Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June/July 2018. To enrich your preparation here we have providing new series of Time and Work- Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.
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1) A alone can do a piece of work in 20 days. B alone can do the same work in 5 days less than C. A and C together can do the same work in 12 days. B started working, after 2 days A joins with him for 2 days only and then C joins with him for last day only. If the remaining work completed by D alone in 5 days, then find the number of days taken by D alone to complete whole work
2) Vinoth is 50% less efficient than Gokul and they together can complete the work in 10 days. If they working together can complete whole work in 5 days, then find the number of days taken by Prabha and Vinoth working alternatively begins with Prabha
3) Manu and Sharan together can do a piece of work in 6 2/3 days. Sharan and Moni together can do the same work in 12 days. Manu and Moni together can do the same work in 7 1/2 days. If Manu, Sharan and Moni working together, then find the share of Manu, out of total share of Rs.5500
4) 12 men or x women can do a piece of work in 36 days. If 18 men and 9 women started working together and complete whole work in 19 1/5 days, then find the value of ‘x’
5) 24 boys or 48 girls can do a piece of work in 12 days. If 36 boys and x girls together can complete the whole work in 4 days, then find the value of ‘x’
6) A, B and C together can do a piece of work in 5 1/3 days. A and B together can do the same work in 6 6/7 days and B takes 4 days more than A. A and B started working together and every 3rd day C alone working until the work was completed. How many days are required to complete the whole work?
7) Sharmi alone can do a piece of work in 12 days who is 50% and 200% more efficient Sheeba and Akila respectively. Sheeba started working on first day, second day Sharmi joins with her and Akila joins with her on third day, how many days required to completing the whole work?
8) 40 men planned to complete a certain work in 20 days working 6 hours per day. After 15 days only three-fifth of the work was completed, how many extra men required to completing the work on time working 8 hours per day?
9) 20 men can do a piece of work in 24 days and 30 women can do the same work in 36 days. 12 men started working on first day and 24 women working on second day, then find the no. of days required to complete the whole work
10) A alone can do three-fourth of a work in 18 days. B alone can do five-eight of the same work in 20 days. C alone can do half of the same work in 24 days. Minimum no of days required completing the whole if two persons form a group and no group work on consecutive days?
Answers:
1) Answer b
A’s one day output = 1/20
B’s one day output = 1/25
C’s one day output = 1/30
Given,
=>5/25+2/20+1/30=(60+30+10)/300
=>100/300=1/3
Remaining =1- 1/3=2/3
(2/3)* D’s whole work= 5
D’s whole work= 15/2 days= 7 ½ days
2) Answer d
Efficiency ratio of Vinoth and Gokul = 1:2
Given,
1/x+1/2x=1/10
Simplify the above equation we get x=15 days
Prabha one day work = 1/5-1/10=1/10
Vinoth one day work = 1/30
1 cycle (2 days) =(1/10+1/30)=4/30
7th cycle (14 days) =28/30
Remaining =1- 28/30=2/30
Remaining work completed by Prabha = (2/30)/(1/10)=2/3
Required number of days =14+ 2/3=14 2/3 days
3) Answer a
Manu, Sharan and Moni together work = 1/2 (3/20+1/12+2/15)
=>1/2×(11/30)=11/60
Manu’s per day work = 1/10
Sharan’s per day work = 1/20
Moni’s per day work = 1/30
Efficiency ratio of Manu, Sharan and Moni = 1/10:1/20:1/30=6:3:2
Share of Manu = 6/11×5500=Rs.3000
4) Answer c
Given,
((96/5)×18)/(36×12)+((96/5)×9)/(36×X)=1
=>4/5+96/20x=1
=>96/20x=1/5
=>x=24
5) Answer e
36 boys 4 days work = (36×4)/(24×12)=1/2
Remaining =1- 1/2=1/2
Remaining work completed by x girls = (1/2)/((x×4)/(48×12))=1
=>x=72
6) Answer c
A, B and C together can do a piece of work in 5 1/3 days
(A+B+C)’s one day work=3/16
A and B together can do the same work in 6 6/7 days
(A+B)’s one day work = 7/48
C’s one day work = (3/16) – (7/48) = 1/24
B takes 4 days more than A
= > B = A + 4 (Let us assume A= x, B= x+4)
(1/x) +(1/(x+4)) = 7/48
7x2 -68x -192 =0
X=12
A’s per day work = 1/12
B’s per day work = 1/16
C’s per day work = 1/24
1 cycle (3 days) = 2(1/12+1/16)+1/24
= 16/48 = 1/3
3rd cycle (9 days) = 3/3
Required number of days 9 days
7) Answer e
LCM of 12, 18 and 36 = 36
Sharmi’s per day work = 1/12 =3 units
Sheeba’s per day work = 1/18 = 2 units
Akila’s per day work = 1/36 = 1 unit
1st day = 2 units
2nd day = 5 units
3rd day = 6 units
At the end of 3rd day 13 units completed out of 36 units
Required no. of days = 8 ½
8) Answer d
Given,
(40*15*6)/(3/5)=((40+x)*5*8)/(2/5)
X= 20
9) Answer a
Man per day work = 1/(20*24)
Woman per day work = 1/(30*36)
1 cycle (2 day) = 12/(20*24)+24/(30*36)
21st cycle (42 days) = 357/360
Remaining = 1-357/360 = 3/360
Required no of days = 42 1/3
10) Answer c
LCM of 24, 32 and 48= 96 units
A+B= 7 units
B+C= 5 units
A+C= 6 units
Most efficient group is A+B and Second most efficient group is A+C
1 cycle (2 days) = 7+6=13 units
7th cycle (14 days) = 91 units
Required no of days = 14 5/7
This post was last modified on June 12, 2021 12:43 pm