Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from March 2018. To enrich your preparation here we have providing new series of Data Interpretation – Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.
Click “Start Quiz” to attend these Questions and view Solutions
| Topic | Daily Publishing Time |
| Daily News Papers & Editorials | 8.00 AM |
| Current Affairs Quiz | 9.00 AM |
| Logical Reasoning | 10.00 AM |
| Quantitative Aptitude “20-20” | 11.00 AM |
| Vocabulary (Based on The Hindu) | 12.00 PM |
| Static GK Quiz | 1.00 PM |
| English Language “20-20” | 2.00 PM |
| Banking Awareness Quiz | 3.00 PM |
| Reasoning Puzzles & Seating | 4.00 PM |
| Daily Current Affairs Updates | 5.00 PM |
| Data Interpretation / Application Sums (Topic Wise) | 6.00 PM |
| Reasoning Ability “20-20” | 7.00 PM |
| English Language (New Pattern Questions) | 8.00 PM |
| General / Financial Awareness Quiz | 9.00 PM |
Directions (Q. 1 – 5) Study the following information carefully and answer the questions given below:
Directions (Q. 6-10) Study the following table and answer the following questions.
| Type | Shops | ||||
| P | Q | R | S | T | |
| A | 1250 | 3500 | 1360 | 2240 | – |
| B | – | 3080 | 3700 | 4200 | 920 |
| C | 3460 | 4400 | 4860 | 4860 | 4760 |
| D | 900 | 680 | 700 | – | 600 |
| E | 300 | 440 | 1200 | 1250 | 280 |
Answers:
Directions (Q. 1 – 5)
Sum of total number of boys, girls and teachers in school A = 250 + 125 + 15 = 390
Sum of total number of boys, girls and teachers in school D = 275 + 100 + 14 = 389
Required percentage = 390/389 x 100 = 100.25%
Total number of boys, girls and teachers in school B = 175 + 200 + 20 = 395
Total number of boys, girls and teachers in school C = 225 + 75 + 25 = 325
Required ratio = 395:325 = 79:65
Total number of boys from all the schools together = 250 + 175 + 225 + 275 + 125 + 200 = 1250
Total number of girls from all the schools together = 125 + 200 + 75 + 100 + 225 + 175 = 900
Required difference = 1250 – 900 = 350
Total number of boys, girls and teachers of school E = 125 + 225 + 26 = 376
Total number of boys, girls and teachers of school F = 200 + 175 + 30 = 405
Required percentage = (405 – 376)/405 x 100 = 7.1% less
Total number of teachers from all the schools together = 15 + 20 + 25 + 14 + 26 + 30 = 130
Total number of students of school A = 250 + 125 = 375
Total number of students of school C = 225 + 75 = 300
Required sum = 130 + 375 + 300 = 805
Directions (Q. 6-10)
Since the total sale of type B is 14000,
x+3080+3700+4200+920=14000
x=2100
So, the lowest sale is 920. The shop is T.
The sale of type D in shop S= 4X 280
=1120
The total type D sold by all the shops=900+680+700+1120+600=4000
Then 15% of 4000=600
Using the above question, we have
The sale of type D in shop S=1120.
Then the Total sale of shop S=2240+4200+4860+1120+1250=13670
Then the average number of items sold in shop S=13670/5
=2734
Total no of shops in Type A is 11000.
So, Total shops of Type A in shop T is,
=>11000-(1250+3500+1360+2240)
=> 2650
Total shops of Type D in shop R = 700
Less % = (1950/2650)*100
=>73.58%
The total sale of shop Q=12100
The total sale of the shop R =11820
Thus the difference=12100-11820 =280
Click Here for More Quantitative Aptitude Questions
This post was last modified on June 12, 2021 3:14 pm