8)(x – 15) = 0
x = 8, 15
y2 – 14y + 48 = 0
y2 – 8y – 6y + 48 = 0
y(y – 8) – 6(y – 8) = 0
(y – 6)(y – 8) = 0
y = 6, 8
x ≥ y
3) Answer: E
x2Â + 20x + 99 = 0
x2Â + 11x + 9x + 99 = 0
x(x + 11) + 9(x + 11) = 0
(x + 9)(x + 11) = 0
x = -9, -11
y2 – 12y – 189 = 0
y2 – 21y + 9x – 189 = 0
y(y – 21) + 9(x – 21) = 0
(y + 9)(y – 21) = 0
y = -9, 21
x ≤ y
4) Answer: C
2x2 – 15x + 18 = 0
2x2 – 12x – 3x + 18 = 0
2x(x – 6) – 3(x – 6) = 0
(2x – 3)(x – 6) = 0
x = 3/2, 6
3y2 – 11y + 10 = 0
3y2 – 6y – 5y + 10 = 0
3y(y – 2) – 5(y – 2) = 0
(3y – 5)(y – 2) = 0
y = 2, 5/3
Relationship between x and y cannot be established.
5) Answer: C
x2 – 17x + 42 =0
x2 – 14x – 3x + 42 = 0
x(x – 14) – 3(x – 14) = 0
(x – 3)(x – 14) = 0
x = 3, 14
y2 – 19y + 70 = 0
y2 – 14y – 5y + 70 = 0
y(y – 14) – 5(y – 14) = 0
(y – 5)(y – 14) = 0
y = 5, 14
Relationship between x and y cannot be established.
6) Answer: E
x2 – 14x + 45 = 0
x2 – 9x – 5x + 45 = 0
x(x – 9) – 5(x – 9) = 0
(x – 5)(x – 9) = 0
x = 5, 9
y2 – 20y + 99 = 0
y2 – 11y – 9y + 99 = 0
y(y – 11) – 9(y – 11) = 0
(y – 9)(y – 11) = 0
y = 9, 11
x ≤ y
7) Answer: D
2x2Â – 13x + 18 = 0
2x2 – 9x – 4x + 18 = 0
2x(x – 2) – 9(x – 2) = 0
(2x – 9)(x – 2) = 0
x = 9/2, 2
y2Â – 13y + 42 = 0
y2 – 6y – 7y + 42 = 0
y(y – 6) – 7(y – 6) = 0
(y – 7)(y – 6) = 0
y =7, 6
x < y
8) Answer: C
x2+ 10x – 96 = 0
x2+ 16x – 6x – 96 = 0
x(x + 16) – 6(x + 16) = 0
(x – 6)(x + 16) = 0
x = 6, -16
y2Â + 23y + 112 = 0
y2Â + 16y + 7y + 112 = 0
y(y + 16) + 7(y + 16) = 0
(y + 7)(y + 16) = 0
y = -7, -16
Relationship between x and y cannot be established.
9) Answer: B
2x2Â – 10x + 12 = 0
2x2 – 6x – 4x + 12 = 0
2x(x – 3) – 4(x – 3) = 0
(2x – 4)(x – 3) = 0
x = 2, 3
y2 – y – 2 = 0
y2 – 2y + y – 2 = 0
y(y – 2) + 1(y – 2) = 0
(y + 1)(y – 2) = 0
y = -1, 2
x ≥ y
10) Answer: E
2x2Â – 30x + 112 = 0
2x2 – 16x – 14x + 112 = 0
2x(x – 8) – 14(x – 8) = 0
(2x – 14)(x – 8) = 0
x = 8, 7
y2Â – 18y + 80 = 0
y2 – 10y – 8y + 80 = 0
y(y – 10) – 8(y – 10) = 0
(y – 8)(y – 10) = 0
y = 8, 10
x ≤ y
Quadratic Equation Questions For Bank Clerk Prelims Exam 2022 pdf
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