Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June 2018. To enrich your preparation here we have providing new series of Average – Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.
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Answers:
1). Answer b
Let newly joined students be x,
According to the question,
60*5 = (60 + x)*4
300 = 240 + 4x
60 = 4x
X = 15
The newly joined students in the class = 15
2). Answer c
= > 3 : 1
The number of girls in the class = 16
1’s = 16
3’s = 48
The number of boys in the class = 48
3). Answer d
The total present age of the family of 5 members = (23*5) + (4*5) = 135
A baby is born now; the average age of the family is same as before.
The total present age of the family of 6 members (Including the baby)
= > 23*6 = 138
The age of the baby = 138 – 135 = 3 years
4). Answer a
Total age of 25 students and teacher = 26*15 = 390
Total age of 25 students = 25*14 = 350
The age of the teacher = 390 – 350 = 40
Shortcut:
N Average
26 15
25 14
N is decreased by 1 and at the same time average also decreased by 1.
Then, the shortcut is,
The age of the teacher = (26 + 14) or (25 + 15) = 40 years
5). Answer c
Let passed candidates be x,
So, Failed candidates = 240 – x
Total marks,
(240*70) = 78x + (240 – x)*30
16800 = 78x + 7200 – 30x
9600 = 48x
X= 9600/48 = 200
Total no of passed candidates in the examination is 200.
6). Answer d
The average marks scored by 12 students = 73
Total marks scored by 12 students = (73*12) = 876
If the scores of Ajay, Akhil and Alok are included, the average becomes 73.6
Total marks scored by 15 students = (73.6*15) = 1104
The scores of Ajay, Akhil and Alok = 1104 – 876 = 228
Ajay = 68 marks, Alok = Akhil + 6
Alok – Akhil = 6 –à (1)
Alok + Akhil = 160-à (2)
Solving (1) and (2),
Alok = 83
Akhil = 77 marks
7). Answer a
Total age of all the members of the family= 30*5= 150 years
Total age of the four members at the time of birth of youngest= 150- 10*5= 100 years.
Required average of family= 100/4= 25 years.
8). Answer d
Total cost of mobiles A, B and C= 30000*3 = Rs. 90000
Average cost of A, B, C and D= 30000*(80/100) = Rs. 24000
Total cost four mobile= 24000*4 = Rs. 96000
Cost of mobile D= 96000-90000 = Rs. 6000
9). Answer b
Total ages of 6 family members, 3 years ago
= > 6*40= 240 years
Total ages of the family at present including daughter
= > 240+18= 258
Total ages of the family including daughter-in-law
= > 39*6
= > 234 years
So,
Required difference= 258-234= 24 years.
10). Answer c
Praveen = 18 + 48 = 66
Sneha = 66 – 6 = 60
Prakash = 60 – 4 =56
Jothi = (48*3) – (60 + 56) = 28
So total mark of Jothi + Prakash = 56 + 28 = 84
Daily Practice Test Schedule | Good Luck
| Topic | Daily Publishing Time |
| Daily News Papers & Editorials | 8.00 AM |
| Current Affairs Quiz | 9.00 AM |
| Quantitative Aptitude “20-20” | 11.00 AM |
| Vocabulary (Based on The Hindu) | 12.00 PM |
| General Awareness “20-20” | 1.00 PM |
| English Language “20-20” | 2.00 PM |
| Reasoning Puzzles & Seating | 4.00 PM |
| Daily Current Affairs Updates | 5.00 PM |
| Data Interpretation / Application Sums (Topic Wise) | 6.00 PM |
| Reasoning Ability “20-20” | 7.00 PM |
| English Language (New Pattern Questions) | 8.00 PM |
This post was last modified on March 18, 2022 8:49 am