Dear Readers, SBI is conducting Online Examination for the recruitment of Clerical Cadre and Probationary Officers. Examination of SBI Clerk/PO Mains was scheduled from August 2018. To enrich your preparation here we have providing new series of Inequality- Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk/PO Mains Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.
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Quantity II: 5 years ago, the ratio of age of A and B is 4: 1. If the difference between their ages is 30 years, then find the present age of A?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
Quantity II: P and Q started a business together. After one year, their profit ratio is 3: 4. If P invested Rs. 12000, then find the initial investment of Q?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
Quantity II: 150 m long train crosses a telegram post in 3 sec. Find the speed of the train?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
Quantity II: A certain sum of money invested for a period of 5 years at 6 % per annum, simple interest earned is Rs. 5400. Find the principle?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
Quantity II: Two trains of equal length moves towards each other at a
Speed of 40 km/hr and 35 km/hr respectively. If they crossing each other after 14.4 secs, then find the length of each train
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
Quantity I: If 3 toys are drawn randomly, then the probability of getting 2 yellow toys and 1 black toys?
Quantity II: If 2 toys are drawn randomly, then the probability of getting both the toys is violet?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
Quantity II: The average age of 6 consecutive even numbers is 57. Find the smallest number?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
Quantity II: Kavi can do a piece of work in 9 days and Silambu can do the same work in 18 days. They started the work. After 3 days Sanjay joined them, who can complete the same work in 3 days. What is the total number of days in which they had completed the work?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
Quantity II: A and B started a business by investing in the ratio of 7: 4. A invested for a whole year. At the end of the year, the share of A and B is 3: 1. How many months B invested the money?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
Quantity II: If the breadth of a triangle is increased by 30 % while the height of a triangle is decreased by 20 %, then find the percentage change in area of the triangle?
a) Quantity I > Quantity II
b) Quantity I ≥ Quantity II
c) Quantity II > Quantity I
d) Quantity II ≥ Quantity I
e) Quantity I = Quantity II or Relation cannot be established
Answers:
Quantity I:Total age of 28 students = 28*15 = 420Total age of 28 students + 1 teacher = 29*16 = 464The age of the teacher = 464 – 420 = 44 years(Or)Shortcut:
N Average
28 15
29 16
The age of the teacher = (28 + 16) or (29 + 15) = 44 years
Quantity II:
5 years ago, the ratio of age of A and B = 4: 1(4x, x)
According to the question,
4x – x = 30
3x = 30
X = 10
The present age of A = 4x + 5 = 45 years
Quantity II > Quantity I
2. Answer a
Quantity I:The share of A and B= > 24000: 30000= > 4: 59’s = 720001’s = 8000
The share of A = 4’s = Rs. 32000
Quantity II:
Let the initial investment of Q be x,
According to the question,
(12000/x) = (3/4)
X = Rs. 16000
Quantity I > Quantity II
3. Answer c
Quantity I:The ratio of speed of two trains = 3: 5 (3x, 5x)The speed of second train = 350/7 = 50 km/hr5x = 50X = 10The speed of first train = 3x = 30 km/hr
Quantity II:
The speed of the train = 150/3 = 50 m/s = 50*(18/5) = 180 km/hr
Quantity II > Quantity I
4. Answer c
Quantity I:The difference between the simple interest and compound interest for 2 years,Diff = Sum*(r/100)2121.50 = Sum*(9/100)2(121.50*100*100)/81 = SumSum = Rs. 15000
Quantity II:
5400 = (P*5*6)/100
(5400*100)/30 = P
Principle = Rs. 18000
Quantity II > Quantity I
5. Answer a
Quantity I:Let the distance be x,According to the question,T = D/S(x/2)/15 + (x/2)/18 = 11x/30 + x/36 = 11
66x/(30*36) = 11
X = 180 km
The distance covered by him is 180 km
Quantity II:
Let the train length be x,
14.4 = (x + x)/[(40 + 35)*(5/18)]
14.4 = (2x*18)/(75*5)
(14.4*75*5)/36 = x
X = 150 m
Quantity I > Quantity II
6. Answer c
Quantity I:Total probability n(S) = 18C3Required probability n(E) = 4C2 and 6C1P(E) = n(E)/n(S) = 4C2 and 6C1 / 18C3= > 3/68
Quantity II:
Total probability n(S) = 18C2
Required probability n(E) = 8C2
P(E) = n(E)/n(S) = 8C2 / 18C2
= > 28/153
Quantity II > Quantity I
7. Answer a
Quantity I:Total age of 7 persons = 42*7 = 294Total age of 3 persons = 38*3 = 114Total age of other 3 persons = 42*3 = 126The age of the remaining member = 294 – (114 + 126) = 54
Quantity II:
Let the consecutive even numbers be, x, x + 2, x + 4, x + 6, x + 8, x + 10.
x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10 = 57*6
6x + 30 = 342
6x = 312
X = 312/6 = 52
Quantity I > Quantity II
8. Answer e
Quantity I:Total work = men * days16 men can complete a work in 6 daysTotal work = 16*6 = 963 days work = 16*3 = 48Remaining work = 96 – 48 = 48
Now, the total men = 16 – 4 = 12 men
Remaining work can be completed in,
= > 48/12 = 4 days
Quantity II:
Kavi’s one day work = (1/9) days
Silambu’s one day work = (1/18) days
Sanjay’s one day work = (1/3) days
(Kavi + Silambu)’s one day work = (1/9) + (1/18) = 3/18 = 1/6 days
3 day work = (1/6)*3 = (1/2)
(1/2) of the work can be completed. Remaining is,
= > 1-(1/2) = ½
(Kavi + Silambu + Sanjay)’s one day work,
= > (1/6) + (1/3) = 3/6 = ½ days
Whole work can be completed by three of them in 2 days.
According to the question,
(1/2)*2 = 1 day
Total days = 3 days + 1day = 4 days
Quantity I = Quantity II
9. Answer c
Quantity I:The share of P and Q = 12500/37500 = 1:3So,30000*x / 45000*12 = 1/390000x = 540000x= 540000/90000
x= 6 months
Quantity II:
Let B invested for x months,
According to the question,
= > (7*12)/(4*x) = (3/1)
= > 21/x = 3/1
= > x = 7 months
Quantity II > Quantity I
10. Answer a
Quantity I:Let the length and breadth be 10 m and 10m respectively.Normal Area = lb = 10*10 = 100 Sq mNew Area = (10*120/100)*(10*90/100) = 12*9 = 108 Sq mPercentage change = [(108 – 100)/100]*100 = (8/100)*100 = 8 % increased
Quantity II:
Let the breadth and height of a triangle be 10 m and 10 m respectively.
Normal area = (1/2)*bh = (1/2)*10*10 = 50 Sq m
New area = (1/2)*(10*130/100)*(10*80/100) = (1/2)*13*8 = 52 Sq m
Percentage change = [(52 – 50)/50]*100 = 4 % increased
Quantity I > Quantity II
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This post was last modified on June 26, 2021 8:56 am