Dear Readers, SBI is conducting Online Examination for the recruitment of probationary officer. To enrich your preparation here we have providing new series of Data Interpretation – Quantitative Aptitude Questions. Candidates those who are appearing in SBI PO Prelims Exams can practice these Quantitative Aptitude average questions daily and make your preparation effective.
[WpProQuiz 2818]
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Directions (Q. 1 – 5) Study the following information carefully and answer the given questions:
Following table shows the total number of people visiting the five different game shows in a certain year and the percentage of men, women and children’s among them.
| Game shows | Total number of people | Percentage | ||
| Men | Women | Children | ||
| A | 1500 | 34 % | 35 % | 31 % |
| B | 2700 | 42 % | 28 % | 30 % |
| C | 3600 | 26 % | 37 % | 37 % |
| D | 4400 | 31 % | 33 % | 36 % |
| E | 5200 | 39 % | 29 % | 32 % |
Directions (Q. 6 – 10) Study the following information carefully and answer the given questions:
Following table shows the total units consumed by the six different houses in four different months in the year 2017 and the amount per units also given.
| Feb | Apr | June | Aug | |
| A | 670 | 750 | 520 | 440 |
| B | 760 | 810 | 630 | 570 |
| C | 430 | 480 | 520 | 460 |
| D | 630 | 650 | 680 | 720 |
| E | 540 | 260 | 620 | 640 |
| F | 380 | 420 | 280 | 420 |
Note:
1- 100 units = Rs. 1
101 – 300 units = Rs. 3
301 – 500 units = Rs. 5
Above 500 units = Rs. 6.50
Answers:
Directions (Q. 1 – 5)
1.Answer: a
| Game shows | Total number of people | Men | Women | Children |
| A | 1500 | 510 | 525 | 465 |
| B | 2700 | 1134 | 756 | 810 |
| C | 3600 | 936 | 1332 | 1332 |
| D | 4400 | 1364 | 1452 | 1584 |
| E | 5200 | 2028 | 1508 | 1664 |
Total men and Children visiting the game show A and C together
= > 510 + 465 + 936 + 1332 = 3243
Total women and children visiting the game show B and D together
= > 756 + 810 + 1452 + 1584 = 4602
Required % = (3243/4602)*100 = 70.46 % = 70 %
2.Answer: d
The total number of men visiting all the given game shows together
= > 510 + 1134 + 936 + 1364 + 2028 = 5972
The total number of women visiting all the given game shows together
= > 525 + 756 + 1332 + 1452 + 1508 = 5573
Required difference = 5972 – 5573 = 399
3.Answer: b
The total number of children visiting all the given game shows together
= > 465 + 810 + 1332 + 1584 + 1664 = 5855
4.Answer: a
The total number of women visiting the game shows A, C and E together
= > 525 + 1332 + 1508 = 3365
The total number of men visiting the game shows B, D and E together
= > 1134 + 1364 + 2028 = 4526
Required ratio = 3365: 4526
5.Answer: c
Total number of people visiting the game show A and E together
= > 1500 + 5200 = 6700
Total number of people visiting the game show B and D together
= > 2700 + 4400 = 7100
Required % = [(7100 – 6700)/7100]*100 = 5.63 % = 6 % less
Directions (Q. 6 – 10)
6.Answer: b
The electricity amount of house A, C and E in the month of Feb
= > 670*6.50 + 430*5 + 540*6.50
= > 4355 + 2150 + 3510 = Rs. 10015
The electricity amount of house B, D and F in the month of June
= > 630*6.50 + 680*6.50 + 280*3
= > 4095 + 4420 + 840 = Rs. 9355
Required difference = 10015 – 9355 = Rs. 660
7.Answer: d
The electricity amount of all the given houses in the month of Apr
= > 750*6.50 + 810*6.50 + 480*5 + 650*6.50 + 260*3 + 420*5
= > 4875 + 5265 + 2400 + 4225 + 780 + 2100
= > 19645
The electricity amount of all the given houses in the month of August
= > 440*5 + 570*6.50 + 460*5 + 720*6.50 + 640*6.50 + 420*5
= > 2200 + 3705 + 2300 + 4680 + 4160 + 2100
= > 19145
Required ratio = 19645: 19145 = 3929: 3829
8.Answer: a
The total electricity amount paid by the house owner of F for all the given months together
= > 380*5 + 420*5 + 280*3 + 420*5
= > 1900 + 2100 + 840 + 2100
= > 6940
Required average = 6940/4 = 1735
9.Answer: c
Total units consumed by all the given houses in the month of Feb
= > 670 + 760 + 430 + 630 + 540 + 380 = 3410
Total units consumed by all the given houses in the month of August
= > 440 + 570 + 460 + 720 + 640 + 420 = 3250
Required % = (3410/3250)*100 = 104.92 % = 105 %
10.Answer: d
Total electricity amount paid by the house owner of A, D and F together for all the given months
= > 670*6.50 + 750*6.50 + 520*6.50 + 440*5 + 630*6.50 + 650*6.50 + 680*6.50 + 720*6.50 + 380*5 + 420*5 + 280*3 + 420*5
= > 4355 + 4875 + 3380 + 2200 + 4095 + 4225 + 4420 + 4680 + 1900 + 2100 + 840 + 2100
= > Rs. 39710
Daily Practice Test Schedule | Good Luck
| Topic | Daily Publishing Time |
| Daily News Papers & Editorials | 8.00 AM |
| Current Affairs Quiz | 9.00 AM |
| Quantitative Aptitude “20-20” | 11.00 AM |
| Vocabulary (Based on The Hindu) | 12.00 PM |
| General Awareness “20-20” | 1.00 PM |
| English Language “20-20” | 2.00 PM |
| Reasoning Puzzles & Seating | 4.00 PM |
| Daily Current Affairs Updates | 5.00 PM |
| Data Interpretation / Application Sums (Topic Wise) | 6.00 PM |
| Reasoning Ability “20-20” | 7.00 PM |
| English Language (New Pattern Questions) | 8.00 PM |
This post was last modified on March 18, 2022 8:49 am