Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June 2018. To enrich your preparation here we have providing new series of Inequality – Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.
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- Quantity I: If 47a + 47b = 5452. What is the average of a and b?
Quantity II: The average of four consecutive numbers A, B, C and D is 49.5. What is the value of B?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
- Quantity I: Two numbers are respectively 20% and 50% more than a 3rd number. What is the percentage of 2nd with respect to 1st?
Quantity II: From 2008 to 2009, the sales of a book decreased by 80%. If the sales in 2010 was the same as in 2008, by what percent did it increase from 2009 to 2010?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
- Quantity I: By selling an article for Rs. 720, a man loses 10%. At what price should he sell it to gain 40 %?
Quantity II: The difference between the CP and SP of an article is Rs. 240. If the profit is 20%, find the selling price?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
- Quantity I: At simple Interest, a sum becomes 3 times in 20 year. Find the time, in which the sum will be double at the same rate of interest.
Quantity II: Simple interest for the sum of Rs. 1500 is Rs. 30 in 4 year and Rs. 60 in 8 year. Find the rate of simple interest.
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
- 3x+y = 81 and 81x-y = 3
Quantity I: value of x
Quantity II: value of y
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
- 6x – 10y= 10 and x/ x + y= 5/7
Quantity I: Value of x- y
Quantity II: Value of x+ y
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
- Quantity I: Two men start together to walk a certain distance, one at 4km/hr and another at 3km/hr. The former arrives half an hour before the latter. What is the distance?
Quantity II: A man completes 30 km of a journey at 6 km/hr and the remaining 40 km of the journey in 5 hr. Find the average speed for the whole journey.
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
- Two trains of lengths 50m and 65m are moving in the same direction at 18 m/s and 17m/s respectively.
Quantity I: Time taken by the faster train to cross the slower train.
Quantity II: Time taken by the slower train to cross a platform of length 156 m.
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
- Quantity I: In how many ways, the letters of the word STRESS can be arranged?
Quantity 2: In how many ways the letters of word FINANCE can be arranged?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
- Quantity I: 5x2– 34x + 45=0
Quantity II: 4y2 -19y + 21=0
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
Answers:
- Answer a
Explanation:
Quantity I
47(a+ b) =5452
a + b= 5452/47= 116
Average value= 116/2= 58
Quantity II
Let the numbers A, B, C and D be x, x+1, x+2, x+3
So,
x + (x+1) + (x+2) + (x+3)/4= 49.5
4x + 6 = 198
4x = 192
x = 48
Value of B= 48+1= 49
Hence Quantity I > Quantity II
- Answer c
Explanation:
Quantity I
First number =120
Second number= 150
Third number = 100
Required percentage= (150/120)*100= 125%
Quantity II
Sale in 2008= 100
Sale in 2009= 20
Sale in 2010= 100
Required percentage increase= 80/20*100= 400%
Hence Quantity II> Quantity I
- Answer c
Explanation:
Quantity I
SP= 720 and loss= 10%
CP= 100/90*720= Rs 800
SP of article at 5% gain = 140/100*800= Rs. 1120
Quantity II
Difference between SP and CP= 240
Gain%= SP – CP/CP*100
20= (240/CP)*100
CP= 1200
SP= 1200+240 = Rs. 1440
Hence Quantity II > Quantity I
- Answer a
Explanation:
Quantity I
Let sum = P, then for 20 year
SI= 3P- P= 2P
2P= P * R *T/100
R= 10%
For the sum to be double
SI= 2P-P= P
P= P*10*N/100
N= 10 years
Quantity II
SI in 8 year= 60
SI in 4 year= 30
So,
1500*R*8/100 – 1500* R * 4/100= 60-30
1500*R*4/100 = 30
6000R/100 = 30
R= 30/60 = 0.5 %
Hence Quantity I > Quantity II
- Answer a
Explanation:
3x+y= 81
3x+y= 34
x +y= 4……. (i)
81x-y= 3
(34) x-y= 31
x –y= ¼ …….. (ii)
On solving, we get
x= 17/8
y= 15/8
Hence, Quantity I > Quantity II
- Answer c
Explanation:
Given, 6x-10y = 10…….(i)
X / x+ y= 5/7
7x= 5x+5y
2x-5y= 0………….(ii)
On solving the two equations we get,
x= 5
y= 2
Quantity I= 5-2= 3
Quantity II= 5+2= 7
Hence Quantity II > Quantity I
- Answer c
Explanation:
Quantity I
Let the total distance be x
According to question
x/3 – x/4= 1/2
x= 6 km
Quantity 2
Total distance= 70 km
Total Time = 30/6+5= 60/6= 10 hr
Average speed= Total distance/Total time = 70/10= 7 km/hr
Hence Quantity II > Quantity I
- Answer a
Explanation:
Quantity I
Relative speed= 18-17= 1m/s
Required time= (50+65)/1= 115 seconds
Quantity II
Time taken to cross a platform of length 156 m= (65+156)/17= 13 seconds
Hence Quantity I > Quantity II
- Answer c
Explanation:
Quantity I
Required numbers of arrangement= 6!/3!= 6*5*4*3!/ 3!= 120
Quantity II
Required number of arrangement= 7!/2!= 2520
Hence Quantity II > Quantity I
- Answer e
Explanation:
Quantity I
5x2– 34x +45 = 0
5x2– 25x-9x+45= 0
5x(x-5) – 9(x-5) = 0
(x-5) (5x-9)=0
So, x= 5, 5/9
Quantity II
4y2 -19y +21= 0
4y2-12y-7y+21= 0
4y(y-3)-7(y-3) = 0
(y-3) (4y-7) = 0
So, y= 3, 7/4
Hence there is no relation between Quantity I and Quantity II
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