Dear Aspirants, Our IBPS Guide team is providing new series of Quantitative Aptitude Questions for LIC AAO Mains 2019 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
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Directions (Q. 1 – 5): Study the following information carefully and answer the given questions:
The following pie chart1 shows percentage distribution of total number of students studied in six different colleges.
The pie chart2 shows the percentage distribution of total number of girls studied in six different colleges.
Note:
- All the questions are different from each other.
1) Find the difference between the total number of girls studied in college P and R together to that of total number of students studied in college Q, if the ratio between the total number of boys to that of girls studied in college S is 4 : 5?
a) 150
b) 250
c) 300
d) 400
e) None of these
2) Find the ratio between the total number of students studied in college R to that of total number of boys studied in college S and U together, if the total number of boys studied in college P is 2100 more than the total number of girls studied in the same college?
a) 15 : 7
b) 23 : 11
c) 59 : 43
d) 45 : 32
e) None of these
3) Total number of girls studied in college Q and S together is approximately what percentage of total number of boys studied in college R and T together, if the ratio between the total number of girls to that of boys studied in college U is 11 : 13?
a) 104 %
b) 89 %
c) 72 %
d) 56 %
e) 127 %
4) Find the average number of boys studied in college P, Q and R together, if the ratio between the total number of girls to that of boys studied in college S is 5 : 6?
a) 7150
b) 6900
c) 6650
d) 6400
e) None of these
5) Find the difference between the average number of girls studied in college P, R and S together to that from college Q, T and U together?
a) 400
b) 650
c) 500
d) 250
e) None of these
Directions (Q. 6 – 10): Study the following information carefully and answer the given questions:
The following pie chart shows the percentage distribution of total population of 6 different cities in a certain state.
The following table shows the percentage of population of above poverty line in 6 different cities. Some values are missing here.
6)Find the ratio between the total male population in city A to that of total female population in city F, if the ratio between the male to that of female population in city A and city F is 6 : 5 and 2 : 3 respectively?
a) 2 : 1
b) 5 : 4
c) 3 : 2
d) 7 : 5
e) None of these
7) Find the difference between the total below poverty line population in city A and B together to that of total above poverty line population in city E and F together, if the ratio between the above poverty line to that of below poverty line population in city B is 33 : 17 and the percentage of below poverty line population in city E is 32 %?
a) 50000
b) 75000
c) 60000
d) 35000
e) None of these
8) Find the average number of above poverty line population in city A, C and F together?
a) 256000
b) 262000
c) 288000
d) 274000
e) None of these
9) Total above poverty line population in city D and F together is what percentage of total female population in city B and E together, if the ratio between the male to that of female population in city B and city E is 2 : 3 and 4 : 3 respectively and the percentage of below poverty line population in city D is 38 %?
a) 84 %
b) 92 %
c) 98 %
d) 76 %
e) None of these
10) Find the difference between the average total population of city B, C and D together to that of the average above poverty line population of city A, C and F together?
a) 152000
b) 168000
c) 176000
d) 184000
e) None of these
Answers:
1) Answer: a)
Total number of girls studied in college S = 20000*(20/100) = 4000
Total number of students studied in college S = (4000/5)*9 = 7200
(16/100)*Total students in all the colleges = 7200
Total students in all the colleges = 7200*(100/16) = 45000
The total number of girls studied in college P and R together
= >20000*(33/100) = 6600
The total number of students studied in college Q
= >45000*(15/100) = 6750
Required difference = 6750 – 6600 = 150
2) Answer: d)
Total number of girls studied in college P
= > 20000*(15/100) = 3000
Total number of students studied in college P
= > 3000 + 3000 + 2100 = 8100
(18/100)*Total number of students studied in all the colleges = 8100
Total number of students studied in all the colleges
= > 8100*(100/18) = 45000
The total number of students studied in college R
= > 45000*(20/100) = 9000
The total number of boys studied in college S and U together
= >[45000*(16/100) – 20000*(20/100)] + [45000*(12/100) – 20000*(11/100)]
= > [7200 – 4000] + [5400 – 2200]
= > 3200 + 3200 = 6400
Required ratio = 9000 : 6400 = 45 : 32
3) Answer: b)
Total number of girls studied in college U = 20000*(11/100) = 2200
Total number of students studied in college U
= > (2200/11)*24 = 4800
(12/100)*Total number of students studied in all the colleges = 4800
Total number of students studied in all the colleges
= > 4800*(100/12) = 40000
Total number of girls studied in college Q and S together
= > 20000*(33/100) = 6600
Total number of boys studied in college R and T together
= >[40000*(20/100) – 20000*(18/100)] + [40000*(19/100) – 20000*(23/100)]
= > [8000 – 3600] + [7600 – 4600]
= > 4400 + 3000 = 7400
Required % = (6600/7400)*100 = 89.189 % = 89 %
4) Answer: c)
Total number of girls studied in college S = 20000*(20/100) = 4000
Total number of students studied in college S
= > (4000/5)*11 = 8800
(16/100)*Total number of students studied in all the colleges = 8800
Total number of students studied in all the colleges
= > 8800*(100/16) = 55000
The total number of boys studied in college P, Q and R together
= >[55000*(18/100) – 20000*(15/100)] + [55000*(15/100) – 20000*(13/100)] + 55000*(20/100) – 20000*(18/100)]
= > [9900 – 3000] + [8250 – 2600] + [11000 – 3600]
= > 6900 + 5650 + 7400 = 19950
Required average = 19950/3 = 6650
5) Answer: a)
The average number of girls studied in college P, R and S together
= >20000*(53/100)*(1/3)
The average number of girls studied in college Q, T and U together
= >20000*(47/100)*(1/3)
Required difference = 20000*(1/3)*(1/100)*[53 – 47] = 400
Directions (6-10):
6) Answer: a)
The average number of girls studied in college P, R and S together
= >20000*(53/100)*(1/3)
The average number of girls studied in college Q, T and U together
= >20000*(47/100)*(1/3)
Required difference = 20000*(1/3)*(1/100)*[53 – 47] = 400
7) Answer: a)
The total male population in city A
= >450000*(100/18)*(22/100)*(6/11)
The total female population in city F
= >450000*(100/18)*(10/100)*(3/5)
Required ratio = [450000*(100/18)*(22/100)*(6/11)] : [450000*(100/18)*(10/100)*(3/5)]
= > 2 : 1
8) Answer: c)
The total below poverty line population in city A and B together
= >450000*(100/18)*(22/100)*(26/100) + 450000*(100/18)*(20/100)*(17/50)
= > 143000 + 170000 = 313000
The total above poverty line population in city E and F together
= >450000*(100/18)*(14/100)*(68/100) + 450000*(100/18)*(10/100)*(54/100)
= > 238000 + 135000 = 373000
Required difference = 373000 – 313000 = 60000
9) Answer: d)
The average number of above poverty line population in city A, C and F together
= >[450000*(100/18)*(22/100)*(74/100) + 450000*(100/18)*(16/100)*(70/100) + 450000*(100/18)*(10/100)*(54/100)]/3
= > [407000 + 280000 + 135000]/3
= >822000/3 = 274000
10) Answer: b)
Total above poverty line population in city D and F together
= >450000*(62/100) + 450000*(100/18)*(10/100)*(54/100)
= >279000 + 135000 = 414000
Total female population in city B and E together
= >450000*(100/18)*(20/100)*(3/5) + 450000*(100/18)*(14/100)*(3/7)
= > 300000 + 150000 = 450000
Required % = (414000/450000)*100 = 92 %
