Quantitative Aptitude Questions (Time and Work) for SBI Clerk / IDBI Executive 2018 Day-69

Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June 2018. To enrich your preparation here we have providing new series of Time and Work- Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.

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1) The ratio of efficiency of Arun is to Chitra is 5:3. The ratio of number of days taken by Chitra to Banu is 2:3. Arun takes 8 days less than Chitra, when Arun and Chitra complete the work individually. Banu and Chitra started the work and left after 2 days. The number of days taken by Arun to finish the remaining work is?

1. 4 days
2. 5 days
3. 6 days
4. 10 days
5. None of these

2) Arun is twice efficient as Bavi and together they do the same work in as much time as Chitra and David together. If Chitra and David can complete the work in 20 and 30 days respectively, working alone, then in how many days Arun can complete the work alone?

1. 12 days
2. 18 days
3. 24 days
4. 30 days
5. None of these

3) Efficiency of A is 50% more than B and B takes 21 days to complete a piece of work. A started the work alone and then B joined with him in 5 days before actual completion of the work. For how many days A worked alone?

1. 6 days
2. 4 1/2 days
3. 5 2/3 days
4. 7 days
5. None

4) A piece of work has to be completed in 50 days, a number of men are employed but it is found that only half of the work is done in 30 days, then an additional 20 men were joined to complete the work on time. How many men initially put to work?

1. 30
2. 35
3. 40
4. 45
5. None of these

5) A tent can be built by a certain number of workers in 20 days. But it requires less than 20 workers to build it in 30 days. How many workers will build it in 50 days?

1.  30
2.  24
3.  50
4.  18
5.  None of these

6) A can do a particular work in 6 days. B can do the same work in 8 days. A and B signed to do it for Rs. 4000. They completed the work in 3 days with the help of C. How much is to be paid to C?

1.  Rs. 380
2.  Rs. 600
3.  Rs. 500
4.  Rs. 450
5.  None of these

7) Ram and Ravi can separately do a piece of work in 20 and 15 days respectively. They worked together for 6 days, after which Ravi was replaced by Rohit. If the work was finished in next 4 days, then the number of days in which Rohit alone could do the work will be?

1. 40
2. 42
3. 45
4. 50
5. None of these

8) A and B undertake to complete a piece of work for Rupees 1200. A can do it in 8 days, B can do it in 12 days and with the help of C they complete the work in 4 days. Find the share of C?

1. 100
2. 200
3. 300
4. 400
5. None of these

9) A and B can do a piece of work in 20 and 25 days respectively. They began the work together but A leaves after some days and B completed the remaining work in 12 days. Number of days after which A left the job-

1. 5 7/9 days
2. 6 7/9 days
3. 7 7/9 days
4. 11 7/9 days
5. None of these

10) P can do a piece of work in 20 days. Q is 25 percent more efficient than P. In how many days half the work is completed when both are working simultaneously?

1. 41/9 days
2. 40/9 days
3. 39/9 days
4. 43/9 days
5. None of these

Answers:

1)Answer:  D

The ratio of efficiency of Arun and Chitra = 5:3

The ratio of number of days taken by Arun and Chitra = 3 : 5

The ratio of number of days taken by Chitra and Banu = 2:3

Ratio of number of days taken by Arun : Chitra : Banu = 6:10:15

According to the question,

= > Chitra – Arun = 8 days

= > 10’s – 6’s = 8

= > 4’s = 8

= > 1’s = 2

Number of days taken to finish the whole work,

= > Arun = 12 days, Chitra = 20 days, Banu = 30 days

Work done by Banu and Chitra in two days,

= > (2/20) + (2/30) = (1/10) + (1/15) = 25/(10*15) = (1/6)

Rest of the work = 5/6

The number of days taken by Arun to finish the remaining work is,

Number of days = (5/6)*12= 10 days

2) Answer: B

1/x + 1/2x = 1/20 + 1/30

3/2x = 1/12

X = 18

Number of days taken by Arun = 18 days

3) Answer: C

Efficiency (A : B) =150:100= 3 : 2

Then days 2:3

B takes 21 days to do the work. Then A takes 14 days to do the work.

Total units of work = 42(LCM of 14,21)

A = 3 unit

B = 2 unit

A and B worked for 5days ==>5*(3+2) = 25 unit

Remaining = (42-25) =17 unit

Then A did that 17 unit alone in 17/3= 5 2/3 days.

4) Answer: C

Let the no of men be x,

A piece of work has to be completed in 50 days

According to the question,

Men            days  work

X                30      (1/2)

(x +20)        20      (1/2)

Work = men * days

= > 30x/(1/2) = (x + 20)*20/(1/2)

= > 30x = (x + 20)*20

= > 30x = 20x + 400

= > 10x = 400

= > x = 40 men

5)Answer:  B

Let, x workers can do the work in 20 days.

Then no of workers require to finish it in 30 days is 20x / 30

20x/30 = (x – 20)

10x = 600

x = 60

So, the no of workers required to finished it in 50 days = (60 * 20) / 50 = 24 workers.

6) Answer: C

A = 6 days

B = 8 days

C = (1/3) – (1/8 + 1/6) = 1/24

So, C alone can complete the work in 24 days.

Then the ratio 1/6 : 1/8 : 1/24 = 4 : 3 : 1

Now total amount Rs. 4000

8’s = 4000

1’s = 500

The amount paid to C is Rs 500.

7) Answer: A

Ram and Ravi worked together

1/20+1/15 = (3+4)/60= 7/60

They work for 6 days so 7/60*6 = 7/10

Remaining work 3/10 done by Ram and Rohit.

Ram and Rohit finished it in 4days

(3/10)*(Ram + Rohit)’s whole work = 4

(Ram + Rohit)’s whole work = 40/3

Rohit’s one day work = (3/40) – (1/20) = 1/40

Rohit alone can complete the work in 40 days

8) Answer: B

1/8 + 1/12 + 1/C = ¼

1/C = (1/4) – (1/8 + 1/12)

(1/C) = (1/4) – (5/24) = 1/24

We get C = 24 days

Now efficiency of A, B and C are in the ratio of = 1/8 :1/12 : 1/24 = 3 : 2 : 1

6’s = 1200

1’s = 200

So share of C = Rs. 200

9) Answer: A

(1/20 + 1/25)*x + 12/25 = 1

(1/20 + 1/25)*x = 1 – (12/25)

(1/20 + 1/25)*x = 13/25

9x/100 = 13/25

We will get x = 52/9

X = 5 7/9 days

10)Answer:  B

Q is 25 percent more efficient than P

Efficiency ratio Q : P = 5 : 4

Days ratio Q : P = 4 : 5

P can do a piece of work in 20 days

5’s = 20 = > 1’s = 4

So Q can complete the work in 16 days

(1/20 + 1/16)*x = ½

X = 40/9 days

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