Quantitative Aptitude Questions (Ages) for SBI Clerk 2018 Day- 117

Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June 2018. To enrich your preparation here we have providing new series of Ages- Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.

Click “Start Quiz” to attend these Questions and view Solutions

Click here to view Quantitative Aptitude Questions in Hindi

1. Three years ago, the average age of Ravi‘s family, having 6 members, was 16 years. Ravi becomes father but the average age of his family is same today. What is the present age of baby?

1. 2 years
2. 4 years
3. 3 years
4. 1 year
5. None of these

2. One year ago, the ratio of age of Rani and Yamuna is 2: 3. 5 years hence, their ratio will be 8: 11. Find the present age of Rani?

1. 15 years
2. 17 years
3. 23 years
4. 19 years
5. None of these

3. Average of the ages of A, B, C and D, four years ago was 36 years. Average of the present ages of C, D, E and F is 43 years. The average age of E and F after four years will be 44 years. Find the average of the present ages of A and B.

1. 30 years
2. 40 years
3. 34 years
4. 45 years
5. None of these

4. 5 years ago, the age of a man was 3 years more than 4 times his son’s age. After 3 years the man will be 6 years less than thrice the age of his son. After how many years will the sum of their ages be 80 years?

1. 12 years
2. 16 years
3. 14 years
4. 10 years
5. None of these

5. 5 years ago, the ratio of age of A and B is 3: 2. C is 7 years younger than A. The present age of C is 4 times of D’s present age. Find the present age of B, if the age of D, after 6 years is 13 years?

1. 25 years
2. 23 years
3. 21 years
4. 27 years
5. None of these

6. 5 years ago, the ratio of age of A and B is 2: 3. The average present age of A, B and C together is 28. C is 11 years younger than B. Find the present age of C?

1. 28 years
2. 24 years
3. 20 years
4. 32 years
5. None of these

7. The difference between the ages of Rohit and Agila, 3 years ago was 12 years. If the ratio of their ages 9 years hence is 7:4, then find the present age of Rohit’s mother who is 25 years older than Rohit?

1. 34 years
2. 45 years
3. 31 years
4. 44 years
5. 22 years

8. The ratio between the ages of two persons A and B is 2:5. If the difference between their ages is 18 years then find the age of another person C if the average age of all the persons five years hence will be 30 years?

1. 25
2. 18
3. 33
4. 30
5. None of these

9. The Average Present age of Anitha and Arjun is 23 years. The ratio between their ages, after 5 years will be 4: 3, then find the age of Arjun?

1. 25
2. 19
3. 22
4. 30
5. None of these

10. The ratio of present age of B and C is 3: 1. The present age of A is equal to the square of the present age of C. Find the present age of A, if sum of present age of A, B and C is 45 years?

1. 25 years
2. 28 years
3. 31 years
4. 33 years
5. None of these

Answers:

1.Answer a

The age of 6 members 3 years ago = 6 * 16 = 96 years

Total age of 6 members at present= 96 + (6×3) = 114 years

Total age of 7 members at present =7×16=112 years…

The age of baby = 114 – 112 = 2 years

2.Answer d

One year ago, the ratio of age of Rani and Yamuna = 2: 3(2x, 3x)

5 years hence, their ratio will be = 8: 11

According to the question,

(2x + 6)/(3x+ 6) = (8/11)

22x + 66 = 24x + 48

2x = 18

X = 9

The present age of Rani = 2x + 1 = 19 years

3.Answer c

Sum of the Present ages of A, B, C and D

= > (36*4) + (4*4) = 160 years

Sum of the Present ages of C, D, E and F

= > 43*4 = 172 years

Sum of the Present ages of E and F

= > (44*2) – 8 = 80 years

Sum of the Present ages of C and D

= > 172 – 80 = 92 years

Sum of the Present ages of A and B

= > 160 – 92 = 68 years

Required average = 68/2 = 34 years

4.Answer b

Let the present age of man and son be x and y,

(x – 5) = 4(y – 5) + 3

(x – 5) = 4y – 20 + 3

X – 4y = -12 -à (1)

(x+3) = 3(y+3) – 6

X +3 = 3y + 9 – 6

X – 3y = 0 -à (2)

Solving (1) and (2),

Y = 12, x = 36

Sum of present age of man and son = 12 + 36 = 48

After 16 years, Sum = 48 + 32 = 80 years

5.Answer a

5 years ago, the ratio of age of A and B = 3: 2 (3x, 2x)

The present age of A and B = 3x + 5, 2x + 5

Present age of C = Present age of A – 7

Present age of D = 13 – 6 = 7

Present age of C = 4 * present age of D

= > 4*7 = 28 years

Present age of A = 28 + 7 = 35 years

3x + 5 = 35

3x = 30

X = 10

The present age of B = 2x + 5 = 25 years

6.Answer b

5 years ago, the ratio of age of A and B = 2: 3(2x, 3x)

The average present age of A, B and C together = 28

Total present age of A, B and C = 28*3 = 84 years

Present age of C = Present age of B – 11

Present age of C = 3x + 5 – 11 = 3x – 6

According to the question,

2x + 3x + 10 + 3x – 6 = 84

8x + 4 = 84

8x = 80

X = 10

Present age of C = 3x – 6 = 30 – 6 = 24 years

7.Answer d

3 years ago, Rohit – Agila = 12

9 years hence, the ratio of Rohit and Agila = 7: 4 (7x, 4x)

Present age of Rohit and Agila = 7x – 9, 4x – 9

According to the question,

7x – 4x = 12

3x = 12

X = 4

Present age of Rohit = 7x – 9 = 19

Present age of Rohit’s mother = 19 + 25

= > 44 years

8.Answer c

Let the present age of C be x,

The ratio of the ages of two persons A and B = 2: 5(2x, 5x)

5x – 2x = 18

3x = 18

X = 6 years

A’s present age = 6*2 = 12 years

B’s present age = 6*5 = 30 years

Total present ages of A, B and C = 30*3 = 90 years

According to the question,

12 + 30 + x + 15 = 90

X = 90 – 57 = 33

Present age of C = 33 years

9. Answer b

Total present age of Anitha and Arjun = 23*2 = 46 years

After 5 years, their ratio will be = 4: 3(4x, 3x)

According to the question,

7x – 10 = 46

7x = 56

X = 8

Present age of Arjun = 3x – 5 = 24 – 5 = 19 years

10.Answer a

The ratio of present age of B and C = 3 : 1 (3x, x)

The present age of A = (Present age of C)² = x²

Sum of present age of A, B and C = 45 years

3x + x + x² = 45

X² + 4x – 45 = 0

(x + 9) (x – 5) = 0

X = 5, -9(-9 will be eliminated)

Present age of A = x² = 25 years

 

Daily Practice Test Schedule | Good Luck

Topic	Daily Publishing Time
Daily News Papers & Editorials	8.00 AM
Current Affairs Quiz	9.00 AM
Quantitative Aptitude “20-20”	11.00 AM
Vocabulary (Based on The Hindu)	12.00 PM
General Awareness “20-20”	1.00 PM
English Language “20-20”	2.00 PM
Reasoning Puzzles & Seating	4.00 PM
Daily Current Affairs Updates	5.00 PM
Data Interpretation / Application Sums (Topic Wise)	6.00 PM
Reasoning Ability “20-20”	7.00 PM
English Language (New Pattern Questions)	8.00 PM

Click Here for More Quantitative Aptitude Questions