Dear Readers, SBI is conducting Online preliminary Examination for the recruitment of Clerical Cadre. preliminary Examination of SBI Clerk was scheduled from June 2018. To enrich your preparation here we have providing new series of Time and work – Quantitative Aptitude Questions. Candidates those who are appearing in SBI Clerk Prelims Exam can practice these Quantitative Aptitude average questions daily and make your preparation effective.
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1) A alone can do a piece of work in x days. B alone can do the same work in 5 days more than A. C alone can do the same work in 15 days. If all of them working together and completed the work in 7 1/7 days, then find the value of ‘x’
a) 20
b) 25
c) 30
d) 10
e) 12
2) M & N do a certain work in 40 days and 24 days respectively. M started the work alone and then after 8 days N joined him till the completion of the work. How long did the work last?
a) 16days
b) 18days
c) 20 days
d) 22 days
e) None of these
3) Kathir takes thrice as much time as Karthi and twice as much as Krish to finish a piece of work. Together they finish the work in 3 days. What is the time taken by Karthi to finish the work?
4) Moni can do a piece of work in 18 days, Moni and Jack together can do in 9 days. If Jack does the work only for half a day daily then in how many days the work will be completed?
5) Rishwi can finish a work in 6 days working 4 hours a day. Dhiviksha can complete the same work in 4 days working 5 hrs a day. If both Rishwi and Dhiviksha work together, working 4 hrs a day, in how many days can they finished the work?
a) 30/11
b) 11/120
c) 11/30
d) 30/13
e) None of these
6) Karthi is 40% more efficient than Rajesh, and Karthi can alone do a work in 20 days. If they working in alternative days starts with Karthi, then in how many days the work will get completed?
7) ‘X’ men can complete a piece of work in 40 days. If there were 8 men more, the work could be finished in 10 days less. The original number of men is:
8) If 10men or 20 women or 50 children can complete the work in 9 months, if 5 men and10 women and 10 children can complete the work in how many months?
9) Preethi can complete the work in 24 minutes and Shri can complete the work in 36 minutes. Kavitha can complete the work in 6/5 th of efficient by both Preethi and Shri together. Find the total time taken by all together to complete the work.
10) A, B and C alone can finish a work in 48, 30 and 24 days respectively. A, B and C started working together and C left the work after 8 days and B left the work 6 days before it got completed. Only A worked till the end to finish the work. How many days A worked together with B?
Answers:
1). Answer: b
Given,(1/x) + (1/(x+5)) +1/15 = 7/50
(1/x) + (1/(x+5)) = 7/50 – 1/15
(2x+5)/(x2+5x) = 11/150
11x2-245x-750 =0
Simplify the above equation, we get x = -30/11, 275/11=25, (Eliminate –ve value)
X= 25 days
2). Answer: C
Work done by M in 8 days = 1/40*8=1/5
Remaining work = 1-1/5 = 4/5
(M+N)’s 1 day work = 1/40 + 1/24
= (3+5)/120 =8/120
=1/15
Now 1/15 work is done by M & N in 1 day.
So 4/5 work will be done by X and Y is,
=15 * 4/5
=12 days
Hence total time taken = 12+8 = 20 days
3). Answer: C
Kathir takes thrice as much time as Karthi and twice as much as Krish,Kathir takes x days, Karthi takes x/3 days and Krish takes x/2 days
Together they work then finished in 3 days
(1/x) + (3/x) + (2/x) = 1/3
6/x = 1/3
x = 18
Karthi takes 18/3 = 6 days
So, Karthi takes 6 days to complete work.
4). Answer: D
Moni’s 1 day work = 1/18They can together complete in 9 days.
Jack’s 1 day work = 1/9 – 1/18 = 1/18
If Jack works only for half a day daily, then his 1 day work becomes (1/2)*(1/18) = 1/36
Therefore, 1 day work of both Moni and Jack,
= 1/18 + 1/36 = 3/36 = 1/12
Hence, the work will be completed in 12 days.
5). Answer: A
Rishwi can complete the work in (6*4) = 24 hrsDhiviksha can complete the work in (4*5) = 20 hrs
Rishwi’s 1 hr work = 1/24
Dhiviksha’s 1 hr work = 1/20
(Rishwi and Dhiviksha)’s 1 hr work = (1/24 + 1/20)
= (5+6)/120 = 11/120
So both Rishwi and Dhiviksha will finish the work in (120/11) hrs
Number of days of 4 hrs each = 120/11*1/4
=120/44
=30/11 days
6). Answer: d
The ratio of Efficiency of Karthi and Rajesh= 140:100 = 7:5Then work ratio of Karthi and Rajesh=5:7
Now given that, Karthi’s one day’s work= 1/20
Then Rajesh’s one day’s work= 1/28
Thus in two days, the work done by them= 1/20+1/28=12/140
Then work done by them in 22 days= (12*11)/140 = 132/140
Work done by them in 23 days = (132/140) + (1/20) = 139/140
Remaining work = 1- (139/140) = 1/140
Remaining work done by Rajesh in = (1/140)*28 = (1/5) days
Thus total days to complete the work= 23 + (1/5) = 23 (1/5) days
7). Answer: D
Let the number of men is ”a”a*40 = (a+8)30
40a=30a+240
10a=240 => a=24
8). Answer: D
10 men =50 children5 men =25 children
20 women = 50 children
10 women = 25 children
50 children can complete it on 9 months
= 25+25+10 =60
= (50*9)/60 =7.5 months
9). Answer: B
Total work = 72Preethi = 24 minutes = 3 work/min
Shri = 36 minutes = 2 work/min
Kavitha = 12 minutes = 6 work/min (<= (6/5)*(3+2))
Total work done in one minute = 11 works
= 72 /11 = 6 6/11 min
10). Answer: a
Solution:
Let x be the total number of days to complete the work.
x/48 + (x-6)/30 + 8/24=1
(5x+8x-48+80)/240=1
13x +32=240
x=16 days
Thus number of days A worked with B=(x-6) days = 10 days
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This post was last modified on March 18, 2022 8:50 am