Dear Readers, SBI is conducting Online Examination for the recruitment of probationary officer. To enrich your preparation here we have providing new series of Data Interpretation – Quantitative Aptitude Questions. Candidates those who are appearing in SBI PO Prelims Exams can practice these Quantitative Aptitude average questions daily and make your preparation effective.
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Directions (Q. 1 – 5) Study the following information carefully and answer the given questions:
Following bar graph shows the time taken to travel (in hours) by six vehicles in two different days.
Distance covered (in kilometres) by six vehicles on each day.
| Vehicle | Day 1 | Day 2 |
| P | 864 | 774 |
| Q | 516 | 864 |
| R | 550 | 546 |
| S | 703 | 810 |
| T | 636 | 693 |
| U | 931 | 770 |
Directions (Q. 6 – 10) Study the following table carefully and answer the given questions:
Following table shows the population of different cities (In lakhs) and the ratio of males and females among them and the percentage of adult males and adult females.
| City | Population (In lakhs) | M : F | % Adult males from total males | % Adult females from total females |
| A | 8.1 | 5 : 4 | 76 % | 81 % |
| B | 7.7 | 6 : 5 | 69 % | 72 % |
| C | 9.8 | 3 : 4 | 70 % | 60 % |
| D | 7.2 | 2 : 1 | 66 % | 78 % |
| E | 8.5 | 2 : 3 | 82 % | 83 % |
Answers:
1). Answer c
The speed of vehicle P, Q and R on Day 1
= > (864/16) + (516/12) + (550/11)
= > 54 + 43 + 50 = 147 km/hr
The speed of vehicle S, T and U on Day 2
= > (810/18) + (693/11) + (770/14)
= > 45 + 63 + 55 = 163 km/hr
Required ratio = 147: 163
2). Answer d
The speed of vehicle P, Q and R on Day 2
= > (774/18) + (864/16) + (546/14)
= > 43 + 54 + 39 = 136 km/hr
The speed of vehicle P, S and T on Day 1
= > (864/16) + (703/19) + (636/12)
= > 54 + 37 + 53 = 144 km/hr
Required difference = 144 – 136 = 8 km/hr
3).Answer a
Total time taken to travel by six vehicles on Day 1
= > 16 + 12 + 11 + 19 + 12 + 19
= > 89 hours
Total time taken to travel by six vehicles on Day 2
= > 18 + 16 + 14 + 18 + 11 + 14
= > 91 hours
Required % = (89/91)*100 = 97.8 % = 98 %
4). Answer c
Speed of P = (864/16) = 54 km/hr
Speed of Q = (516/12) = 43 km/hr
Speed of R = (550/11) = 50 km/hr
Speed of S = (703/19) = 37 km/hr
Speed of T = (636/12) = 53 km/hr
Speed of U = (931/19) = 49 km/hr
Vehicle P has highest speed.
5). Answer b
Total distance travelled by six vehicles on Day 1
= > 864 + 516 + 550 + 703 + 636 + 931 = 4200 km
Total distance travelled by six vehicles on Day 2
= > 774 + 864 + 546 + 810 + 693 + 770 = 4457 km
Required % = [(4457 – 4200)/4457]*100 = 5.766 % = 6 % less
Direction (6-10)
6). Answer b
The total number of adult males in City C
= > 980000 *3/7 *(70/100) =294000
The total number of adult females in City A
= > 810000*4/9 * (81/100) = 291600
Required difference = 294000-291600= 2400
7). Answer d
| City | Population (In lakhs) | Males | Females |
| A | 810000 | 450000 | 360000 |
| B | 770000 | 420000 | 350000 |
| C | 980000 | 420000 | 560000 |
| D | 720000 | 480000 | 240000 |
| E | 850000 | 340000 | 510000 |
The total number of males of all the given cities together
= > (4.5 + 4.2 + 4.2 + 4.8 + 3.4) lakhs
= > 21.1 lakhs
= > 2110000
The total number of females of all the given cities together
= > (3.6 + 3.5 + 5.6 + 2.4 + 5.1) lakhs
= > 20.2 lakhs
= > 2020000
Required ratio = 2110000: 2020000 = 211: 202
8). Answer c
Total number of minor males in City A and B together
= > 8.1* 5/9 *(24/100)*100000 + 7.7* 6/11*(31/100)*100000
= > (86400+130200) = 216600
Total number of minor females in City D and E together
= > 7.2*1/3 *(22/100)*100000 + 8.5*3/5 *(17/100)*100000
= > 52800+86700=139500
Required % = (216600/139500) *100 = 155%
9). Answer a
Total number of adult females in City B and C together
= > 7.7*5/11*(72/100) * 100000 + 9.8 *4/7 *(60/100) *100000
= > 252000+336000 = 588000
Total number of adult males in City A and E together
= > 8.1* * 5/9 *(76/100) * 100000+ 8.5*2/5 *(82/100) *100000
= > 342000+278800
= > 620800
Required % = [(620800-588000)/620800]*100
= > 5 % less
10. Answer d
Total number of adult females in all the given cities
= > 8.1*4/9 *(81/100) + 7.7*5/11 *(72/100) + 9.8*4/7*(60/100) + 7.2*1/3*(78/100) + 8.5*3/5*(83/100)
=>291600+252000+336000+187200+423300
=>1490100
Required average = 1490100/5 = 298020
Daily Practice Test Schedule | Good Luck
| Topic | Daily Publishing Time |
| Daily News Papers & Editorials | 8.00 AM |
| Current Affairs Quiz | 9.00 AM |
| Quantitative Aptitude “20-20” | 11.00 AM |
| Vocabulary (Based on The Hindu) | 12.00 PM |
| General Awareness “20-20” | 1.00 PM |
| English Language “20-20” | 2.00 PM |
| Reasoning Puzzles & Seating | 4.00 PM |
| Daily Current Affairs Updates | 5.00 PM |
| Data Interpretation / Application Sums (Topic Wise) | 6.00 PM |
| Reasoning Ability “20-20” | 7.00 PM |
| English Language (New Pattern Questions) | 8.00 PM |
This post was last modified on March 18, 2022 8:49 am