Quantitative Aptitude Questions (Probability) for SBI Clerk / IDBI Executive 2018 Day- 71

Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June 2018. To enrich your preparation here we have providing new series of Probability – Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.

Click “Start Quiz” to attend these Questions and view Solutions

1) A cartoon contains 7 red and 5 green apples. 3 apples are drawn at random. Find the probability that they are of the same colors.

1. 7 /44
2. 9 / 44
3. 12/44
4. 3/44
5. None of these

2) 2 dice are thrown simultaneously. What is the probability that the sum of the numbers on the faces is divisible by either 3 or 5?

1. 7/36
2. 19/36
3. 9/36
4. 2/7
5. None of these

3) From a pack of 52 cards one card is drawn at random. What is the probability that the card drawn is a six or a diamond?

1. 17/52
2. 4/13
3. 9/52
4. 3/13
5. None of these

4) 2 cards are drawn together at random from a pack of 52 cards. What is the probability of both the cards being jack?

1. 25 / 57
2. 53/256
3. 4/221
4. 1/221
5. None of these

5) In a bouquet, there are 5 red, 3 white and 7 orange roses. One rose is picked up randomly. What is the probability that is neither red nor orange?

1. 1/3
2. 1/5
3. 1/8
4. 1/7
5. None of these

6) In a bag contains 6 black toys, 7 violet toys and 5 blue toys. Three toys are drawn at random from the bag. The probability that all of them are blue is?

1. 11/816
2. 5/408
3. 13/816
4. 7/408
5. None of these

7) A card is drawn from a pack of 52 cards. The card is drawn at random. What is the probability that it is neither a heart nor a king?

1. 4/13
2. 7/13
3. 9/13
4. 11/13
5. None of these

8) A box contains 7 black and 5 white hair clips. 3 hair clips are drawn at random. What is the probability that one is black and the other 2 are white?

1. 15/22
2. 8/11
3. 7/22
4. 7/11
5. None of these

9) A pouch contains 4 black, 2 red and 5 blue pens. 2 pens are drawn at random. What is the probability that none of the pens drawn is blue?

1. 5/11
2. 15/11
3. 3/11
4. 17/11
5. None of these

10) A box contains 15 tube lights, out of which 6 are repair. 3 tube lights are chosen at random from this box. Find the probability that at least one of these is repair?

1. 53/65
2. 62/45
3. 84/65
4. 73/45
5. None of these

Answers:

1) Answer: B

Let s be the sample space.

Then n(S) = no. of ways of drawing 3 apples out of 12

= > 12C₃ = 12*11*10 / 3*2*1

= > 220

Let E = event of getting both apples of the same color. Then

n(E) = no. of ways of drawing 3 apples out of 7 or 3 apples out of 5

=7C₃ +5C₃

=7*6*5 / 3*2*1 + (5*4*3 / 3*2*1)

=35 + 10

=45

P(E) = n(E) / n(S)

= 45 / 220

= 9/44

2) Answer: B

Clearly n(s) = 6*6 = 36

Let E be the event that the sum of the numbers on the 2 faces is divisible by either 3 or 5. Then

E = {(1,2), (1,4), (1,5), (2,1), (2,3), (2,4), (3,2), (3,3), (3,6), (4,1), (4,2), (4,5), (4,6), (5,1), (5,4), (5,5), (6,3), (6,4), (6,6)}

n(E) = 19

Hence P(E) = n(E) / n(s)

= 19/ 36

3) Answer: B

Here n(S) = 52

There are 13 diamond cards (including one six) and also 3 more sixes are there.

Let E = event of getting a six or a diamond

Then n(E) = 13 +3

n(E) = 16

Therefore P(E) = n(E) / n(S)

=16 / 52

P(E) = 4/13

4) Answer: D

Let s be the sample space

Then n (S) = 52C₂

=52*51/2*1

=2652/2

=1326

Let E = event of getting 2 jack cards out of 4

n(E) = 4C₂ = 4*3 / 2*1

=12/2

=6

P(E) = n(E)/n(S) = 6/1326

=1/221

5) Answer: B

Total no. of roses = 5+3+7

=15

Let E = event that the rose drawn is neither red nor orange

n(E) = 3

Therefore P(E) = n(E) / n(s)

=3/15

=1/5

The probability that is neither red nor orange is 1/5

6) Answer: B

Let s be the sample space

Then n(S) = no. of ways of drawing 3 toys out of 18

=18C₃

=18*17*16 / 3*2*1

=816

let E = event of getting all the 3 blue balls

n(E) = 5C₃

=5*4*3 / 3*2*1

=10

P(E) = n(E) / n(S)

=10/816

=5/408

7) Answer: C

There are 13 heart and 3 king

Probability of getting heart or a king:

= (13+3)/52

=16/52

=4/13

So probability of getting neither hearts nor a king:

=1- 4/13

=9/13

8) Answer: C

Let s be the sample space. Then

n(S) = no. of ways of drawing 3 hair clips out of 12

=12C₃ = 12*11*10 / 3*2*1

=220

Let E = event of drawing 1 black and 2 white hairclips

n(E) = no. of ways of drawing 1 black out of 7 and 2 white out of 5

=7C₁ and 5C₂

=7*(5*4 / 2*1)

=7*10

=70

P(E ) = n(E) / n(S)

= 70/220

= 7/22

9) Answer: C

Total no. of pens = 4+ 2+5

=11

Let s be the sample space. Then

n(S) = no. of ways of drawing 2 pens out of 11

=11C₂ = 11*10 / 2*1

=55

Let E = event of drawing 2 pens, none of which is blue

n(E) = no. of ways of drawing 2 pens out of 6 pens

=6C₂

=6*5 / 2*1

=15

P(E) = n(E) / n(S)

=15 / 55

= 3/11

10) Answer: A

P(none is repair) = 9C₃ / 15C₃

= (9*8*7 / 3*2*1) / (15*14*13 / 3*2*1)

= (504/6) / (2730 / 6)

= 504/6 * 6/2730

= 504/2730

= 12/65

P(at least one is repair) = 1 – 12/65

= 53/65

Daily Practice Test Schedule | Good Luck

Click Here for More Quantitative Aptitude Questions

0 0 votes

Rating

Subscribe

Notify of

new follow-up comments new replies to my comments

Label

Name*

Email

Label

Name*

Email

0 Comments

Inline Feedbacks

View all comments

Load More Comments