Quantitative Aptitude

Quantitative Aptitude Questions (Simple Interest) Day-37

Quantitative Aptitude Questions (Simple Interest) for Day-37:

Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June/July. To enrich your preparation here we have providing new series of Simple Interest- Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.

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Topic Daily Publishing Time
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  1. Simple interest for the sum of Rs.1500 is Rs.50 in 4 years and Rs.80 in 8 years. Find the rate of SI?
  1. 0.5%
  2. 1%
  3. 1.5%
  4. 2%
  5. None of these

2) A sum of money amounts to Rs 19600 after 10 years and Rs 24010 after 16 years at the same rate of simple interest. The rate of interest per annum is:

  1. 4 %
  2. 3 %
  3. 5 %
  4. 6 %
  5. None of these

3) A sum of Rs. 2250 was lent partly at 7 % and 10% p.a. simple interest. The total interest received after 3 years was Rs.540. The ratio of the money lent at 7% to that lent at 10% is?

  1. 3:2
  2. 2:1
  3. 1:2
  4. 2:3
  5. None of these

4) A sum was put at S.I at a certain rate for 8 years. Had it been put at 4% higher rate, it would have fetched Rs. 480 more. What was the Sum?

  1. 1500
  2. 1700
  3. 1575
  4. 1650
  5. None of these

5). Sachin would have paid Rs. 5280 at the end of 4 years, for a sum of money borrowed, at rate of 8% p.a. S.I. If he wants to repay his loan a year before its due, then what is the amount paid by him?

  1. Rs. 5060
  2. Rs. 4960
  3. Rs. 4760
  4. Rs. 4670
  5. None of these

6). Veena obtained an amount of Rs. 8376 as simple interest on a certain amount at 8 p.c.p.a. after 6 years. What is the amount invested by Veena?

  1. Rs. 17180
  2. Rs. 18110
  3. Rs. 16660
  4. Rs. 17450
  5. None of these

7) A sum of Rs. 6200 is divided into 2 parts, one at 10% and another one at 6%. If the total interest received is Rs.424. Find the money lent at 6 % interest rate.

  1. Rs. 3000
  2. Rs. 4500
  3. Rs. 3400
  4. Rs. 4900
  5. None of these

8) Rs.1200 becomes Rs.1434 in 3 yrs at a certain rate of S.I. If the rate of interest is increased by 4%, then the amount will be?

  1. Rs1245
  2. Rs.1432
  3. Rs.1578
  4. Rs.1365
  5. None of these

9)  The S.I on a sum of money will be Rs. 300 after 5 yrs. If the principal is tripled after 2 ½ yrs, what will be the total interest at the end of the 5th year?

  1. 600
  2. 450
  3. 500
  4. 300
  5. None of these
  1. At simple interest, a sum becomes three times in 20 years. Find the time in which the sum will be double at the same rate of interest?
  1. 8 years
  2. 10 years
  3. 12 years
  4. 14 years
  5. None of these

Answers:

1). Answer: a

S.I = (PRT / 100)

According to the question, = [(1500 × R × 8) / 100] – [(1500 × R × 4) / 100] = 80 – 50 (12000R – 6000R) / 100 = 30

6000R / 100 = 30

R = 30/60 = ½ = 0.5%

2). Answer: d

We can get SI of 6 years = 24010 – 19600 = 4410

SI for 10 years = (4410/6)*10

= 7350 [so that we can get principal amount after deducting SI]

Principal = 19600 – 7350

= 12250

SI = PTR/100

R = SI *100 /PT

R= 7350*100 / 12250*10

R = 735000/ 122500

R = 6 %

3). Answer: b

let the sum lent at 7% be Rs.x and that

lent at 10% be Rs.(2250-x).

Then, Interest on x at 7% for 3 years + interest on (2250-x) at 10% for 3 years = 450

x*7*3/100 + (2250-x)*10*3/100 =540

21x/100 + (2250-x)30 /100 =540

21x/100 + 67500-30x/100 =540

21x+67500-30x = 54000

67500-9x =54000

9x =13500

X=1500

Required ratio =  x : (2250-x)

=1500:750

=2:1

4). Answer: a

At 4% more rate, the increase in S.I for 8 years = Rs.480

So, at 4% more rate, the increase in SI for 1 year = 480/8 = Rs.60/-

i.e. Rs.60 is 4% of the invested sum

So, 1% of the invested sum = 60/4

Therefore, the invested sum = 60 × 100/4

=Rs. 1500

(or)

(P*8*(r+4))/100 – (P*8*r)/100 = 480

(8P/100)(r+4-r) =480

P = 480*100/32 = Rs. 1500

5). Answer: b

P + (P × (8 / 100) × 4) = 5280

(33 / 25)P = 5280

P = Rs. 4000

Amount payable after 3 years

= 4000 + [4000 × (8 / 100) × 3] = Rs. 4960

6). Answer: d

S.I = (P × r × t) / 100

8736 = (P × 6 × 8) / 100 = (8736 × 100) / (6 × 8)

= Rs. 17450

7). Answer: d

Let the sum lent at 32% be x and

The sum lent at be (6200 – x)

(x*1*10/100) + ((6200-x)*1*6/100) = 424

10x/100 + 37200 – 6x/100 = 424

4x + 37,200 = 42400

X = 5200/4 = 1300

Money lent at 10% = Rs. 1300

Money lent at 6% = Rs. (6200 – 1300) = Rs. 4900

8). Answer: c

S.I = Rs(1434 – 1200)

=Rs. 234

R = SI *100 / P*N

R = 234 *100/1200*3

= 13/2 %

New rate = 13/2  + 4 = 21/2 %

New S.I = Rs. (1200 * 3 * 21 /200)

=Rs. 378

New amount = Rs. (1200 + 378)

=Rs.1578

9). Answer: a

Let the sum be Rs.x

Now S.I = Rs.300

T = 5years

R = 100*SI / P*T

= 100*300 / x*5

= (6000/x) %

S.I for first 2 ½ years = Rs. (x*5*6000 / 2*100*x)

=Rs.150

S.I for last 2 ½ years = Rs. (3x*5*6000 / 2*x*100)

=Rs.450

Therefore total interest = Rs. (450+150) = Rs. 600

10). Answer: b

Let Sum = P, T= 20 yrs;

∴ S.I = 3P – P = 2P

Formula for S.I = (PRT) / 100

2P = (P × R × 20) / 100

R = 10%

To find Time (T),

∴ S.I = 2P – P = P

P = (P × 10 × T) / 100

Hence, T = 10 yrs.

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This post was last modified on September 24, 2020 12:05 pm

7 years ago

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