Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June/July 2018. To enrich your preparation here we have providing new series of Data Interpretation – Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.
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Topic | Daily Publishing Time |
Daily News Papers & Editorials | 8.00 AM |
Current Affairs Quiz | 9.00 AM |
Logical Reasoning | 10.00 AM |
Quantitative Aptitude “20-20” | 11.00 AM |
Vocabulary (Based on The Hindu) | 12.00 PM |
Static GK Quiz | 1.00 PM |
English Language “20-20” | 2.00 PM |
Banking Awareness Quiz | 3.00 PM |
Reasoning Puzzles & Seating | 4.00 PM |
Daily Current Affairs Updates | 5.00 PM |
Data Interpretation / Application Sums (Topic Wise) | 6.00 PM |
Reasoning Ability “20-20” | 7.00 PM |
English Language (New Pattern Questions) | 8.00 PM |
General / Financial Awareness Quiz | 9.00 PM |
Directions (Q. 1-5) Study the following table carefully and answer the given questions:
Table below shows different Rate of Interest offered by three schemes:-
Name | Scheme A | Scheme B | Scheme C |
Amit | 10 | 10 | 12 |
Sumit | 8 | 12 | 15 |
Vineet | 6 | 16 | 18 |
Sujan | 9 | ———– | 6 |
NOTE:
Directions (Q. 6-10) Study the following bar graph carefully and answer the given questions:
Bar Graph shows time taken by 5 different pipes to fill a tank:-
Table above shows time taken by 5 different pipes to empty a tank.
Pipe A | 15 |
Pipe B | 10 |
Pipe C | 16 |
Pipe D | 8 |
Pipe E | 10 |
All the units are in Hours.
Answers:
Directions (Q. 1-5)
Explanation:
Let the sum invested in both the schemes be X
Then
X*8*4/100 + X*12*4/100 = 1500
32X/100 + 48X/100= 1500
80X/100=1500
X= 1500*100/80
X= 1875
Money Invested in scheme A and B= Rs 1875 (Investment is same)
Therefore,
Money invested in scheme C= 1875/25*15 (Ratio Given)
= 1125
Interest earned in Scheme C= 1125*4*15/100
= Rs 675
2.Answer a
Let the Money Invested in scheme C be X
Now,
=1800* 100 / 4*6 (Interest earned in scheme C is twice the Scheme B)
= Rs 7500
Money invested in Scheme C = Rs 7500
Money Invested in Scheme B = 7500/15*7
= Rs 3500
Rate of Interest in Scheme B= 900*100/3500*4
= 6.42%
let the principal invested in scheme C is X
X*12*4/100=1200
X= 1200 *100/48
=2500
Therefore, Interest received from Scheme A =Rs 2500
Money Invested =2500*100/4*10
= Rs 6250
Therefore,
Money invested in Scheme A= Rs 6250
Simple Interest earned by Amit in Scheme A= 15000*2*10/100
= Rs 3000
Compound Interest earned by Amit in Scheme C =15000{(1+12/100)^2-1)}
= Rs 3816
Difference = Rs (3816-3000) = Rs 816
let the money invested in Scheme A be X, Scheme B = 10000-X
X*4*6/100+ 16*4(10000-x)=5000
24x/100 + 640000-64X/100 =5000
-40X + 640000/100= 5000
-40X+640000= 500000
40X=140000
X= 3500
Therefore,
Interest earned in Scheme B= 6500*16*4/100
=Rs 4160
Directions (Q. 6-10)
Total units of work = 75 (LCM of 25 and 15)
Work units done by both the pipes in 1 hour = 8
Work units done in 1 hour with ¾ of their actual efficiency= ¾ of 8 = 6
Time required to fill the tank= 75/6 = 12.5 hours.
Total units of work= 60
Units of worked done in 1 hour = (3+4)-4
= 3
Time required to fill 40% of the tank= 24/3
= 8 hours
Total Units of work= 240
Units of work done in 1 hour = (24+16)-15
= 25
Units of work done in 27 hours alternatively = 9 *25
= 225
Remaining units needs to be done by A= 15/24
= 5/8
Total time required= 27+5/8
= 27.625 hours
Total units of work= 50
Units of work done in 1 hour= 7
Time required to fill 56% of the tank by A and D= 28/7
= 4 hours
Time required to fill the remaining tank by A = 22/2
= 11 hours
Total time required = 4+11
= 15 hours.
Total units of work= 300
A and C will be opened for 10 hours
So, work done by A and C = (12+15) * 10
= 270
So, B should be opened for remaining units= (300-270)/ 20
= 1.5 hours.
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This post was last modified on June 15, 2021 5:38 pm