Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June 2018. To enrich your preparation here we have providing new series of Ages- Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.
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Answers:
1.Answer b
4 years ago, the ratio of the ages of Arun and Praveen = 8: 7 (8x, 7x)
Present ages of Arun and Praveen = 8x + 4, 7x + 4
Present age of Raju = (1/6)*Arun’s present age + 12
Arun’s present age = 36 years
8x = 32
x = 4
Praveen’s present age = 7x + 4 = 32
Raju’s present age = (1/6)*36 + 12 = 18
Required ratio = 32: 18 = 16: 9
2.Answer d
The present age of Kala and her husband = 4 : 5 (4x, 5x)
The present age Kala’s daughter = (1/3)*Kala’s present age
Kala’s daughter = Kala’s son – 3
Kala’s son after 5 years = 20 years
Kala’s son’s present age = 15 years
Kala’s daughter = 15 – 3 = 12 years
Kala’s present age = 3*12 = 36 years
4’s = 36
1’s = 9
Present age of Kala’s husband = 5x = 45 years
Required difference = 45- 36 = 9 years
3.Answer a
Ratio of present ages of Sri and Gowtham = 5:7 (5x, 7x)
Rajesh = Sri + 5 = 5x + 5
Rajesh = Gowtham – 1 = 7x – 1
According to the question,
5x + 5 = 7x – 1
7x – 5x = 6
2x = 6
X = 3
Present age of Sri = 5x = 15
Present age of Gowtham = 7x = 21
Required sum = 15 + 21 = 36 years
4.Answer c
The ratio of B’s age six years hence to C’s present age = 4: 3 (4x, 3x)
Present age of B and C = 4x – 6, 3x
A = 2*C = 2*3x = 6x
B = A – 14
4x – 6 = 6x – 14
14 – 6 = 6x – 4x
2x = 8
X = 4
C’s age 2 years ago = 3x – 2 = 12- 2 = 10 years
5.Answer b
3 years ago, the ratio between the ages of Asha and Ragu = 3 : 4 (3x, 4x)
Praveen = Ragu + 6
Asha’s age, after 4 years = 25
Asha’s present age = 21 years
3x + 3 = 21
3x = 18
X = 6
Ragu’s present age = 4x + 3 = 27 years
Present age of Praveen = 27 + 6 = 33 years
6.Answer c
Let the age of Anusha and Nisha be x and y respectively,
x*y = 300
2*x = y + 10
X = (y + 10)/2
[(y + 10)/2]*y = 300
Y2 + 10y = 600
Y2 + 10y – 600 = 0
(y – 20) (y + 30) = 0
Y = 20, -30 (-30 will be eliminated)
Anusha’s age = 300/20 = 15 years
7.Answer a
Let the present ages of Ram and his wife are 5x and 4x respectively.
(5x – 5)/(4x – 5) = 9/7
=> 35x – 35 = 36x – 45
=> x = 10
Present age of Ram = 5x = 50 years
Present age of his wife = 4x = 40 years
Let after y years ratio of their ages will be 6: 5,
(50 + y)/(40 + y) = 6/5
=> 250 + 5y = 240 + 6y
=> y = 250 – 240
=> y = 10 years
8.Answer d
4 years ago, the ratio of ages of Raghav and Karuna = 2: 3(2x, 3x)
Karuna’s age after 5 years = 27 years
Karuna’s present age = 22 years
3’s = 18
1’s = 6
Raghav’s present age = 2x + 4 = 16 years
According to the question,
16 + 22 = 7 + Meena’s present age
38 – 7 = Meena’s present age
Meena’s present age = 31 years
9.Answer b
The ratio of present ages of Sanjay and Anand = 5: 4 (5x, 4x)
3 years hence, their ratio will become = 11: 9
According to the question,
(5x + 3)/(4x + 3) = (11/9)
45x + 27 = 44x + 33
X = 6
Sanjay’s present age = 5x = 30 years
Present age of Priyanka = 30/2 = 15 years.
10.Answer c
The ratio of present age of Meena and her son’s age = 3 : 1 (3x, x)
Meena’s present age = (2/5)*Meena’s father’s present age
Meena’s father’s present age = (15/2)x
According to the question,
x + 3x + (15/2) x = 138
(2x + 6x + 15x)/2 = 138
23x = 138*2
x = 12
Required difference = 90 – 12 = 78 years
Daily Practice Test Schedule | Good Luck
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Current Affairs Quiz | 9.00 AM |
Quantitative Aptitude “20-20” | 11.00 AM |
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This post was last modified on June 26, 2021 8:58 am