Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June 2018. To enrich your preparation here we have providing new series of Mensuration – Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.
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Answers:
1). Answer a
The area of the rectangular plot = 324 sq cm
Lb= 324
Length = 4*Breadth
4b*b = 324
4b2 = 324
b2 = 324/4 = 81
b = 9 cm
l = 4*9 = 36 cm
Perimeter of the rectangle = 2(l + b) = 2*(36 + 9) = 90 cm
The cost of fencing the plot = Rs. 7 per cm
Total cost = 90*7 = Rs. 630
2). Answer d
Let the length and breadth of the rectangle is 10 cm and 10cm,
Previous area= 10*10= 100
New length= 10*120/100= 12
New breadth= 10*90/100= 9
New area= 12*9= 108
Required percentage = [(108 – 100)/100]*100 = 8 % increased.
3). Answer c
Area of a circle= πr2
616 = 22r2/7
616*(7/22) = r2
r2 = 196
r = 14 m
Circumference = 2*22/7 * 14= 88 sq. m
Perimeter of the rectangle = 3*88 = 264 sq. m
264 = 2(l + 60)
132 = l + 60
l = 132 – 60
l = 72
Area of the rectangle = 72*60= 4320 sq. m
4). Answer b
The perimeter of a rectangle = 132 m
2(l + b) = 132
l + b = 66 –> (1)
l – b = 14 –> (2)
By solving the equation (1) and (2), we get,
l = 40, b = 26
Area of rectangle = lb = 40*26 = 1040
Area of Square = 1040 – 16 = 1024 = Side2
Side (a) = 32 m
Perimeter of square = 4*32 = 128 m
5). Answer a
Perimeter of the field = 3250/6.50 = 500 m
The ratio of length and breadth of the rectangle = 3: 2(3x, 2x)
According to the question,
2*(3x + 2x) = 500
10x = 500
X = 50
So, length = 150 m & breadth = 100 m
Difference between length & breadth
= > (150 – 100) m = 50 m
6). Answer c
Area of square = 784 Sq m
Side of the square = 28 m
Length of the rectangle = 28 + 12 = 40 m
Breadth of the rectangle = 28 – 5 = 23 m
Area of the rectangle = 40*23 = 920 Sq m
7). Answer a
The area of a square (a2) = 1296 sq cm
Side (a) = √1296 = 36 cm
Length of the rectangle = 36*(1/3) = 12 cm
Breadth of the rectangle = 36 – 28 = 8 cm
Perimeter of the rectangle = 2(l + b)
= > 2*(12 + 8)
= > 40 cm
8). Answer c
Radius = (7/9)*side
Area of circle = πr 2 = 1386
(22/7)*r2 = 1386
r2 = 1386*(7/22)
Radius (r) = 21 cm
Side = Radius*(9/7) = 21*(9/7) = 27 cm
Perimeter of the square = 4a
= > 27*4
= > 108 cm
9). Answer d
Area of circle
= > πr2 = 2464
=> (22/7)* r2 = 2464
=> r2 = 2464 x (7/22)
=> r2 = 784
=> r = 28 cm
Radius of the cylinder = 28/2 = 14 cm
Height of the cylinder = 28 cm
Volume of the cylinder = πr2h = (22/7)*14*14*28 = 17248 cm3
10). Answer a
The diagonal of the square is 14√2 cm
=> d = 14√2
Area of square = ½ d2= ½*196*2 =196
a2=196 = > a=14
Perimeter of square = 4a = 56 cm
Perimeter of equilateral triangle = 56 + 4 = 60 cm
= > 3a = 60
= > a = 20
Area of equilateral triangle = √3/4 a2
= > √3/4 *20*20
= > 100√3 sq cm
Daily Practice Test Schedule | Good Luck
| Topic | Daily Publishing Time |
| Daily News Papers & Editorials | 8.00 AM |
| Current Affairs Quiz | 9.00 AM |
| Quantitative Aptitude “20-20” | 11.00 AM |
| Vocabulary (Based on The Hindu) | 12.00 PM |
| General Awareness “20-20” | 1.00 PM |
| English Language “20-20” | 2.00 PM |
| Reasoning Puzzles & Seating | 4.00 PM |
| Daily Current Affairs Updates | 5.00 PM |
| Data Interpretation / Application Sums (Topic Wise) | 6.00 PM |
| Reasoning Ability “20-20” | 7.00 PM |
| English Language (New Pattern Questions) | 8.00 PM |
This post was last modified on June 26, 2021 8:56 am