CWC/FCI Prelims 2019 – Quantitative Aptitude Questions (Day-54)

Dear Readers, Exam Race for the Year 2019 has already started, CWC/ FCI will be the most expected exam among the aspirants. Preparation and performance both requisite to clear CWC/FCI Exam. To enrich your preparation here we are providing a new series of Practice Questions on CWC/ FCI Quantitative Aptitude Section. Aspirants, practice these questions on a regular basis to improve your score in the aptitude section. Start your effective preparation from the right beginning to get success in the upcoming CWC/FCI Exam.

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Directions (Q. 1 – 5): In the following questions, two equations I and II are given. You have to solve both the equations and give answer as,

a) If x > y

b) If x ≥ y

c) If x < y

d) If x ≤ y

e) If x = y or the relation cannot be established

1) I) x2 – 16x + 55 = 0

II) 2y2 – y – 36 = 0

2) I) 3x2 + 4x – 64 = 0

II) 2y2 – 21y + 52 = 0

3) I) x2 + 15x + 56 = 0

II) y2 + 13y + 42 = 0

4) I) x2 + x – 132 = 0      

II) y2 – 13y – 48 = 0

5) I) x2 – 12x + 36 = 0   

II) 5y2 + 4y – 12 = 0

Directions (Q. 6 – 10): Study the following information carefully and answer the given questions.

The following table shows the total number of people (Male + Female) went for 5 different hotels and ate some veg and non-veg items in a certain week. The ratio of veg to that of non-veg items also given here.

Hotels Total people Veg : Non-veg
A 1800 5 : 4
B 2500 2 : 3
C 3600 4 : 5
D 2000 3 : 2
E 2800 3 : 4

 

6) Find the difference between the total number of male eating veg to that of total number of female eating non-veg from hotel A, if the percentage of total number of female eating veg and that of male eating non-veg from hotel A is 52 % and 45 %?

a) 40

b) 60

c) 80

d) 20

e) None of these

7) Find the ratio between the total number of people eating Veg from hotel B and D together to that of total number of people eating non-veg from hotel C and E together?

a) 23: 29

b) 19: 25

c) 34: 47

d) 11: 18

e) None of these

8) Find the total number of people eating non-veg from hotel B, C and D together?

a) 3800

b) 4300

c) 4700

d) 3500

e) None of these

9) Total number of people eating non-veg from hotel E is what percentage of total number of people eating veg from hotel A?

a) 125 %

b) 140 %

c) 160 %

d) 175 %

e) None of these

10) Find the difference between the average number of people went for hotel A and C together to that of the average number of people went for hotel B and D together?

a) 600

b) 300

c) 750

d) 450

e) None of these

Answers:

1) Answer: a)

I) x2 – 16x + 55 = 0

(x – 11) (x – 5) = 0

x = 11, 5

II) 2y2 – y – 36 = 0

2y2 + 8y – 9y – 36 = 0

2y (y + 4) – 9 (y + 4) = 0

(2y – 9) (y + 4) = 0

y = 4.5, -4

x > y        

2) Answer: d)

I) 3x2 + 4x – 64 = 0

3x2 – 12x + 16x – 64 = 0

3x(x – 4) + 16(x – 4) = 0

(3x + 16) (x – 4) = 0

x = -16/3, 4 = -5.33, 4

II) 2y2 – 21y + 52 = 0

2y2 – 8y – 13y + 52 = 0

2y (y – 4) – 13 (y – 4) = 0

(2y – 13) (y – 4) = 0

y = 13/2, 4 = 6.5, 4

x y

3) Answer: d)

I) x2 + 15x + 56 = 0

(x + 8) (x + 7) = 0

x = -8, -7

II) y2 + 13y + 42 = 0

(y + 6) (y + 7) = 0

y = -6, -7

x ≤ y

4) Answer: e)

I) x2 + x – 132 = 0

(x – 11) (x + 12) = 0

x = 11, -12

II) y2 – 13y – 48 = 0

(y + 3) (y – 16) = 0

y = -3, 16

Can’t be determined

5) Answer: a)

I) x2 – 12x + 36 = 0

(x – 6) (x – 6) = 0

x = 6, 6

II) 5y2 + 4y – 12 = 0

5y2 + 10y – 6y – 12 = 0

5y (y + 2) – 6(y + 2) = 0

(5y – 6) (y + 2) = 0

y = -2, 6/5

x > y

6) Answer: a)

The total number of male eating veg from hotel A

= > 1800*(5/9)*(48/100) = 480

The total number of female eating non-veg from hotel A

= > 1800*(4/9)*(55/100) = 440

Required difference = 480 – 440 = 40

7) Answer: d)

The total number of people eating Veg from hotel B and D together

= > 2500*(2/5) + 2000*(3/5)

= > 1000 + 1200 = 2200

The total number of people eating non-veg from hotel C and E together

= > 3600*(5/9) + 2800*(4/7)

= > 2000 + 1600 = 3600

Required ratio = 2200: 3600 = 11: 18

8) Answer: b)

The total number of people eating non-veg from hotel B, C and D together

= > [2500*(3/5) + 3600*(5/9) + 2000*(2/5)]

= > [1500 + 2000 + 800] = 4300

9) Answer: c)

Total number of people eating non-veg from hotel E

= > 2800*(4/7) = 1600

Total number of people eating Veg from hotel A

= > 1800*(5/9) = 1000

Required % = (1600/1000)*100 = 160 %

10) Answer: d)

The average number of people went for hotel A and C together

= > (1800 + 3600)/2 = 2700

The average number of people went for hotel B and D together

= > (2500 + 2000)/2 = 2250

Required difference = 2700 – 2250 = 450

 

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This post was last modified on September 1, 2020 11:49 pm