Dear Readers, SBI is conducting Online Examination for the recruitment of probationary officer. To enrich your preparation here we have providing new series of Data Interpretation – Quantitative Aptitude Questions. Candidates those who are appearing in SBI PO Mains Exams can practice these Quantitative Aptitude average questions daily and make your preparation effective.
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Directions (1-5): Study the following information carefully and answer the given questions:
The Table below shows time taken by different outlet pipes to empty the tank:
| Pipes | Time ( Hours) |
| P | 15 |
| Q | 10 |
| R | 12 |
| S | 6 |
| T | 8 |
| U | 15 |
1) Pipe A and C were opened simultaneously to fill an empty tank. After some time pipe C was closed, then pipe A took 4 hours to fill the rest of the tank. For how much time was the pipe A and B opened together?
a) 6
b) 18
c) 4
d) 7
e) 2
2) Pipe D and F were opened to fill the empty but when the tank was 64% full Pipe B was also opened find the total time taken to fill the tank?
a) 8(4/7)
b) 2(3/8)
c) 5(2/19)
d) 4(1/9)
e) None of these
3) If Pipes A and B were opened together to fill a tank but accidentally pipe P was also opened with Pipe A and B then find the time taken to fill the empty tank?
a) 56
b) 24
c) 25
d) 60
e) 14
4) The pipes C and E filled the empty tank of capacity 3300 liters in 5(5/11) hours then find how many liters of water pipe C fills in one hour?
a) 250
b) 370
c) 156
d) 275
e) 450
5) If pipes S and T were used to drain water from the tank but due to hurry these pipes were not opened properly, so the pipes allowed 1/2th and 2/3 part of water respectively, how long will they take to empty the tank?
a) 12
b) 24
c) 6
d) 7
e) None of these
Directions (6-10): Read the following information carefully and answer the following questions carefully. The table shows different kinds of balls in each bag.
| Types of Balls | Bag A | Bag B | Bag C |
| White | 2 | 4 | 8 |
| Red | 4 | 3 | 3 |
| Green | 6 | 2 | 6 |
| Yellow | 3 | 4 | 5 |
6) Three balls are drawn at random from Bag A. What is the probability that all the three are of same color?
a) 5/91
b) 9/91
c) 15/91
d) 19/91
e) 14/93
7) Two balls are picked at random from Bag B. What is the probability that both the balls are white color?
a) 1/13
b) 9/91
c) 15/91
d) 19/91
e) 14/93
8) Three Balls are drawn at random from Bag A. What is the probability that at least two red balls are drawn?
a) 1/13
b) 2/13
c) 4/13
d) 8/13
e) 7/13
9) Three balls are drawn at random from Bag B. What is the probability that at least one ball is of Red color?
a) 42/143
b) 44/143
c) 46/143
d) 83/143
e) None of these
10) Four balls are drawn at random from Bag A. What is the probability that all the balls are of different colors?
a) 42/455
b) 44/455
c) 46/455
d) 48/455
e) None of these
Answers:
1) Answer: a)
Total units of work= 60
Pipe A’s one hour work= 3 units
Pipe C’s one hour work= 5 units
Work done by pipe A in 4 hours to fill the rest of the tank= 3*4= 12 units
Remaining work was done by pipe A and C= 60-12= 48
Time for which pipe C was open = 48/8= 6 hours
2) Answer: a)
Total units of work= 150
Pipe D’s one hour work= 6 units
Pipe F’s one hour work= 10 units
Pipe B’s one hour work= 5 units
Time taken by pipes D and F to fill 64% of the tank= 96/ (10+6) = 6 hours
Remaining units= 54
Time taken to fill the tank= 54/ (6+10+5) = 54/21 hours
Total time taken to fill the cistern= 6+ 54/21= 8(4/7) hours
3) Answer: d)
Total units of work= 60
Pipe A’s one hour work= 3 units
Pipe B’s one hour work= 2 units
Pipe P’s one hour work= 4 units
Three pipes one hour work= 3+2-4= 1 units
So, time require to fill the empty tank= 60/1= 60 hours
4) Answer: d)
Liters of water filled by pipe C in 5(5/11) hours
= 1/12* 60/11=5/11
= 5/11* 3300= 1500 liters.
So pipe C can fill liters of water in one hour= 1500*11/60= 275 liters.
5) Answer: c)
Total units of work= 24
Work done pipe S in one hour= ½* 4= 2 units
Work done pipe T in one hour= 2/3* 3= 2 units
So, the time taken to empty the tank= 24 /4= 6 hours
Direction (6-10)
6) Answer: a)
The probability that all the three balls are of same color
= (4C3 + 6C3+ 3C3)/ 15C3
= (4+20+1)*6/15*14*13
= 25*6/15*14*13
= 5/91
7) Answer: a)
Probability of both the balls of white color
= 4C2/13C2
= 6/ 78
= 1/13
8) Answer: b)
The probability that at least two red balls are drawn
= (4C1*11C1+4C3)/15C3
= (66+4)*6/ (15*14*13)
= 70*6/ (15*14*13)
= 2/13
9) Answer: d)
Probability of picking no red balls
= 10C3/13C3
= 120/286
So, Probability of at least two red balls
= 1- 120/286
= 166/286
= 83/143
10) Answer: d)
The probability that all the balls are of different colors
= (2C1)*(4C1)*(6C1)*(3C1)/15C4
=(2*4*6*3*4*3*2)/(15*14*13*12)
= 48/455
Daily Practice Test Schedule | Good Luck
| Topic | Daily Publishing Time |
| Daily News Papers & Editorials | 8.00 AM |
| Current Affairs Quiz | 9.00 AM |
| Quantitative Aptitude “20-20” | 11.00 AM |
| Vocabulary (Based on The Hindu) | 12.00 PM |
| General Awareness “20-20” | 1.00 PM |
| English Language “20-20” | 2.00 PM |
| Reasoning Puzzles & Seating | 4.00 PM |
| Daily Current Affairs Updates | 5.00 PM |
| Data Interpretation / Application Sums (Topic Wise) | 6.00 PM |
| Reasoning Ability “20-20” | 7.00 PM |
| English Language (New Pattern Questions) | 8.00 PM |
This post was last modified on March 18, 2022 8:50 am