Quantitative Aptitude Questions (Data Interpretation) for SBI Clerk 2018 Day-18

Quantitative Aptitude Questions (Data Interpretation) for SBI Clerk 2018 Day-18:

Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from March 2018. To enrich your preparation here we have providing new series of Data Interpretation – Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.

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Daily Practice Test Schedule | Good Luck

Directions (Q. 1-5) Study the following information carefully and answer the given questions:

Data related to sales of car by different cars in the year 2006:-

Ratio of Ac and Non AC cars sold by the different companies:-

1. Find the average no of Non AC car sold by Company A,C,D,E.

1. 9700
2. 10400
3. 8300
4. 4500
5. None of these

2. The number of Ac car sold by company B in 2006 to men and women is in ratio of 7:5, then find the difference between the Ac car purchased by men and women?

1. 4000
2. 3000
3. 2500
4. 2000
5. None of these

3. The sale of AC car in 2007 by company D decreased by 30 % as compared to previous year then find the percentage by which the sale of non AC car increased?

1. 20
2. 15
3. 12
4. Can’t be determined
5. none of these

4. The no of AC car sold by company F in 2006 is 30 % less than the AC car sold by company C then find the difference between the Non AC car sold by company A and AC car sold by F?

1. 6300
2. 2500
3. 7700
4. 6777
5. None of these

5. If company B exported 60% of its AC car then AC car sold by company B in India is what percentage less than the non AC car sold by company E?

1. 30
2. 35
3. 60
4. 24
5. None of these

Directions (Q. 6-10) Study the following information carefully and answer the given questions:

Number of different balls in two bags A and B:-

6. If two balls are picked at random from Bag A then what is the probability that both balls are red?

1. 1/7
2. 3/7
3. 2/7
4. 3/14
5. None of these

7. If three balls are picked at random from Bag B, what is the probability that two are red and one is green?

1. 3/25
2. 3/22
3. 4/23
4. 5/24
5. None of these

8. If four balls are picked at random from Bag A what is the probability that one is green, two are blue and one is red?

1. 23/455
2. 3/910
3. 24/455
4. 1/66
5. None of these

9. If two balls are picked at random from Bag B, what is the probability that both are blue?

1. 1/66
2. 3/74
3. 6/77
4. 4/27
5. None of these

10. If two balls are picked at random from Bag A, what is the probability that either both are green or both are yellow?

1. 2/105
2. 6/105
3. 9/51
4. 4/105
5. None of these

Answers:

Directions (Q. 1-5)

1. Answer b

No of Non AC car sold by different cars

A= 18/25*17500= 12600

C= 13/20*20000=13000

D= 4/10*10000= 4000

E= 15/25* 20000= 12000

Total cars sold by the companies= 41600

Average = 41600/4= 10400 cars.

2. Answer d

AC car sold by company B in 2006= 12/25*25000= 12000

AC cars purchased by men= 12000*7/12=7000

AC cars purchased by women= 5000

Difference = 7000-5000= 2000

3. Answer d

Can’t be determined

4. Answer c

AC car sold by C= 7/20* 20000= 7000

AC car sold by F= 7000*70/100= 4900

Non AC car sold by A= 17500*18/25= 12600

Required difference= 12600 -4900= 7700 cars

5. Answer c

AC Cars sold by B = 25000*12/25= 12000

AC cars exported by B= 12000*60/100= 7200

AC cars sold by B in India- 12000-7200= 4800

Non AC cars sold by E= 15/25*20000= 12000

Required Percentage= 12000-4800/12000*100=60%

Directions (Q. 6-10)

6. Answer a

Total number of balls in Bag A

= 6+4+2+3=15

Ways of selection of two red balls

=n(E)= ⁶C₂

Ways of selection of two balls

= n(S) =¹⁵C₂

So required probability= ⁶C₂ /¹⁵C₂

= 6*5/15*14

= 1/7

7. Answer b

Total number of balls =12

= ¹²C₃

Ways to pick 2 red balls= ⁴C₂= 6

Ways to pick one green balls= ⁵C₁= 5

Required probability= 6*5/220= 3/22

8. Answer c

Ways of selection of 4 balls = ¹⁵C₄

Ways of selection of one green ball= ²C₁

Ways of selection two blue balls= ⁴C₂

Ways of selection of one red ball= ⁶C₁

Required probability = 24/455

9. Answer a

Total balls =12

Total outcomes =¹²C₂

Favorable outcomes = ²C₂ =1

Required Probability= 1/66

10. Answer d

Total Ways to select two green balls= ²C₂

Total Ways to select two yellow balls= ³C₂

Probability of both green balls= 1 / ¹⁵C₂

Probability of both yellow balls= 3 / ¹⁵C₂

Required probability = 1 / ¹⁵C₂ + 3 / ¹⁵C₂ = 4/105.

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