Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June 2018. To enrich your preparation here we have providing new series of Ages – Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.
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Answers:
Raju’s present age = 17 years
After 5 years, Jegan’s father’s age = 3*Raju’s age
= > 3*17 = 51 years
Present age of Jegan’s father = 46 years
Jegan’s present age = (1/5)* Jegan’s father’s age after 4 years
= > J = (1/5)*50
= > J = 10
Jegan’s present age = 10 years
The present age of Gowtham and Mano = 42 : x
Mano = Gayathri – 8
Gayathri’s age = 32 – 7 = 25 years
Mano = 25 – 8 = 17
Gowtham’s age – Mano’s age = Gayathri’s age
Gowtham’s age = 17 + 25 = 42
The value of x = 17 years
Let the ages of 3 daughters be x, y and z
According to the question,
x+y+z+24 = 85
x + y + z = 85-24 = 61
Possible square numbers are, 1, 4, 9, 16, 25, 36, 49
So,
The ages are, 9, 16 and 36
The age of Moni = 36, Sree = 16 and Subha = 9 years
The age of Moni, 3 years ago = 33 years
The ratio of present age of Nivetha and Renuka = 3 : 5
Nivetha = Banu – 7
After 8 years, Banu’s age = 30
Present age of Banu = 22
Nivetha = 22 – 7 = 15
3’s = 15
1’s = 5
Present age of Renuka = 5’s = 25 years
Let the age of Saaru and her father be x and y,
2x + y = 79–>(1)
X + 2y = 104 –>(2)
By solving (1) and (2),
Y = 43, X = 18
The average age of Saaru and her father and mother = 32
Sum of the ages of Saaru and her father and mother = 32*3 = 96
Present age of Saaru’s mother = 96 – (43 + 18) = 35 years
Let the age of Vasu be x,
Sum of the ages of Vasu, Ravi, Chitra and Naveen = 78
Vasu + Ravi + Chitra + Naveen = 78
Vasu = Ravi + 5
Chitra = Naveen + 3
Vasu = 9*Naveen
According to the question,
= > x + x – 5 + (x/9) + 3 + (x/9) = 78
= > 2x +(2x/9) = 80
= > 20x = 720
= > x = 36
Vasu = 36 years
Chitra = (Vasu/9) + 3 = (36/9) +3 = 7 years
The present ratio of age of A and B = 5: 6
8 years hence, the ratio of age of A and B = 7: 8
According to the question,
(5x + 8)/(6x + 8) = (7/8)
40x + 64 = 42x + 56
2x = 8
X = 4
The present age of A = 20, the present age of B = 24
Required sum = 20 + 24 = 44 years
The sum of the present age Raji and her son = 70 years
Raji + Raji’s son = 70
15 years ago, the ratio of the age of Raji and her son = 3: 1
According to the question,
3x + 15 + x + 15 = 70
4x = 70 – 30
4x = 40
X = 10
Present age of Raji’s son = x + 15 = 25 years
Ashok got married 14 years ago,
Present age of Ashok = (7/5)*Ashok’s age at the time of marriage
Present age of Ashok: Ashok’s age at the time of his marriage = 7: 5
= > 2’s = 14
= > 1’s = 7
Present age of Ashok = 7’s = 49
Ashok’s brother = Ashok – 10 = 49 – 10 = 39 years
The age of Ashok’s brother at the time of his marriage = 39 – 14= 25 years
5 years ago, the ratio of age of the father and his son = 3: 1(3x, x)
7 years hence, the ratio of age of the father and his son = 19: 9
According to the question,
(3x + 12)/(x + 12) = (19/9)
27x + 108 = 19x + 228
8x = 120
X = 15
The present age of the father and his son = (3x + 5), (x + 5) = 50, 20
The average Present age of the father, mother, son and daughter = 30
Total Present age of the father, mother, son and daughter = 30*4 = 120
Total present age of the mother and her daughter = 120 – 70 = 50
Let the present age of mother and daughter be A and B,
A + B = 50—>(1)
A – B = 30—>(2)
By solving the equation (1) and (2),
A = 40, B = 10
The present age of the daughter = 10 years
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Current Affairs Quiz | 9.00 AM |
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Quantitative Aptitude “20-20” | 11.00 AM |
Vocabulary (Based on The Hindu) | 12.00 PM |
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This post was last modified on September 22, 2020 4:50 pm