Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June 2018. To enrich your preparation here we have providing new series of Data Interpretation – Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims and IDBI Executive Exams can practice these Quantitative Aptitude average questions daily and make your preparation effective.
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Directions (Q. 1-5) Read the following information carefully and answer the following questions carefully.
1. Inlet pipes A, B and outlet pipe S took 10 hours to fill the empty tank then find how much time Pipe S will take to empty a full tank?
a) 24(1/9)
b) 18(7/13)
c) 18(6/23)
d) 1(2/7)
e) 4(8/9)
2. Inlet pipe E and outlet pipe Q can fill the empty tank in 42 hours then how much time is required for inlet pipe C if it is opened with outlet Q to fill the tank?
a) 24(1/9)
b) 18(7/13)
c) 15(3/4)
d) 21(21/29)
e) 4(8/9)
3. Inlet pipes B, C and D were opened to fill tank so after how much time pipe C should be closed so that the tank gets filled in 8 hours?
a) 24(1/9)
b) 18(7/13)
c) 1(5/7)
d) 1(2/7)
e) 4(8/9)
a) 25
b) 18
c) 15
d) 24
e) 48
5. The time taken by inlet pipe D and outlet pipe P to fill the tank is 2 hours less than time taken by inlet pipe C and outlet S to fill the tank then find the time required by outlet pipe S to empty the full tank if the outlet pipe P can empty the full tank in 40 hours?
a) 24(1/9)
b) 25(4/11)
c) 15(3/4)
d) 1(2/7)
e) 4(8/9)
Directions (Q. 6 – 10): Study the following information carefully and answer the questions given below:
The following bar graph represents number of days taken by husbands and wives of six different families to complete a piece of work.
a) 4(54/143) days
b) 4(58/143) days
c) 3(58/143) days
d) 4(58/141) days
e) None of these
a) 200%
b) 220%
c) 280%
d) 100%
e) None of these
a) 5(4/167) days
b) 4(4/167) days
c) 3(4/167) days
d) 4(3/167) days
e) None of these
a) 7(19/35) days
b) 5(19/35) days
c) 3(19/35) days
d) 5(19/35) days
e) None of these
a) 3(7/17) days
b) 3(9/17) days
c) 3(7/17) days
d) 4(9/17) days
e) None of these
Answers:
Directions (Q. 1-5)
Total units of work= 420
A’s one hour work= 35 units
B’s one hour work= 30 units
A+B+S= 42 units
Units of work done by S in one hour= 65- 42= 23 units
Time required by S to empty the tank= 420/23= 18(6/23) hours.
Total units of work= 210 units
E’s one hour work= 7 units
Q’s and E’s one hour work= 5 units
Work done by Q in an hour= 7-5= 2 units
Time required by Q to empty the tank= 210/2= 105 hours.
Total units of work= 630
Q’s one work= 6 units
C’s one hour work= 35 units
Q’s and C’s one hour work= 35 – 6 = 29 units
Time required= 630/29= 21(21/29) hours.
Total units of work= 504
B’s one hour work= 36 units
C’s one hours work= 28 units
D’s one hour work= 21 units
Work done by B and D in 8 hours= (36+21)*8= 456 units
Units of work remaining= 504-456= 48 units
Time after which pipe C should be closed= 48/28= 1(5/7) hours.
Efficiency ratio of F and T = 3: 1
Time ratio of F and T = 1: 3
T takes 48 days to complete the whole work
Total units of work= 48 units
F’s one hour work= 3 units
T’s one hour work= 1 units
Work done by pipe F and T in 2 hours= 3+1= 4 units
Work done in 24 hours= 4*12= 48 units
So the time required to fill the tank= 24 hours.
Total units of work= 120 units
D’s one hour work= 5 units
P’s one hour work= 3 units
Work done by D and P in one hour= 5-3= 2 units
Time taken by D and P to fill the tank = 120/2= 60 hours
Time taken by C and S to fill the tank= 62 hours
Time taken by C to fill the tank = 18 hours
Total units of work= 558 units (LCM of 18 and 62)
Work done by pipe C = 31 units
Work done by pipe C and S= 9 units
Work done by pipe S= 31-9= 22 units
Time required by pipe S to fill the tank= 558/22= 25(4/11) hours.
Directions (Q. 6 – 10):
Let the work will be completed in x days.
X (1/10 + 1/14 + 1/18) = 1
=> x (63 + 45 + 35)/630 = 1
=> x = 630/143 = 4(58/143) days
Let the time taken by Malhotara family to complete the work = x days
Let the time taken by Banerjee family to complete the work = y days
X (1/24 + 1/32) = 1
=> x(4 + 3)/96 = 1
=> x = 96/7
Y(1/12 + 1/16) = 1
=> y(4 + 3)/48 = 1
=> y = 48/7
Required percentage = [(96/7)/(48/7)] x 100 = 200%
Let the work will get complete in x days.
x(1/12 + 1/16 + 1/14 + 1/32) = 1
=> x(56 + 42 + 48 + 21)/672 = 1
=> x = 672/167 days = 4(4/167) days
Let Deshmukh family can complete the remaining work in x days.
3/14 + x (1/16 + 1/24) = 1
=> x (3 + 2)/48 = 11/14
=> x = 264/35 days = 7(19/35) days
Let the time taken by wife of all the families to complete the work = x days
X (1/12 + 1/32 + 1/16 + 1/32 + 1/24 + 1/30) = 1
=> x (40 + 15 + 30 + 15 + 20 + 16)/480 = 1
=> x = 480/136
=> x = 60/17 = 3(9/17) days
Daily Practice Test Schedule | Good Luck
| Topic | Daily Publishing Time |
| Daily News Papers & Editorials | 8.00 AM |
| Current Affairs Quiz | 9.00 AM |
| Logical Reasoning | 10.00 AM |
| Quantitative Aptitude “20-20” | 11.00 AM |
| Vocabulary (Based on The Hindu) | 12.00 PM |
| Static GK Quiz | 1.00 PM |
| English Language “20-20” | 2.00 PM |
| Banking Awareness Quiz | 3.00 PM |
| Reasoning Puzzles & Seating | 4.00 PM |
| Daily Current Affairs Updates | 5.00 PM |
| Data Interpretation / Application Sums (Topic Wise) | 6.00 PM |
| Reasoning Ability “20-20” | 7.00 PM |
| English Language (New Pattern Questions) | 8.00 PM |
| General / Financial Awareness Quiz | 9.00 PM |
This post was last modified on September 23, 2020 10:18 am