Dear Aspirants, Our IBPS Guide team is providing new pattern Quantitative Aptitude Questions for IBPS Clerk Mains 2019 so the aspirants can practice it on a daily basis. These questions are framed by our skilled experts after understanding your needs thoroughly. Aspirants can practice these new series questions daily to familiarize with the exact exam pattern and make your preparation effective.
[WpProQuiz 7562]
Caselet
Directions (1 – 5): Read the following information carefully and answer the given questions.
In one of the college there are 1300 employees. The college has five departments – CSE, EEE, ECE, Civil and Mech. Out of the total number of female employees in the college, 30% work in CSE department, 22% work in ECE department, 18% work in EEE department, 12% work in Mech department and remaining 90 female employees work in Civil department. Out of the total number of male employees in the college, 18% work in CSE department, 20% work in ECE department, 30% work in Mech department, 22% work in EEE department and the remaining employees work in Civil department.
1) The total number of male employees working in the civil and EEE department together is approximately what percent of the total number of employees (both male and female) working in CSE and ECE department together?
a) 45%
b) 43%
c) 47%
d) 42%
e) 49%
2) If the male employees in ECE department is increase by 20%, the male employees in the Civil department increase by 10%, 25% of male employee increased by Mech department and 16 male employees Joins CSE department and the number of male employees in the EEE department is same, what is the percentage increase in the number of male employees in the college?
a) 12.5%
b) 14.5%
c) 16.5%
d) 10.5%
e) None of these
3) If 50 female employees from CSE department are transferred to the Mech department and 20 male employees from Mech department are transferred to the CSE department, what is the ratio of the number of female employee to the number of male employees in the Mech department after the transfer the employees?
a) 1: 2
b) 2: 5
c) 3: 2
d) 5: 3
e) None of these
4) What is the average number of employees (both male and female) who work in CSE, Mech and ECE department together?
a) 268
b) 258
c) 288
d) 298
e) None of these
5) What is the difference between the number of employees (both male and female) working in EEE department and the number of employees (both male and female) working in Civil department?
a) 76
b) 66
c) 86
d) 96
e) None of these
Number series
Directions (6 – 10): The questions below are based on the given Series-I. The series-I satisfy a certain pattern, follow the same pattern in Series-II and answer the questions given below.
6)
a) 850
b) 900
c) 920
d) 825
e) 720
7)
a) 202
b) 196
c) 144
d) 112
e) 214
8)
a) 65
b) 73
c) 87
d) 53
e) 51
9)
a) 210
b) 187
c) 193
d) 171
e) 157
10)
a) 524
b) 612
c) 670
d) 718
e) 656
Answers:
Directions (1 – 5):
18% of female employees work in Civil department = 90
Total number of female employees in the college = 500
Number of female employees in CSE department = 500 * 30/100 = 150
Number of female employees in ECE department = 500 * 22/100 = 110
Number of female employees in EEE department = 500 * 18/100 = 90
Number of female employees in Mech department = 500 * 12/100 = 60
Total number of male employees in the college = 1300 – 500 = 800
Number of male employees in CSE department = 800 * 18/100 = 144
Number of male employees in EEE department = 800 * 22/100 = 176
Number of male employees in ECE department = 800 * 20/100 = 160
Number of male employees in Mech department = 800 * 30/100 = 240
Number of male employees in Civil department = 800 * 10/100 = 80
1) Answer: a)
Number of male employee in Civil department = 80
Number of male employee in EEE department = 176
Total male of Civil and EEE = 256
Total number of employees in CSE department = 294
Total number of employees in ECE department = 270
Total employees of ECE and CSE = 564
Required percentage = 256 * 100/564 = 45%
2) Answer: b)
Number of male employees in ECE department = 160 * 120/100 = 192
Number of male employees in Civil department = 80 * 110/100 = 88
Number of male employees in Mech department = 240 * 125/100 = 300
Number of male employees in CSE department = 144 + 16 = 160
Number of male employees in EEE department = 176
New total number of male employees in the college = 916
Required percentage = (916 – 800) * 100/800 = 14.5%
3) Answer: a)
After transferred the number of female employees in Mech department
= 60 + 50 = 110
After transferred number of male employees in Mech department
= 240 – 20 = 220
Required ratio = 110: 220 = 1: 2
4) Answer: c)
Average = (294 + 300 + 270)/3 = 864/3 = 288
5) Answer: d)
Difference = 266 – 170 = 96
Directions (6-10):
6) Answer: a)
Series I pattern:
1549 – 192 (361) = 1188
1188 – 172 (289) = 899
899 – 152 (225) = 674
674 – 132 (169) = 505
505 – 112 (121) = 384
Series II pattern:
2015 – 192 (361) = 1654
1654 – 172 (289) = 1365
1365 – 152 (225) = 1140
1140 – 132 (169) = 971
971 – 112 (121) = 850
7) Answer: d)
Series I pattern:
14 * 2 + 2 = 28+2 = 30
30 * 2 + 4 = 60 + 4 = 64
64 * 2 + 8 = 128 + 8 = 136
136 * 2 + 16 = 272 + 16 = 288
288 * 2 + 32 = 576 + 32 = 608
Series II pattern:
3 * 2 + 2 = 6 + 2 = 8
8 * 2 + 4 = 16 + 4 = 20
20 * 2 + 8 = 40 + 8 = 48
48 * 2 + 16 = 96 + 16 = 112
112 * 2 + 32 = 224 + 32 = 256
8) Answer: b)
Series I pattern:
137 + 15 = 152
152 + 20 = 172
172 + 25 = 197
197 + 30 = 227
227 + 35 = 262
Series II pattern:
73 + 15 = 88
88 + 20 = 108
108 + 25 = 133
133 + 30 = 163
163 + 35 = 198
9) Answer: c)
Series I pattern:
Series II pattern:
10) Answer: d)
Series I pattern:
153 – 1 = 3374
133 – 3 = 2194
113 – 5 = 1326
93 – 7 = 722
73 – 9 = 334
53 – 11 = 114
Series II pattern:
193 – 1 = 6858
173 – 3 = 4910
153 – 5 = 3370
133 – 7 = 2190
113 – 9 = 1322
93 – 11 = 718
