Dear Friends, SBI Clerk 2018 Notification has been released we hope you all have started your preparation. Here we have started New Series of Practice Materials specially for SBI Clerk 2018. Aspirants those who are preparing for the exams can use this “20-20” Quantitative Aptitude Questions.
[WpProQuiz 1195]
Click “Start Quiz” to attend these Questions and view Explanation
1). The ratio of the radii of two right circular cylinders (A and B) is 2 : 5. The ratio of the height of cylinders A to B is 3 : 1. What is the ratio of the volumes of cylinders A to B?
2). Raja gives 30% of his salary to his mother, 40% of the remaining salary he invests in an insurance scheme and PPF in the ratio of 4 : 3 and the remaining he keeps in his bank account. If the difference between the amount he gives to his mother and that he invests in insurance scheme is Rs.8400, how much is Raja’s salary?
3). C is 40% less efficient than A. A and B together can finish a piece of work in 10 days. B and C together can do it in 15 days. In how many days can A alone finish the same piece of work?
4). In a bag there are 7 red balls and 5 green balls. Three balls are picked at random. What is the probability that two balls are red and one ball is green in colour?
5). Shyama invested Rs. P for 2 years in scheme A, which offered 11% pa simple interest. She also invested Rs. 600+P in scheme B, which offered 20% compound interest (compound annually) for 2 years. If the amount received from scheme A was less than that received from scheme B by Rs. 1216 then what is the value of P?
Directions (Q. 6-10): What approximate value will come in place of question mark (?) in the given questions? (You are not expected to calculate the exact value.)
6). 619.002 – 134.99 ÷ 14.998—(9.01)^2=?
7). 439.97 ÷ 15.02 + 208.08 ÷ 8.01 — 16.01 =?
8) (2914.01 ÷ 31.1) ÷ (1.99 ÷ 3.01) × 510.01 ÷ 169.99 = ?
9). ? % of (140.06 x 7.99 — 679.92) = 330.01
10). 40% of 859 + 86.01 ÷ 7.99 = ?
Direction (Q. 11-15): Study the following table carefully and answer the questions given below: Number of shirts of different prices bought over the years.
Directions (Q. 16-20): What should come in place of question mark (?) in the following number series:
16). 17, 9, 15, 40, 143.5, ?
17). 3, 5, 13, 49, 241, ?
18). 508, 256, 130, 67, 35.5, ?
19). 7, 13, 31, 85, 247, ?
20). 64, 36, 22, 15, ? , 9.75
Answers:
1). Answer a
Let the radius of cylinder A be 2x and that of cylinder B be 5x.
Now, height of cylinder A = 3y and height of cylinder B = y
Now, volume of cylinder A = h
= (22/7) x (2x)^2 x 3y = (22/7) x 4x^2 x 3y
Volume of cylinder B = h
= (22/7) × (5x)^2 × y = (22/7) x (25x^2) x y
Required ratio = [ (22/7) x 4x^2 x 3y] / [(22/7) x 25x^2 x y] = 12/25
= 12:25
2). Answer a
Let Raja’s salary be Rs. x.
Raja gives 30% of his salary to his mother.
Raja gives [(x × 30)/100 = Rs. 3x/10] to his mother
Remaining salary of Raja = x – (3x /10) = Rs. 7x /10
Investments of Raja in insurance and PPF is 40% of the remaining salary.
Insurance + PPF = (7x x 40)/ (10×100) = 7x/25
Remaining salary of Raja = 7x/10 – 7x/25
= (35x —14x)/50 = 21x /50
Raja’s investment in insurance scheme
= (7x/25) × (4/7) = 4x/25
Now, according to the question,
3x/10 – 4x/7 = 8400
or, (15x-8x) / 50 =8400
or, 7x = 8400 x 50
x = (8400x 50)/7 =1200 x 50 = Rs. 60000
3). Answer b
Suppose total work = 30 units (LCM of 10 and 15)
(A + B)’s one day’s work = 30/10
= 3 units
And (B + C)’s one day’s work = 30/15 = 2 unit
According to the question, C : A = 60 : 100
or, C :A = 3 : 5
C/A = 3/5
Or, A = 5C/3
Again, A +B = 3 units ..(i)
B+C = 2 units …(ii)
Putting the value of A in equation (i), we get
[ 5C/3 + B = 3 unit ] – [B + C = 2 units]= 5C/3 – C=1 units
Or, 2C/3 = 1 units
C = 3/2 units
Then A = 5C/3 = 5×3/2 / 3 = 2.5 units
Now, total work is 30 units. Then A alone can do the work in
(30 /2.5 =) 12 days
4). Answer b
Total number of balls = 7 + 5 = 12
Now, three halls are picked randomly
Then, the number of sample space n(S)
=12C3 =(10 ×11 ×12) / (1×2×3) = 220
The number of events
n(E) =7C2 x5C1 = [(6×7)/2] x 5
= 21 x 5 = 105
P(E) = n(E)/n(S)=105/220 = 21/44
5). Answer d
Amount received from scheme A
= P+ [(Px2x11)/100] =( 100P+22P)/100 = 122P/100
Amount received from scheme B
= (P + 600) [1+ (20/100)]^2
= (P + 600) (6/5)^2
= (P + 600) (36/25)
= 36P/25 + (600×36)/25 = 36P/25 + 864
Now, according to the question,
36P/25 + 864 – 122P/100 = 1216
Or, 36P/25 – 122P/100 = 1216-864
Or, (144P-122P)/100 = 352
Or, 22P = 352×100
P = (352×100) / 22 = Rs. 1600
Directions (Q. 6-10):
6). Answer b
? = 619.002 – 134.99 ÷ 14.998 –(9.01)^2 = 620 – 135 ÷ 15 – (9)^2
= 620 – 90 = 530
7). Answer e
? = 439.97 ÷ 15.02 + 208.08 ÷ 8.01 –16.01 = 440 ÷ 15 + 208 ÷ 8 – 16
= 29 + 26 – 16 =29 + 10 = 39
8) Answer: b
(2914.01 ÷ 31.1) ÷ (1.99 ÷ 3.01) × 510.01 ÷ 169.99 = ?
94 * (3/2) * (510/170) = X
X= 423
9). Answer e
?% of (140.06 x 7.99 — 679.92) = 330.01
= [? X (140×8-680)] / 100 = 330
or, ? x (1120 — 680) = 330 x 100
or, ? x 440 = 33000
? = 33000 / 440 = 75
10). Answer e
?= 40% of 859 + 86.01 ÷ 7.99
= (40 x 860) / 100 + 86 ÷ 8
= 344 + 11 = 355
Direction (Q. 11-15):
Price range of 1000 – 1999 the number of shirts bought in 2011 and 2016
= 140 + 470 = 610
Price range of 2000 – 2999 the number of shirts bought in 2013 and 2015
= 100 + 135 = 235
Required percentage
= 610/235 × 100
= 259.57%
Number of shirts in price range 4000 – 5000 bought in 2011 and 2015 together
= 105 + 400 = 505
Number of shirts in price range 1000 – 1999 bought in 2012 and 2016 together
= 370 + 470 = 840
Required ratio = 505 : 840
= 101 : 168
Number of shirts bought in 2015
= (25 + 400 + 200 + 135 + 175 + 75 + 25) = 1035
Number of shirts bought in 2016
= (75 + 375 + 240 + 300 + 470 + 530 + 65) = 2055
So required difference = 2055 – 1035
= 1020
Number of shirts bought in:
2011 = 50+105+70+300+140+200+65=930
2012 = 106+1000+100+500+370+700+135=2911
2013 = 2+40+80+100+200+15+111=548
2014 = 30+105+115+216+225+400+188=1279
2015 = 25+400+200+135+175+75+25=1035
2016 = 75+375+240+300+470+530+65=2055
So maximum number of shirts was bought in 2012
Number of shirts in the price range:
More than 5000 = 50 + 106 + 2 + 30 + 25 + 75 = 288
4000 – 5000 = 105 + 1000 + 40 + 105 + 400 + 375 = 2025
3000 – 3999 = 70 + 100 + 80 + 115 + 200 + 240 = 805
2000 – 2999 = 300 + 500 + 100 + 216 + 135 + 300 =1551
1000 – 1999 = 140 + 370 + 200 + 225 + 175 + 470 = 1580
500 – 999 = 200 + 700 + 15 + 400 + 75 + 530 = 1920
Less than 500 = 65 + 135 + 111 + 188 + 25 + 65 = 589
So maximum number of shirts bought in price range of 4000 – 5000
Directions (Q. 16-20):
16). Answer c
The series is ×0.5 + 0.5, ×1.5 + 1.5, ×2.5 + 2.5, ×3.5 + 3.5, ×4.5 + 4.5
17). Answer d
The series is ×2-1, ×3-2, ×4-3, ×5-4, ×6-5
The whole series is /2 + 2
19). Answer c
The logic is, The difference*3
20). Answer c
The whole series is ×0.5 + 4
This post was last modified on September 17, 2020 10:47 am