Dear Readers, SBI is conducting Online Examination for the recruitment of probationary officer. To enrich your preparation here we have providing new series of Data Interpretation – Quantitative Aptitude Questions. Candidates those who are appearing in SBI PO Prelims Exams can practice these Quantitative Aptitude average questions daily and make your preparation effective.
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Directions (Q. 1 – 5) Study the following information carefully and answer the given questions:
Following bar graph shows the total number of newspaper readers(In thousands) of English and Hindi language in different months of a certain city in the year 2017 and the table shows the ratio of male to female readers among them.
| Month | English language M : F | Hindi language M : F |
| August | 3 : 4 | 1 : 1 |
| September | 5 : 3 | 6 : 5 |
| October | 11: 6 | 7 : 6 |
| November | 4 : 3 | 2 : 1 |
| December | 9 : 7 | 5 : 3 |
1). Total number of male Hindi newspaper readers in the month of August and November together is approximately what percentage of total number of female English newspaper readers in the month of September and December together?
a) 120%
b) 115%
c) 127%
d) 108%
e) 135%
a) 143: 121
b) 149: 127
c) 135: 137
d) 131: 141
e) None of these
a) 24000
b) 12000
c) 18000
d) 21000
e) 20000
a) 46000
b) 44000
c) 48000
d) 45000
e) 40000
a) 38%
b) 36%
c) 42%
d) 48%
e) 52%
Directions (Q. 6 – 10) Study the following information carefully and answer the given questions:
Following table shows the percentage distribution of total number of students who completed their graduation from different universities and the ratio of male to female among them.
Total number of students = 56000
| University | Total number of students | Male : Female |
| P | 23 % | 7 : 3 |
| Q | 18 % | 5 : 4 |
| R | 12 % | 2 : 1 |
| S | 27 % | 3 : 5 |
| T | 20 % | 2 : 3 |
Answers:
Directions (Q. 1 – 5)
Total number of male Hindi newspaper readers in the month of August and November together
= > 36000*(1/2) + 66000*(2/3)
= > 18000 + 44000 = 62000
Total number of female English newspaper readers in the month of September and December together
= > 56000*(3/8) + 64000*(7/16)
= > 21000 + 28000 = 49000
Required % = (62000/49000)*100 = 126.53 % = 127 %
The total number of male Hindi newspaper readers of all the given months together
= > [36*(1/2) + 44*(6/11) + 52*(7/13) + 66*(2/3) + 56*(5/8)] thousand
= > [18 + 24 + 28 + 44 + 35] thousand
= > 149000
The total number of female English newspaper readers of all the given months together
= > [42*(4/7) + 56*(3/8) + 68*(6/17) + 70*(3/7) + 64*(7/16)] thousand
= > [24 + 21 + 24 + 30 + 28] thousand
= > 127000
Required ratio = 149000: 127000 = 149: 127
The total number of female Hindi newspaper readers of all the given months together
= > [36*(1/2) + 44*(5/11) + 52*(6/13) + 66*(1/3) + 56*(3/8)] thousand
= > [18 + 20 + 24 + 22 + 21] thousand
= > 105000
Required average = 105000/5 = 21000
The total English newspaper readers of all the given months
= > [42 + 56+ 68 + 70 + 64] thousand
= > 300000
The total Hindi newspaper readers of all the given months
= > [36 + 44 + 52 + 66 + 56] thousand
= > 254000
Required difference = 300000 – 254000 = 46000
Total number of female Hindi newspaper readers in the month of September and October together
= > [44*(5/11) + 52*(6/13)] thousand
= > [20 + 24] thousand
= > 44000
Total number of male English newspaper reader in the month of November and December together
= > [70*(4/7) + 64*(9/16)] thousand
= > [40 + 36] thousand = 76000
Required % = [(76000 – 44000)/76000]*100 = 42.1 % = 42 %
Directions (6-10):
| University | Total number of students | Male | Female |
| P | 12880 | 9016 | 3864 |
| Q | 10080 | 5600 | 4480 |
| R | 6720 | 4480 | 2240 |
| S | 15120 | 5670 | 9450 |
| T | 11200 | 4480 | 6720 |
The total number of male graduates from the given universities together
= > 9016 + 5600 + 4480 + 5670 + 4480
= > 29246
Total number of female graduates from university Q and R
= > 4480 + 2240 = 6720
Total number of male graduates from university P and T
= > 9016 + 4480 = 13496
Required % = (6720/13496)*100 = 49.79 % = 50 %
The total number of male graduates from university Q, R and T together
= > 5600 + 4480 + 4480 = 14560
The total number of female graduates from university P, R and S together
= > 3864 + 2240 + 9450 = 15554
Required ratio = 14560: 15554 = 7280: 7777
Required % = {[(23+ 18) – (12 + 27)]/(12 + 27)}*100
= > {(41 – 39)/39}*100 = 5.128 % = 5 % more
University S has highest number of female graduates.
Daily Practice Test Schedule | Good Luck
| Topic | Daily Publishing Time |
| Daily News Papers & Editorials | 8.00 AM |
| Current Affairs Quiz | 9.00 AM |
| Quantitative Aptitude “20-20” | 11.00 AM |
| Vocabulary (Based on The Hindu) | 12.00 PM |
| General Awareness “20-20” | 1.00 PM |
| English Language “20-20” | 2.00 PM |
| Reasoning Puzzles & Seating | 4.00 PM |
| Daily Current Affairs Updates | 5.00 PM |
| Data Interpretation / Application Sums (Topic Wise) | 6.00 PM |
| Reasoning Ability “20-20” | 7.00 PM |
| English Language (New Pattern Questions) | 8.00 PM |
This post was last modified on March 18, 2022 8:49 am