Quantitative Aptitude Questions (Time and Work) for SBI Clerk 2018 Day- 103

Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June 2018. To enrich your preparation here we have providing new series of Time and Work- Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.

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1. A, B and C together complete the work in 6 12/43 days while B alone can complete the work in 15 days and C alone can complete the same work in 27 days. How many days A can take to complete the work alone?

1. 14 days
2. 22 days
3. 18 days
4. 16 days
5. None of these

2. 5 men can complete a work in 12 days, 8 women can complete it in 18 days and 10 children can complete the same work in 24 days. In how many days can 10 men, 12 women and 8 children complete the same work?

1. 3 9/17 days
2. 4 2/9 days
3. 5 3/7 days
4. 6 6/11 days
5. None of these

3. 4 men or 6 women or 9 boys can finish a work in 98 days, and then the number of days taken by 6 men, 4 women and 5 boys to finish the work is?

1. 28 days
2. 32 days
3. 24 days
4. 36 days
5. None of these

4. A, B and C can do a piece of work in 15 days, 18 days and 24 days respectively. All of them started the work together after 5 days B and C left the work. Then in how many days A alone can do the remaining work?

1. 3 12/27 days
2. 2 17/24 days
3. 4 7/13 days
4. 5 5/7 days
5. None of these

5. 18 men can finish a piece of work in 50 days. 15 men started working and in 40 days they finished a certain part of the work. If it is required to finish the remaining work in 6 days, then how many men must be added to the existing workforce?

1. 24
2. 35
3. 32
4. 20
5. None of these

6. 7 women and 5 men can do a work in 8 days. 6 women and 9 men can do a same work in 6 days. How long will 6 women and 7 men can take to do the work?

1. 7 1/14 days
2. 5 3/7 days
3. 4 2/5 days
4. 6 7/9 days
5. None of these

7. Two men undertook to do a piece of work for Rs. 3600. One alone could do it in 15 days and the other can do it in 10 days while with the assistance of a boy, work gets completed in 4 days. Find the share of boy?

1. 1500
2. 1300
3. 1000
4. 1200
5. None of these

8. A can complete one-third of the work in 5 days and B can complete the two-fifth of the same work in 12 days. Then in how many days A and B together complete the work?

1. 12 days
2. 14 days
3. 10 days
4. 16 days
5. None of these

9. Aravind is four times as efficient as Priya and together they do the same work in as much time as Kalai and Deviga together. If Kalai and Deviga can complete the work alone in 24 and 30 days respectively, then in how many days Aravind can complete the work alone?

1. 14 5/7 days
2. 16 2/3 days
3. 18 ¼ days
4. 17 ½ days
5. None of these

10. Rajiv and Rajesh can separately do a piece of work in 15 and 24 days respectively. They worked together for 8 days, after which Rajesh was replaced by Ranga. If the work was finished in next 1 day, then the number of days in which Ranga alone could do the work will be?

1. 18 days
2. 22 days
3. 15 days
4. 20 days
5. None of these

 

Answers:

1. Answer c

A, B and C together complete the work in = 6 12/43 days = 270/43

(A + B + C)’s one day work = 43/270

B’s one day work = 1/15

C’s one day work = 1/27

A’s one day work = (43/270) – (1/15 + 1/27)

= > 43/270 – 14/135 = 15/270

A can take to complete the work alone in 18 days.

2. Answer a

1 man’s 1 day’s work= 1/60

1 woman’s 1 day’s work= 1/144

1 child’s 1day’s work= 1/240

So,

Required days = (10/60 +12/144 + 8/240)

= 1/6 + 1/12 + 1/30

= 17/60

Required days = 60/17 = 3 9/17 days

3. Answer d

4 men = 9 boys => 1man = 9/4 boys

6 women= 9 boys => 1 woman = 3/2 boys

6 men + 4 women + 5 boys= (6×9/4) + (4×3/2) + 5 = 49/2 boys

Boys           days

9                 98

49/2            ?

Now, B1*D1= B2*D2

9*98=49/2*D2

D2= 36 days

4. Answer b

(A + B + C)’s one day work = (1/15) + (1/18) + (1/24)

= > (59/360)

(A + B + C)’s 5 day work = (59/360)*5 = 59/72

Remaining work = 1 – (59/72) = 13/72

Remaining work done by A alone in,

= > (13/72)*15 = 65/24 = 2 17/24 days

5. Answer b

Total work = 18*50 = 900 units

Remaining work = 900 – (15*40) = 300 units

Let x men be added to finish the remaining work in 6 days

(15 + x)*6 = 300

15 + x = 50

X = 50 -15 = 35

6. Answer a

Total work = (men (or) women)*days

Work equal, so,

(7 w + 5 m)*8 = (6 w + 9 m)*6

56 w + 40 m = 36 w + 54 m

20 w= 14 m

10 w = 7 m

1 w = (7/10) m => 1m = 10/7 w

7 w + 5 m = 7 w + (50/7) w = 99/7 w

6 w + 7 m = 6 w + 10 w = 16 w

Women        days

(99/7)                   8

16               ?

(99/7)*8 = 16x

X= 99/14 days = 7 1/14 days

7. Answer d

(1/15) + (1/10) + 1 boy = (1/4)

1 boy = (1/4) – [(1/15) + (1/10)]

1 boy = (1/4) – (1/6) = (6 – 4)/24 = 1/12

The share of two men and a boy = (1/15): (1/10): (1/12)

= > 4: 6: 5

15’s = 3600

1’s = 240

The share of boy = Rs. 1200

8. Answer c

A can complete 1/3^rd of the work = 5 days

A can complete the whole work in = 5*3 = 15 days

B can complete 2/5^th of the work = 12 days

B can complete the whole work in =12*(5/2) = 30 days

(A + B)’s one day work = (1/15) + (1/30) = 1/10

A and B together can complete the work in, 10 days

9. Answer b

1/x + 1/4x = 1/24 + 1/30

5/4x = 3/40

X = 50/3

Number of days taken by Aravind = 16 2/3 days

10. Answer c

Rajiv and Rajesh worked together

1/15+1/24 = 13/120

They work for 8 days so (13/120)*8 = 26/30 = 13/15

Remaining work 2/15 done by Rajiv and Ranga.

Rajiv and Ranga finished it in 1 day

(2/15)*(Rajiv + Ranga)’s whole work = 1

(Rajiv + Ranga)’s whole work = 15/2

Ranga’s one day work = (2/15) – (1/15) = 1/15

Ranga alone can complete the work in 15 days

 

 

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