Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June/July 2018. To enrich your preparation here we have providing new series of Ratio and Proportion- Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.
[WpProQuiz 1771]Click “Start Quiz” to attend these Questions and view Solutions
1) The ratio of the number of male and female in a committee is 5:6. If the percentage increase in the number of male and female be 12% and 10% respectively, what will be the new ratio?
A.33:28
B.28:33
C.27:34
D.34:27
E.None of these
2) A manager divided Rs 234 into three workers P, Q and R such that 4 times P’s share is equal to 6 times Q’s share which is equal to 3 times R’s share. How much did P get?
A.Rs 82
B.Rs 78
C.Rs 56
D.Rs 64
E.None of these
3) A box contains the coins of 5p, 10p and 25p are in the ratio 3:3:5. If there is Rs. 34 in all, how many 10p coins are there?
A.40
B.60
C.80
D.100
E.None of these
4) The wages of Naveena and Menaka are in the ratio ratio 6:5. If the wages of each is increased by Rs.6000, the new ratio becomes 38:35. What is Menaka’s present salary?
5) Ratio of the salary of X & Y is 5:8. If the salary of X increase by 40% and those of Y decrease by 15%, the new ratio of their salary becomes 10:9. What is X’s salary?
A.24000
B.25000
C.28000
D.data inadequate
E.None of these
6) The ratio of the number of UG students and PG students in a college is 5:4. If 40% of the UG students and 50 % of the PG students are scholarship holders. What percentage of the students does not get the scholarship?
A.54.6%
B.55.2%
C.55.5%
D.54.3%
E.None of these
7) Karan, Hari and Kowshik play cricket. The runs got by Karan to Hari and Hari to Kowshik are in the ratio of 5:3. They get altogether 588 runs. How many runs did Karan get?
Answers:
1) Answer: B
Originally, let the number of male and female in a committee be 5x and 6x respectively.
Their increased number is (112% of 5x) and (110% of 6x).
(112/100)*5 and (110/100)*6
=5.6 : 6.6
=56 : 66
=28 : 33
So, the required ratio = 28 : 33
2) Answer: B
4 times P’s share = 6 times Q’s share = 3 times R’s share
4*P = 6*Q
P/Q = 3/2
6*Q = 3*R
Q/R = ½
P : Q : R = 3 : 2 : 4
The sum of the total Salary,
3x+2x+4x=234
9x=234
X=234/9=26
Hence p gets =3x=3*26= Rs 78
3) Answer: B
Let the no. of 5p, 10p, 25 p coins be 3x, 3x & 5x respectively.
Then sum of their values = Rs. [(5*3x/100) + (10*3x /100) + (25*5x/100)]
=Rs. [(15x/100) + (30x /100) + (125x/100)]
=Rs. (15x+30x+125x / 100)
=Rs. (170x /100)
Therefore 170x / 100 = 34
X=34 *100/170
X=20
Hence the no. of 10p coins = 3x
=3*20
=60
4) Answer: D
Let the original salary of Naveena and Menaka be 6x and 5x respectively
Then, (6x+6000) / (5x+6000) = 38/35
35(6x+6000) = 38(5x +6000)
210x +210000 = 190x + 228000
210x – 190x = 228000 – 210000
20x = 18000
X=900
Menaka’s present salary = 5x
= 5*900 = Rs. 4500
5) Answer: D
Let the original salary of X & Y be 5x & 8x respectively
New salary of X = 40% of 5x
=140/100 * 5x
=700x /100
= 7x
New salary of Y = 85% of 8x
=185 /100 *8x
= 74x/5
Therefore 7x : 74x/5 = 10:9
7x*5/74x =10:9
We can’t find x, so the given data is inadequate
6) Answer: C
Let UG students be = 5x and
PG students be = 4x respectively
No. of those who do not get scholarship,
= 60% of 5x + 50% of 4x
= (60/100*5x) + (50/100*4x)
= 300x/100+ 200x /100
= 3x + 2x
= 5x
Required percentage = (5x/9x) *100
= 55.5%
7) Answer: B
Karan : Hari =5:3
Hari : Kowshik =5:3
Karan : Hari : Kowshik = 25:15:9
Therefore, the runs made by Karan,
=25/49*588
=25*12=300 runs
8) Answer: A
8A= 50B=> A/B=50/8
A : B= 50:8=>25:4
19C = 456
=>C=24
B=2*2C=4*24=96
4’S=96=>1’S=24
A=24*25=600
3A +4B=3*600+4*96=2184
9) Answer: B
Let the first and the third parts be 3x and 5x.
Second part = 1/4 of third part = (1/4) × 5x == 5x/4
Therefore, 3x + (5x/4) + 5x = 370
(12x + 5x + 20x)/4 = 370
37x/4 = 370
x = (370 × 4)/37
x = 10 × 4
x = 40
Therefore,
First part = 3x =3 × 40=120
Second part = 5x/4 =5 × 40/4=50
Third part = 5x =5 × 40=200
10) Answer: A
Two numbers are in the ratio of,
(1 ½): (2 2/3) =>3/2: 8/3 =>9:16 (9x, 16x)
1 2/3: 1 ½ =>5/3:5/2 =>2:3
9x+15/16x+15 =2/3
27x+45 = 32x+30
5x= 15
X=3
The larger of the numbers is, 16x= 48
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| Topic | Daily Publishing Time |
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This post was last modified on April 2, 2018 4:42 pm