Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June 2018. To enrich your preparation here we have providing new series of Profit and loss – Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.
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1). The selling price of a mobile phone including the sales tax is Rs. 16302. The rate of sales tax is 10%. If the shopkeeper has made a profit of 14%, the cost price of the mobile phone is?
2). After allowing a discount of 15% on the marked price of a pen, it is sold for Rs. 119. Then find its marked price?
3). The profit earned by selling a watch for Rs. 2400 is equal to the loss incurred by selling the same watch for Rs. 1680. At what price should the watch be sold to make 25% profit?
4). The cost of the towel is Rs. 50 for manufacturing, and it sold the product to a dealer for Rs. 60, who in turn sold it to a shopkeeper for Rs. 80, who sold it to a customer for Rs. 100. What is the percentage of profit for the company, who made the highest profit on selling the product?
5). The marked price of the LED TV is 20% above its cost price. He gives two successive discounts to customers of 10% and 25% respectively. As a result he incurred a loss of Rs.1900. At what price (in rupees) did he sell the LED TV to the customer?
6). A shop keeper procures 50 Novels for Rs. 4300 and sells them at a profit equal to the selling price of 7 books. What is the selling price of one dozen books, if the price of each book is same?
7). The teddy is marked 15% above the cost price. When the selling price of an article is increased by 25%, the profit gets increased Rs. 110. If the marked price of the article is Rs. 575, then find original selling price.
8). The company wishes to give 4% commission on the marked price of a product but also wants to earn a profit of 10%. If the cost price of the product is Rs. 120, then find the marked price is?
9). A shopkeeper marks a Branded Hard Disk 65% above the cost price and allows two successive discounts of 8% and 10% respectively. If he spent Rs. 8 on transport and the marked price is Rs. 250, what will be his profit percentage? (Approximately)
10). A shop keeper sells his items at 18% discount and incurs a loss of 3%. How much % above cost price does he mark up his items?
Answers:
1). Ans: C)
110 % of SP = 16302
SP of a mobile = (16302 / 110) * 100 = 14820
CP = (100 / 114) * 14820 = 13000
Cost price of the mobile = Rs. 13000
2). Ans: C)
Suppose, marked price of the article be Rs. X
Then, 85% of x = 119
X × (85 / 100) = 119
X = 119*(20/17) = 140
x = Rs. 140
3). Ans: C)
According to the question,
Profit = Loss
SP1 – CP = CP – SP2
2400 – CP = CP – 1680
2400 + 1680 = 2CP
CP = 4080/2 = 2040
SP = 2040 * (125 /100) = 2040 * (5/4) = Rs. 2550
(Or)
CP = (2400+1680)/2 = 2040
Required SP = 2040*125/100 = Rs.2550
4). Ans: B)
Company Profit % = (60-50)/50*100=100/5 =20 %
Then Dealers Profit % = (80-60)/60*100=100/3 =33 1/3 %
Then Shopkeeper Profit % = (100-80)/80*100 =25 %
Among the three, Dealer gets highest profit %
5).Ans: B)
To take CP = 100
Marked price = 120
120 * 90/100 * 75/100 = 81
Loss = 100 – 81 = 19
19 % of CP = 1900
CP = (100 /19) * 1900 = Rs. 10000
SP = 10000- 1900 = 8100
6). Ans: D
CP of 1 novel = Rs. 4300/50 = Rs.86
Now SP of 50 books = CP of 50 Novels + SP of 7 Novels
=> SP of 43 Novels = 4300
SP of 1 Novel = 4300/43 = Rs.100
Therefore,
Required SP of 1 dozen books = Rs. 1200
7). Ans: B)
Marked Price = Rs. 575
CP = 575 * (100/115) = 500
Profit = Selling Price – 500
And given that, when SP increased by 25%
Let the original selling price be Rs. x,
125/100 * SP – 500 = Profit + 110
5/4 x – 500 = (SP – CP) + 110
5x/4 – 500 = x – 500 + 110
5x/4 – x = 110
(5x – 4x) / 4 = 110
x = 440
Selling price = Rs. 440
8).Ans: B)
CP = Rs. 120
Then SP = 110/100 * 120 = 132
Let the marked price be x,
So, SP = 96 % of Marked price
132 = (96/100)* x
X = 132*(100/96) = 137.5
Required marked price = Rs. 137.5
9). Ans: A)
SP of Hard Disk = 250 * 92/100 * 90/100 = 207
Expense on transport = Rs. 8
CP = 250/165*100 = 152 (Approximately)
Profit % = [(207- (152+8))/(152+8)]*100 = 29%(Approximately)
10). Ans: B)
Let M.P = 100, then S.P. = (82 / 100) × 100 = 82
C.P = 82 × (100 / 97) = 84.5
Mark up above Cost Price = [(100 – 84.5) / 84.5] × 100 = 18.34%
Daily Practice Test Schedule | Good Luck
| Topic | Daily Publishing Time |
| Daily News Papers & Editorials | 8.00 AM |
| Current Affairs Quiz | 9.00 AM |
| Logical Reasoning | 10.00 AM |
| Quantitative Aptitude “20-20” | 11.00 AM |
| Vocabulary (Based on The Hindu) | 12.00 PM |
| Static GK Quiz | 1.00 PM |
| English Language “20-20” | 2.00 PM |
| Banking Awareness Quiz | 3.00 PM |
| Reasoning Puzzles & Seating | 4.00 PM |
| Daily Current Affairs Updates | 5.00 PM |
| Data Interpretation / Application Sums (Topic Wise) | 6.00 PM |
| Reasoning Ability “20-20” | 7.00 PM |
| English Language (New Pattern Questions) | 8.00 PM |
| General / Financial Awareness Quiz | 9.00 PM |
This post was last modified on September 24, 2020 11:05 am